ÌâÄ¿ÄÚÈÝ

ͼ8-3ÊÇijÆøÌåX²úÉú²¢Ñо¿ÆäÐÔÖʵÄ×°Öá£

ͼ8-3
AÖÐÊ¢ÓÐ΢Èܵİ×É«¹ÌÌ壬BÖÐÊ¢ÓÐÎÞÉ«»Ó·¢ÐÔÒºÌ壬CºÍEÖÐÊ¢ÓиÉÔï¼Á¡£AºÍBÖÐÎïÖÊÏàÓöʱÓÐÎÞÉ«ÆøÌåXÉú³É£¬Ëü¾­Í¼ÖÐһϵÁÐ×°ÖÃÔÚÄ©¶ËµÃµ½N2£¬ÇÒE¹ÜµÄÖÊÁ¿Ôö¼Ó¡£
£¨1£©Ð´³öÊ¢·ÅÊÔ¼ÁµÄÃû³Æ£º
A.____________£¬B.____________£¬C.____________£¬E.____________¡£
£¨2£©AºÍBÖÐÎïÖÊÏàÓöÉú³ÉXµÄÖ÷ÒªÔ­ÒòÊÇ£º________________________¡£
£¨3£©DÖз´Ó¦µÄ»¯Ñ§·½³Ìʽ_________________________________________¡£
£¨4£©FÖз´Ó¦µÄ»¯Ñ§·½³Ìʽ_________________________________________¡£
£¨5£©´ÓDÖз´Ó¦ËµÃ÷ÆøÌåX¾ßÓÐ____________£¨Ìî¡°ËáÐÔ¡±¡°¼îÐÔ¡±¡°Ñõ»¯ÐÔ¡±»ò¡°»¹Ô­ÐÔ¡±£©¡£
£¨1£©Éúʯ»Ò Å¨°±Ë® ¼îʯ»Ò ¼îʯ»Ò
(2)CaOÓëË®»¯ºÏÉú³ÉÊìʯ»Ò£¬ÏûºÄË®²¢·Å³ö´óÁ¿ÈÈ£¬Ê¹Å¨°±Ë®ÖеÄNH3Òݳö
£¨3£©3CuO+2NH3N2+3Cu+3H2O
(4)2NH3+H2SO4====(NH4)2SO4
(5)»¹Ô­ÐÔ
´ÓÄ©¶ËµÄN2ÄæÍÆ¿ÉÖªXÖк¬NÔªËØ¡£´ÓEÔöÖØ¿ÉÍƵ¼DÖз´Ó¦ÓÐË®Éú³É¡£N2ºÍH2O¾ùÓÉDÖз´Ó¦¶øÀ´£¬³õ²½ÅжÏDÖÐCuOÓ뺬N¡¢HÔªËصÄÎïÖÊX×÷Ó㬲ÂÏëXΪNH3¡£A¡¢BÏàÓöµÃNH3£¬BӦʢÓÐŨ°±Ë®£¬AÖÐӦʢ¹ÌÌåNaOH»òCaO£¬ÒòÌâ¸øÎïÖÊ΢ÈÜ£¬¿ÉÖªËüÊÇCaO¡£×îºóÈ«Ãæ¼ì²éÑéÖ¤¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø