ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿Ä³Í¬Ñ§Éè¼ÆÈçÏÂʵÑé·½°¸£¬ÒÔ·ÖÀëKClºÍBaCl2Á½ÖÖ¹ÌÌå»ìºÏÎÊԻشðÏÂÁÐÎÊÌ⣺
¹©Ñ¡ÊÔ¼Á£ºNa2SO4ÈÜÒº¡¢K2CO3ÈÜÒº¡¢K2SO4ÈÜÒº¡¢ÑÎËá¡£
£¨1£©ÊÔ¼ÁaÊÇ_________£¬¼ÓÈëÊÔ¼ÁbËù·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ_________¡£
£¨2£©¸Ã·½°¸ÄÜ·ñ´ïµ½ÊµÑéÄ¿µÄ_____(Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±)¡£Èô²»ÄÜ£¬Ó¦ÈçºÎ¸Ä½ø?_____£¨ÈôÄÜ£¬´ËÎʲ»Óûشð)¡£
£¨3£©ÈôÒª²â¶¨Ô»ìºÏÎïÖÐBaCl2µÄÖÊÁ¿·ÖÊý£¬³ýÁËҪ׼ȷ³ÆÁ¿»ìºÏÎïµÄÖÊÁ¿ÍâÖÁÉÙ»¹Òª»ñµÃµÄÊý¾ÝÊÇ____µÄÖÊÁ¿¡£
£¨4£©ÓÃËù£¨3£©ËùÖƱ¸µÄKCl¹ÌÌåÅäÖÆ0.1mol/LKClÈÜÒº450mL£¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨i£©ÅäÖƹý³ÌÖÐÐèÒªÓõ½µÄ²£Á§ÒÇÆ÷ÓÐÉÕ±¡¢²£Á§°ô¡¢Á¿Í²¡¢½ºÍ·µÎ¹Ü¡¢____________¡£
£¨ii£©ÐèÒªÓÃÍÐÅÌÌìƽ³ÆÁ¿______________gKCl¹ÌÌå¡£
¡¾´ð°¸¡¿K2CO3ÈÜÒº BaCO3+2H+£½Ba2++CO2¡ü+H2O ²»ÄÜ Ó¦ÔÚ²Ù×÷¢ÚµÄÂËÒºÖмÓÈë¹ýÁ¿ÑÎËáºóÔÙÕô·¢½á¾§ ³ÁµíA1(»ò¹ÌÌåB) 500mLÈÝÁ¿Æ¿ 3.7
¡¾½âÎö¡¿
·ÖÀëKClºÍBaCl2Á½ÖÖ¹ÌÌå»ìºÏÎ¿ÉÏÈÈÜÓÚË®£¬È»ºó¼ÓÈë¹ýÁ¿K2CO3ʹBaCl2ת»¯Îª³Áµí£¬¹ýÂ˺ó³Áµí¼ÓÈëÑÎËá¿ÉÉú³ÉBaCl2ÈÜÒº£¬¾Õô·¢¡¢½á¾§¡¢¸ÉÔïºó¿ÉµÃ¹ÌÌåBaCl2£¬²Ù×÷¢ÚËùµÃÂËҺΪKClºÍK2CO3µÄ»ìºÏÎÕô·¢½á¾§µÃµ½¹ÌÌåCΪKClºÍK2CO3£¬³ÁµíAΪBaCO3£¬Ï´µÓºó£¬¼ÓÑÎËᣬÕô·¢µÃµ½¹ÌÌåBΪBaCl2£¬ÒÔ´ËÀ´½â´ð¡£
£¨1£©¼ÓÈëÊÔ¼Áa£¬ÓëBaCl2·´Ó¦Éú³ÉBaCO3³Áµí£¬Òò´ËÊÔ¼ÁaÊÇK2CO3ÈÜÒº£»Ì¼Ëá±µ¾¹ýÏ´µÓ¸ÉÔïºó¼ÓÈëÊÔ¼Ábת»¯ÎªÂÈ»¯±µÈÜÒº£¬ÔòÊÔ¼ÁbÊÇÑÎËᣬ·´Ó¦µÄÀë×Ó·½³ÌʽΪBaCO3+2H+£½Ba2++CO2¡ü+H2O¡£
£¨2£©¾²Ù×÷¢ÚµÃµ½µÄÂËÒºÖк¬ÓйýÁ¿K2CO3£¬Ö±½ÓÕô·¢µÃµ½µÄÂÈ»¯¼ØÖлìÓÐ̼Ëá¼Ø£¬Ó¦ÏȼÓÈëÑÎËáËữ£¬È»ºóÔÙÕô·¢½á¾§£»
£¨3£©²â¶¨ÂÈ»¯±µµÄÖÊÁ¿·ÖÊý£¬¿É¼ÆËã̼Ëá±µ»ò·ÖÀëºóÂÈ»¯±µµÄÖÊÁ¿£¬¼´³ýÁËҪ׼ȷ³ÆÁ¿»ìºÏÎïµÄÖÊÁ¿ÍâÖÁÉÙ»¹Òª»ñµÃµÄÊý¾ÝÊdzÁµíA1»ò¹ÌÌåBµÄÖÊÁ¿£»
£¨4£©ÓÃËù£¨3£©ËùÖƱ¸µÄKCl¹ÌÌåÅäÖÆ0.1mol/LKClÈÜÒº450mL£¬ÓÉÓÚûÓÐ450mLÈÝÁ¿Æ¿£¬ÔòÐèÒª500mLÈÝÁ¿Æ¿£¬ÔòÅäÖƹý³ÌÖÐÐèÒªÓõ½µÄ²£Á§ÒÇÆ÷ÓÐÉÕ±¡¢²£Á§°ô¡¢Á¿Í²¡¢½ºÍ·µÎ¹ÜºÍ500mLÈÝÁ¿Æ¿£»Òò´ËÐèÒªKCl¹ÌÌåµÄÖÊÁ¿ÊÇ0.5L¡Á0.1mol/L¡Á74.5g/mol£½3.725g£¬ÓÉÓÚÍÐÅÌÌìƽֻÄܶÁÊýµ½0.1g£¬ÔòÐèÒªÓÃÍÐÅÌÌìƽ³ÆÁ¿µÄÖÊÁ¿ÊÇ3.7g¡£
![](http://thumb2018.1010pic.com/images/loading.gif)