ÌâÄ¿ÄÚÈÝ
ÁòµÄ»¯ºÏÎïÔÚÉú²úºÍ¿ÆÑÐÖз¢»Ó×ÅÖØÒª×÷Óá£
£¨1£©SO2Cl2³£ÓÃÓÚÖÆÔìÒ½Ò©Æ·¡¢È¾ÁÏ¡¢±íÃæ»îÐÔ¼ÁµÈ¡£ÒÑÖª£ºSO2Cl2(g)SO2(g)£«Cl2(g) ¡÷H£½£«97.3 kJ¡¤mol£1¡£Ä³Î¶ÈʱÏòÌå»ýΪ1 LµÄºãÈÝÃܱÕÈÝÆ÷ÖгäÈë0. 20mol SO2Cl2£¬´ïµ½Æ½ºâʱ£¬ÈÝÆ÷Öк¬0.18mol SO2£¬Ôò´Ë¹ý³Ì·´Ó¦ÎüÊÕµÄÈÈÁ¿Îª_____kJ£¬¸ÃζÈʱ·´Ó¦µÄƽºâ³£ÊýΪ_____¡£½«ÉÏÊöËùµÃ»ìºÏÆøÌåÈÜÓÚ×ãÁ¿BaCl2ÈÜÒºÖУ¬×îÖÕÉú³É³ÁµíµÄÖÊÁ¿Îª_______¡£
£¨2£©¹¤ÒµÉÏÖƱ¸ÁòËáµÄ¹ý³ÌÖдæÔÚ·´Ó¦£º2SO2(g)£«O2(g)2SO3(g) ¡÷H£½£198kJ¡¤mol£1400¡æ£¬1.01¡Á105Pa£¬ÏòÈÝ»ýΪ2LµÄºãÈÝÃܱÕÈÝÆ÷ÖгäÈëÒ»¶¨Á¿ SO2ºÍO2£¬n(SO3)ºÍn(O2)Ëæʱ¼äµÄ±ä»¯ÇúÏßÈçͼËùʾ¡£
¢Ù0¡«20min·´Ó¦µÄƽ¾ùËÙÂʦÔ(O2)£½___________¡£
¢ÚÏÂÁÐÐðÊöÕýÈ·µÄÊÇ ¡£
a£®Aµã¦ÔÕý(SO2)£¾¦ÔÄæ(SO2)
b£®Bµã´¦ÓÚƽºâ״̬
c£®CµãºÍDµãn(SO2)Ïàͬ
d£®ÆäËüÌõ¼þ²»±ä£¬500¡æʱ·´Ó¦´ïƽºâ£¬n(SO3)±ÈͼÖÐDµãµÄÖµ´ó
£¨3£©¹¤ÒµÉÏÓÃNa2SO3ÈÜÒºÎüÊÕÑÌÆøÖеÄSO2¡£½«ÑÌÆøͨÈë1.0 mol¡¤L£1µÄNa2SO3ÈÜÒº£¬µ±ÈÜÒºpHԼΪ6ʱ£¬Na2SO3ÈÜÒºÎüÊÕSO2µÄÄÜÁ¦ÏÔÖøϽµ£¬Ó¦¸ü»»ÎüÊÕ¼Á¡£´ËʱÈÜÒºÖÐc (SO32£)µÄŨ¶ÈÊÇ0.2 mol¡¤L£1£¬ÔòÈÜÒºÖÐc(HSO3£)ÊÇ_________mol¡¤L£1¡£
£¨17·Ö£©£¨1£©17.5£¨3·Ö£© 1.62£¨3·Ö£© 46.6g£¨3·Ö£©
£¨2£©0.02mol(L¡¤min) £¨3·Ö£© ac£¨2·Ö£© £¨3£©1.6mol/L£¨3·Ö£©
½âÎöÊÔÌâ·ÖÎö£º£¨1£©´ïµ½Æ½ºâʱ£¬ÈÝÆ÷Öк¬0.18mol SO2£¬Ôò¸ù¾ÝÈÈ»¯Ñ§·½³Ìʽ¿ÉÖª£¬´Ë¹ý³Ì·´Ó¦ÎüÊÕµÄÈÈÁ¿Îª97.3 kJ¡¤mol£1¡Á0.18mol£½17.5kJ¡£¸ù¾Ý·½³Ìʽ¿ÉÖª
SO2Cl2(g)SO2(g)£«Cl2(g)
ÆðʼŨ¶È£¨mol/L£© 0.20 0 0
ת»¯Å¨¶È£¨mol/L£© 0.18 0.18 0.18
ƽºâŨ¶È£¨mol/L£© 0.02 0.18 0.18
ËùÒÔ¸ÃζÈÏ·´Ó¦µÄƽºâ³£ÊýK£½£½1.62¡£
ËùµÃ»ìºÏÆøÌåÈÜÓÚ×ãÁ¿BaCl2ÈÜÒºÖУ¬·¢Éú·´Ó¦SO2£«Cl2£«2H2O£½H2SO4£«2HCl£¬ËùÒÔ´Ùʹƽºâ³ÖÐøÏòÕý·´Ó¦·½Ïò½øÐУ¬Òò´Ë×îÖÕÉú³É³ÁµíµÄÎïÖʵÄÁ¿ÊÇ0.20mol£¬ÔòÁòËá±µµÄÖÊÁ¿Îª0.20mol¡Á232g/mol£½46.6g¡£
£¨2£©¢Ù¸ù¾ÝͼÏñ¿ÉÖª20minʱÈýÑõ»¯ÁòµÄÎïÖʵÄÁ¿ÊÇ1.6mol£¬ÔòÏûºÄÑõÆøµÄÎïÖʵÄÁ¿ÊÇ0.8mol£¬Å¨¶ÈÊÇ0.4mol/L£¬ËùÒÔ0¡«20min·´Ó¦µÄƽ¾ùËÙÂʦÔ(O2)£½0.4mol/L¡Â20min£½0.02mol(L¡¤min)£»
¢Úa£®¸ù¾ÝͼÏñ¿ÉÖªAµã·´Ó¦Ã»Óдﵽƽºâ״̬£¬Æ½ºâÏòÕý·´Ó¦·½Ïò½øÐУ¬Ôò¦ÔÕý(SO2)£¾¦ÔÄæ(SO2)£¬aÕýÈ·£»b£®BµãÎïÖʵÄŨ¶ÈÈÔÈ»ÊDZ仯µÄ£¬·´Ó¦Ã»Óд¦ÓÚƽºâ״̬£¬b²»ÕýÈ·£»c£®CµãºÍDµã¾ùÊÇÏàͬÌõ¼þϵÄƽºâ״̬£¬Òò´Ën(SO2)Ïàͬ£¬cÕýÈ·£»d£®Õý·½Ó¦ÊÇ·ÅÈÈ·´Ó¦£¬ÆäËüÌõ¼þ²»±ä£¬Éý¸ßζÈƽºâÏòÄæ·´Ó¦·½ÏòÒƶ¯£¬ËùÒÔ500¡æʱ·´Ó¦´ïƽºâ£¬n(SO3)±ÈͼÖÐDµãµÄֵС£¬d²»ÕýÈ·£¬´ð°¸Ñ¡ac¡£
£¨3£©ÈÜÒºÖÐc (SO32£)µÄŨ¶ÈÊÇ0.2 mol¡¤L£1£¬ÔòÏûºÄc (SO32£)µÄŨ¶È£½1.0mol/L£0.2mol/L£½0.8mol/L£¬Òò´Ë¸ù¾Ý·½³ÌʽSO32££«SO2£«H2O£½2HSO3£¿ÉÖªÈÜÒºc(HSO3£)£½0.8mol/L¡Á2£½1.6mol/L¡£
¿¼µã£º¿¼²é·´Ó¦ÈÈ¡¢·´Ó¦ËÙÂÊ¡¢Æ½ºâ³£ÊýµÄÓйؼÆË㣻Íâ½çÌõ¼þ¶Ôƽºâ״̬µÄÓ°ÏìÒÔ¼°ÈÜÒºÖÐÀë×ÓŨ¶ÈºÍ³ÁµíÉú³ÉµÄÓйؼÆËã
¼×´¼ÊÇÒ»ÖÖ¿ÉÔÙÉúÄÜÔ´£¬¾ßÓй㷺µÄ¿ª·¢ºÍÓ¦ÓÃÇ°¾°¡£
(1)¹¤ÒµÉÏÒ»°ã²ÉÓÃÏÂÁÐÁ½ÖÖ·´Ó¦ºÏ³É¼×´¼£º
·´Ó¦¢ñ£ºCO(g)£«2H2(g)CH3OH(g)¡¡¦¤H1
·´Ó¦¢ò£ºCO2(g)£«3H2(g)CH3OH(g)£«H2O(g)¡¡¦¤H2
¢ÙÉÏÊö·´Ó¦·ûºÏ¡°Ô×Ó¾¼Ã¡±ÔÔòµÄÊÇ________(Ìî¡°¢ñ¡±»ò¡°¢ò¡±)¡£
¢ÚϱíËùÁÐÊý¾ÝÊÇ·´Ó¦¢ñÔÚ²»Í¬Î¶ÈϵĻ¯Ñ§Æ½ºâ³£Êý(K)¡£
ÎÂ¶È | 250 ¡æ | 300 ¡æ | 350 ¡æ |
K | 2.041 | 0.270 | 0.012 |
ÓɱíÖÐÊý¾ÝÅжϣ¬¦¤H1______0(Ìî¡°£¾¡±¡¢¡°£½¡±»ò¡°£¼¡±)¡£
¢ÛijζÈÏ£¬½«2 mol COºÍ6 mol H2³äÈë2 LµÄÃܱÕÈÝÆ÷ÖУ¬³ä·Ö·´Ó¦£¬´ïµ½Æ½ºâºó£¬²âµÃc(CO)£½0.2 mol¡¤L£1£¬ÔòCOµÄת»¯ÂÊΪ________£¬´ËʱµÄζÈΪ________(´ÓÉϱíÖÐÑ¡Ôñ)¡£
(2)ÒÑÖªÔÚ³£Î³£Ñ¹Ï£º
¢Ù2CH3OH(l)£«3O2(g)=2CO2(g)£«4H2O(g) ¦¤H1£½£1 275.6 kJ¡¤mol£1
¢Ú2CO(g)£«O2(g)=2CO2(g) ¦¤H2£½£566.0 kJ¡¤mol£1
¢ÛH2O(g)=H2O(l)¡¡¦¤H3£½£44.0 kJ¡¤mol£1
д³ö¼×´¼²»ÍêȫȼÉÕÉú³ÉÒ»Ñõ»¯Ì¼ºÍҺ̬ˮµÄÈÈ»¯Ñ§·½³Ìʽ£º
__________________________________________________________¡£
¡°µÍ̼ѻ·¡±ÒÑÒýÆð¸÷¹ú¼ÒµÄ¸ß¶ÈÖØÊÓ£¬¶øÈçºÎ½µµÍ´óÆøÖÐCO2µÄº¬Á¿ºÍÓÐЧµØ¿ª·¢ÀûÓÃCO2Õý³ÉΪ»¯Ñ§¼ÒÑо¿µÄÖ÷Òª¿ÎÌâ¡£
£¨1£©½«²»Í¬Á¿µÄCO(g)ºÍH2O(g)·Ö±ðͨÈëµ½Ìå»ýΪ2LµÄºãÈÝÃܱÕÈÝÆ÷ÖУ¬½øÐз´Ó¦
CO(g)£«H2O(g)CO2(g)£«H2(g)£¬µÃµ½ÈçÏÂÈý×éÊý¾Ý£º
ʵÑé×é | ζȡæ | ÆðʼÁ¿/mol | ƽºâÁ¿/mol | ´ïµ½Æ½ºâËùÐè ʱ¼ä/min | ||
CO | H2O | H2 | CO | |||
1 | 650 | 4 | 2 | 1£®6 | 2£®4 | 6 |
2 | 900 | 2 | 1 | 0£®4 | 1£®6 | 3 |
3 | 900 | a | b | c | d | t |
¢ÙʵÑé2Ìõ¼þÏÂƽºâ³£ÊýK= ¡£
¢ÚʵÑé3ÖУ¬Èôƽºâʱ£¬COµÄת»¯ÂÊ´óÓÚË®ÕôÆø£¬Ôòa/b µÄÖµ_______(Ìî¾ßÌåÖµ»òÈ¡Öµ·¶Î§)¡£
¢ÛʵÑé4£¬Èô900¡æʱ£¬ÔÚ´ËÈÝÆ÷ÖмÓÈëCO¡¢H2O¡¢CO2¡¢H2¾ùΪ1mol£¬Ôò´ËʱVÕý VÄ棨Ìî¡°<¡± £¬¡°>¡± £¬¡°=¡±£©¡£
£¨2£©ÒÑÖªÔÚ³£Î³£Ñ¹Ï£º
¢Ù2CH3OH(l) £« 3O2(g) £½ 2CO2(g) £« 4H2O(g) ¦¤H£½£1275.6 kJ£¯mol
¢Ú2CO (g)+ O2(g) £½ 2CO2(g) ¦¤H£½£566.0 kJ£¯mol
¢ÛH2O(g) £½ H2O(l) ¦¤H£½£44.0 kJ£¯mol
д³ö¼×´¼²»ÍêȫȼÉÕÉú³ÉÒ»Ñõ»¯Ì¼ºÍҺ̬ˮµÄÈÈ»¯Ñ§·½³Ìʽ£º____________
£¨3£©ÒÑÖª²ÝËáÊÇÒ»ÖÖ¶þÔªÈõËᣬ²ÝËáÇâÄÆ£¨NaHC2O4£©ÈÜÒºÏÔËáÐÔ¡£³£ÎÂÏ£¬Ïò10 mL 0.01 mol¡¤L-1 H2C2O4ÈÜÒºÖеμÓ10mL 0.01mol¡¤L-1 NaOHÈÜҺʱ£¬±È½ÏÈÜÒºÖи÷ÖÖÀë×ÓŨ¶ÈµÄ´óС¹Øϵ £»
£¨4£©CO2ÔÚ×ÔÈ»½çÑ»·Ê±¿ÉÓëCaCO3·´Ó¦£¬CaCO3ÊÇÒ»ÖÖÄÑÈÜÎïÖÊ£¬ÆäKsp=2.8¡Á10-9¡£CaCl2ÈÜÒºÓëNa2CO3ÈÜÒº»ìºÏ¿ÉÐγÉCaCO3³Áµí£¬ÏÖ½«µÈÌå»ýµÄCaCl2ÈÜÒºÓëNa2CO3ÈÜÒº»ìºÏ£¬ÈôNa2CO3ÈÜÒºµÄŨ¶ÈΪ2¡Á10-4mol/L £¬ÔòÉú³É³ÁµíËùÐèCaCl2ÈÜÒºµÄ×îСŨ¶ÈΪ _______________mol/L¡£
£¨5£©ÒÔ¶þ¼×ÃÑ£¨CH3OCH3£©¡¢¿ÕÆø¡¢H2SO4ΪÔÁÏ£¬²¬Îªµç¼«¿É¹¹³ÉȼÁϵç³Ø£¬Æ乤×÷ÔÀíÓë¼×ÍéȼÁϵç³ØµÄÔÀíÏàËÆ¡£Çëд³ö¸Ãµç³Ø¸º¼«Éϵĵ缫·´Ó¦Ê½£º ¡£