ÌâÄ¿ÄÚÈÝ

£¨±¾Ìâ¹²12·Ö£©
ÏÂͼÊÇÄ£Ä⹤ҵÖÆÏõËáÔ­ÀíµÄʵÑé×°Öá£ÏÈÓþƾ«µÆ¶ÔÓ²Öʲ£Á§¹ÜÀïµÄÈýÑõ»¯¶þ¸õ¼ÓÈÈ£¬È»ºó°Ñ¿ÕÆø¹ÄÈëÊ¢ÓÐŨ°±Ë®µÄ׶ÐÎÆ¿£¬µ±ÈýÑõ»¯¶þ¸õ±£³ÖºìÈÈ״̬ʱ£¬ÒÆÈ¥¾Æ¾«µÆ¡£¸ù¾ÝÌâÒâ»Ø´ð£º

1£®Ó²Öʲ£Á§¹ÜÀï·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                                  ¡£
µ±ÈýÑõ»¯¶þ¸õºìÈÈʱ£¬ÒªÒÆÈ¥¾Æ¾«µÆ£¬Ô­ÒòÊÇ£º                            ¡£
2£®Ô²µ×ÉÕÆ¿ÀïµÄʵÑéÏÖÏóÊÇ                                     £¬¹ÄÈë¿ÕÆøµÄ×÷ÓÃÊÇ                                ¡£
3£®ÊµÑé¹ý³ÌÖУ¬Èç¹ûÂýÂýµØ¹ÄÈë¿ÕÆø£¬Ê¯ÈïÈÜÒºµÄÑÕÉ«             ¡£
4£®ÊµÑé½áÊøºó£¬ÔÚÔ²µ×ÉÕÆ¿ÄÚ±ÚÉÏÓÐʱ»á¿´µ½ÉÙÁ¿ÎÞÉ«¾§Ì壬д³öÉú³É¸Ã¾§ÌåµÄ»¯Ñ§·½³Ìʽ£º                                           ¡£
5£®ÐÂÖƵÄÈýÑõ»¯¶þ¸õ´ß»¯Ð§¹û½ÏºÃ¡£ÊµÑéÊÒÒ»°ãÓüÓÈÈ·Ö½â(NH4)2Cr2O7µÄ·½·¨ÖÆÈýÑõ»¯¶þ¸õ£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                                          ¡£
6£®¹¤ÒµÉÏÒª»ñµÃŨ¶È½Ï´óµÄÏõËᣬÍùÍùÔÚÏ¡ÏõËáÖмÓÈëÎüË®¼ÁÏõËáþ»òŨÁòËᣬȻºó   £¨ÌîÒ»ÖÖ²Ù×÷Ãû³Æ£©¡£ÊµÑéÊÒÀï±£´æŨÏõËáµÄ·½·¨ÊÇ                  ¡£

£¨¹²12·Ö£©
1¡¢4NH3 + 5O24NO + 6H2O£¨1·Ö£©
¸Ã·´Ó¦ÊÇ·ÅÈÈ·´Ó¦£¬Î¶ÈÌ«¸ß¿ÉÄÜʹ´ß»¯¼ÁµÄ»îÐÔ½µµÍ£¨»ò²£Á§¹ÜÆÆÁÑ£¬ºÏÀí¸ø·Ö£©£¨1·Ö£©
2¡¢Óкì×ØÉ«ÆøÌå²úÉú£¨1·Ö£©   ÌṩO2£¬ÇÒ´Ù½ø°±µÄ»Ó·¢£¨2·Ö£©
3¡¢±äºìÉ«£¨1·Ö£©
4¡¢NH3 + HNO3 ¡ú NH4NO3£¨1·Ö£©
5¡¢(NH4)2Cr2O7 Cr2O3 + N2¡ü + 4H2O£¨2·Ö£©
6¡¢ÕôÁó£¨1·Ö£©   Ê¢ÓÚ×ØÉ«Æ¿£¬ÃÜ·â·ÅÓÚÒõ°µ´¦£¨2·Ö£©

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

£¨±¾Ìâ¹²12·Ö£©ÒÒÃѼ«Ò×»Ó·¢¡¢Î¢ÈÜÓÚË®¡¢ÊÇÁ¼ºÃµÄÓлúÈܼÁ¡£ÒÒ´¼ÓëŨÁòËáµÄ»ìºÏÎïÔÚ²»Í¬Î¶ÈÏ·´Ó¦ÄÜÉú³ÉÒÒÏ©»òÒÒÃÑ¡£Ä³ÊµÑéС×éÓÃÏÂͼװÖÃÖÆÈ¡ÒÒÃѺÍÒÒÏ©¡£

1£®ÖÆÒÒÃÑ£ºÔÚÕôÁóÉÕÆ¿ÖÐÏȼÓÈë10 mLÒÒ´¼£¬ÂýÂý¼ÓÈë10 mLŨÁòËᣬÀäÈ´£¬¹Ì¶¨×°Ö᣼ÓÈȵ½140¡æʱ£¬´ò¿ª·ÖҺ©¶·»îÈû£¬¼ÌÐøµÎ¼Ó10 mLÒÒ´¼£¬²¢±£³Ö140¡æ£¬´ËʱÉÕÆ¿cÖÐÊÕ¼¯µ½ÎÞÉ«ÒºÌå¡£
£¨1£©¢ñºÍ¢òÊÇ·´Ó¦·¢Éú×°Öã¬Ó¦¸ÃÑ¡Ôñ______£¨Ñ¡´ð¡°¢ñ¡±»ò¡°¢ò¡±£©Óë×°ÖâóÏàÁ¬¡£
£¨2£©ÒÒ´¼Í¨¹ý·ÖҺ©¶·Ï¶ËÁ¬½ÓµÄ³¤µ¼¹Ü²åÈëµ½ÒºÃæϼÓÈ룬ĿµÄÓжþ£¬Ò»ÊÇʹ·´Ó¦Îï³ä·Ö»ìºÏ£¬¶þÊÇ_________________¡£
2£®¢óÖÐË®ÀäÄý¹ÜµÄ½øË®¿ÚÊÇ______£¨Ñ¡´ð¡°a¡±»ò¡°b¡±£©¡£±ùÑÎË®µÄ×÷ÓÃÊÇ___________¡£
3£®ÓÐͬѧÈÏΪÒÔÉÏ×°Öû¹²»¹»ÍêÉÆ£¬Ò»ÊÇäåË®¿ÉÄܵ¹Îü£¬¶þÊÇβÆøÃÖÂþÔÚ¿ÕÆøÖÐÓöÃ÷»ðΣÏÕ¡£¸ÃͬѧÉè¼ÆÁËÒÔϼ¸ÖÖ×°ÖÃÓëµ¼¹ÜdÁ¬½Ó£¬ÄãÈÏΪºÏÀíµÄÊÇ£¨Ñ¡Ìî±àºÅ£©_______¡£

4£®·´Ó¦Ò»¶Îʱ¼äºó£¬Éýε½170¡æ£¬¹Û²ìµ½·´Ó¦Îï±äΪºÚÉ«£¬äåË®ÍÊÉ«¡£Ð´³öʵÑé¹ý³ÌÖÐËùÓÐÉú³ÉÆøÌåµÄ·´Ó¦·½³Ìʽ____________________________¡£
5£®ÊµÑéÖÐÊÕ¼¯µ½µÄÒÒÃѲúÆ·ÖпÉÄܺ¬ÓжàÖÖÔÓÖÊ¡£Ä³Í¬Ñ§Éè¼ÆÁËÒÔÏÂÌá´¿·½°¸£º

£¨1£©·ÖÒº²½Öè³ýÈ¥²úÆ·ÖеÄËáÐÔÔÓÖÊ£¬ÔòX¿ÉÒÔÊÇ________________¡£
£¨2£©ÕôÁó²Ù×÷¿É³ýÈ¥µÄÔÓÖÊÊÇ____________¡£
6£®¹¤ÒµÒÒÃѳ£Òò½Ó´¥¿ÕÆøºÍ¹â¶ø±»Ñõ»¯£¬º¬ÓÐÉÙÁ¿¹ýÑõ»¯Î³ýÈ¥¹ýÑõ»¯ÎïµÄÊÔ¼Á¼°²Ù×÷·Ö±ðÊÇ£¨Ñ¡Ìî±àºÅ£©______________¡£
a£®CCl4¡¢ÝÍÈ¡                                  b£®Na2SO3ÈÜÒº¡¢·ÖÒº
c£®Na2SO4ÈÜÒº¡¢¹ýÂË                       d£®ËữµÄFeSO4ÈÜÒº¡¢·ÖÒº

£¨±¾Ìâ¹²12·Ö£©
ÏÂͼÊÇij»¯Ñ§ÐËȤС×é½øÐж¡ÍéÁѽâµÄʵÑéÁ÷³Ì¡££¨×¢£ºCuOÄܽ«ÌþÑõ»¯³ÉCO2ºÍH2O£¬GºóÃæ×°ÖÃÓë´ðÌâÎ޹أ¬Ê¡ÂÔÌú¼Ų̈µÈ¡££©°´ÏÂͼÁ¬ºÃ×°Öúó£¬Ðè½øÐеÄʵÑé²Ù×÷ÓУº¢Ù¸øD¡¢G×°ÖüÓÈÈ£»¢Ú¼ì²éÕûÌ××°ÖõÄÆøÃÜÐÔ£»¢ÛÅųö×°ÖÃÖеĿÕÆøµÈ¡­¡­

£¨1£©ÕâÈý²½²Ù×÷µÄÏȺó˳ÐòÒÀ´ÎÊÇ        £¨Ð´±àºÅ£©£»
£¨2£©¼òҪ˵Ã÷ÅÅ¿ÕÆøµÄ·½·¨ºÍÖ¤Ã÷¿ÕÆøÒÑÅž¡µÄ·½·¨               £»
£¨3£©B×°ÖÃËùÆðµÄ×÷ÓÃÊÇ                 £»
£¨4£©¼Ù¶¨¶¡Íé°´C4H10¡úC2H6£«C2H4ºÍC4H10¡úCH4£«C3H6µÄ·½Ê½ÍêÈ«Áѽ⣬µ±£¨E£«F£©×°ÖõÄ×ÜÖÊÁ¿±È·´Ó¦Ç°Ôö¼ÓÁË0.7g£¬G×°ÖõÄÖÊÁ¿¼õÉÙÁË1.76g£¬Ôò¶¡ÍéµÄÁѽâ²úÎïÖУ¬¼×ÍéÓëÒÒÍéµÄÎïÖʵÄÁ¿Ö®±ÈΪ           ¡££¨¼Ù¶¨Á÷¾­D¡¢G×°ÖÃÖеÄÆøÌåÄÜÍêÈ«·´Ó¦£©
Èô¶ÔE×°ÖÃÖеĻìºÏÎïÔÙ°´ÒÔÏÂÁ÷³ÌʵÑ飺

£¨5£©·ÖÀë²Ù×÷¢ñºÍ¢òµÄÃû³Æ·Ö±ðÊÇ£º¢ñ      ¢ò     £¬Na2SO3ÈÜÒºµÄ×÷ÓÃÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©                 ¡£ 
£¨6£©DµÄ½á¹¹¼òʽÊÇ               ¡£

£¨±¾Ìâ¹²12·Ö£©

ÏÂͼÊÇij»¯Ñ§ÐËȤС×é½øÐж¡ÍéÁѽâµÄʵÑéÁ÷³Ì¡££¨×¢£ºCuOÄܽ«ÌþÑõ»¯³ÉCO2ºÍH2O£¬GºóÃæ×°ÖÃÓë´ðÌâÎ޹أ¬Ê¡ÂÔÌú¼Ų̈µÈ¡££©°´ÏÂͼÁ¬ºÃ×°Öúó£¬Ðè½øÐеÄʵÑé²Ù×÷ÓУº¢Ù¸øD¡¢G×°ÖüÓÈÈ£»¢Ú¼ì²éÕûÌ××°ÖõÄÆøÃÜÐÔ£»¢ÛÅųö×°ÖÃÖеĿÕÆøµÈ¡­¡­

£¨1£©ÕâÈý²½²Ù×÷µÄÏȺó˳ÐòÒÀ´ÎÊÇ         £¨Ð´±àºÅ£©£»

£¨2£©¼òҪ˵Ã÷ÅÅ¿ÕÆøµÄ·½·¨ºÍÖ¤Ã÷¿ÕÆøÒÑÅž¡µÄ·½·¨                £»

£¨3£©B×°ÖÃËùÆðµÄ×÷ÓÃÊÇ                  £»

£¨4£©¼Ù¶¨¶¡Íé°´C4H10¡úC2H6£«C2H4ºÍC4H10¡úCH4£«C3H6µÄ·½Ê½ÍêÈ«Áѽ⣬µ±£¨E£«F£©×°ÖõÄ×ÜÖÊÁ¿±È·´Ó¦Ç°Ôö¼ÓÁË0.7g£¬G×°ÖõÄÖÊÁ¿¼õÉÙÁË1.76g£¬Ôò¶¡ÍéµÄÁѽâ²úÎïÖУ¬¼×ÍéÓëÒÒÍéµÄÎïÖʵÄÁ¿Ö®±ÈΪ            ¡££¨¼Ù¶¨Á÷¾­D¡¢G×°ÖÃÖеÄÆøÌåÄÜÍêÈ«·´Ó¦£©

Èô¶ÔE×°ÖÃÖеĻìºÏÎïÔÙ°´ÒÔÏÂÁ÷³ÌʵÑ飺

£¨5£©·ÖÀë²Ù×÷¢ñºÍ¢òµÄÃû³Æ·Ö±ðÊÇ£º¢ñ       ¢ò      £¬Na2SO3ÈÜÒºµÄ×÷ÓÃÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©                  ¡£ 

£¨6£©DµÄ½á¹¹¼òʽÊÇ                ¡£

 

£¨±¾Ìâ¹²12·Ö£©

ÏÂͼÊÇÄ£Ä⹤ҵÖÆÏõËáÔ­ÀíµÄʵÑé×°Öá£ÏÈÓþƾ«µÆ¶ÔÓ²Öʲ£Á§¹ÜÀïµÄÈýÑõ»¯¶þ¸õ¼ÓÈÈ£¬È»ºó°Ñ¿ÕÆø¹ÄÈëÊ¢ÓÐŨ°±Ë®µÄ׶ÐÎÆ¿£¬µ±ÈýÑõ»¯¶þ¸õ±£³ÖºìÈÈ״̬ʱ£¬ÒÆÈ¥¾Æ¾«µÆ¡£¸ù¾ÝÌâÒâ»Ø´ð£º

1£®Ó²Öʲ£Á§¹ÜÀï·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                                   ¡£

µ±ÈýÑõ»¯¶þ¸õºìÈÈʱ£¬ÒªÒÆÈ¥¾Æ¾«µÆ£¬Ô­ÒòÊÇ£º                             ¡£

2£®Ô²µ×ÉÕÆ¿ÀïµÄʵÑéÏÖÏóÊÇ                                      £¬¹ÄÈë¿ÕÆøµÄ×÷ÓÃÊÇ                                 ¡£

3£®ÊµÑé¹ý³ÌÖУ¬Èç¹ûÂýÂýµØ¹ÄÈë¿ÕÆø£¬Ê¯ÈïÈÜÒºµÄÑÕÉ«              ¡£

4£®ÊµÑé½áÊøºó£¬ÔÚÔ²µ×ÉÕÆ¿ÄÚ±ÚÉÏÓÐʱ»á¿´µ½ÉÙÁ¿ÎÞÉ«¾§Ì壬д³öÉú³É¸Ã¾§ÌåµÄ»¯Ñ§·½³Ìʽ£º                                            ¡£

5£®ÐÂÖƵÄÈýÑõ»¯¶þ¸õ´ß»¯Ð§¹û½ÏºÃ¡£ÊµÑéÊÒÒ»°ãÓüÓÈÈ·Ö½â(NH4)2Cr2O7µÄ·½·¨ÖÆÈýÑõ»¯¶þ¸õ£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                                           ¡£

6£®¹¤ÒµÉÏÒª»ñµÃŨ¶È½Ï´óµÄÏõËᣬÍùÍùÔÚÏ¡ÏõËáÖмÓÈëÎüË®¼ÁÏõËáþ»òŨÁòËᣬȻºó    £¨ÌîÒ»ÖÖ²Ù×÷Ãû³Æ£©¡£ÊµÑéÊÒÀï±£´æŨÏõËáµÄ·½·¨ÊÇ                   ¡£

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø