ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÔÚ¢Ù¡¢¢Ú¡¢¢ÛÈÝ»ý²»µÈµÄºãÈÝÃܱÕÈÝÆ÷ÖУ¬¾ù³äÈë0.lmolCOºÍ0.2molH2£¬ÔÚ´ß»¯¼ÁµÄ×÷ÓÃÏ·¢Éú·´Ó¦£ºCO(g)+2H2(g) CH3OH(g)¡£²âµÃÈý¸öÈÝÆ÷ÖÐƽºâ»ìºÏÎïÖÐCH3OHµÄÌå»ý·ÖÊýËæζȵı仯ÈçͼËùʾ£º
ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ
A. ¸Ã·´Ó¦µÄÕý·´Ó¦Îª·ÅÈÈ·´Ó¦
B. Èý¸öÈÝÆ÷ÈÝ»ý£º¢Ù>¢Ú>¢Û
C. ÔÚPµã£¬COת»¯ÂÊΪ75%
D. ÔÚPµã£¬ÏòÈÝÆ÷¢ÚÖÐÔÙ³äÈëCO¡¢H2 ¼° CH3OH ¸÷ 0.025mol£¬´Ëʱ v(CO)Õý<v (CO)Äæ
¡¾´ð°¸¡¿AC
¡¾½âÎö¡¿A¡¢ÈÎÑ¡Ò»ÖÖÇé¿ö£¬Éý¸ßζȣ¬¼×´¼µÄÌå»ý·ÖÊý¼õС£¬Æ½ºâÄæÏòÒƶ¯£¬ËµÃ÷Ä淴ӦΪÎüÈÈ·´Ó¦£¬Õý·´Ó¦Îª·ÅÈÈ·´Ó¦£¬AÕýÈ·¡£B¡¢ÏàͬζÈÏ Ôö´óѹǿ£¬Æ½ºâÕýÏòÒƶ¯£¬¼×´¼µÄÌå»ý·ÖÊýÔ½´ó£¬¢Ù>¢Ú>¢Û£¬ËµÃ÷¢ÙÖеÄѹǿ×î´ó£¬ÔòÌå»ý×îС£¬¹ÊÌå»ý´óСΪ¢Ù£¼¢Ú£¼¢Û£¬B´íÎó¡£C¡¢Pµã¼×´¼µÄÌå»ý·ÖÊýΪ50%£¬ÉèCOת»¯µÄÎïÖʵÄÁ¿Îªx,ÔòÇâÆøת»¯ÁË2x,¼×´¼Éú³ÉÁËx,50%=x/(0.1-x+0.2-2x+x)µÃµ½x =0.075£¬ËùÒÔCOµÄת»¯ÂÊΪ0.075/0.1*100%=75% £¬CÕýÈ·¡£D¡¢Éè¢ÚÈÝÆ÷Ìå»ýΪV£¬PµãƽºâµÄʱºò£¬CH3OHµÄÎïÖʵÄÁ¿Îª0.075mol£¬Å¨¶ÈΪ£¨0.075/V£©mol¡¤L-1£¬COµÄÎïÖʵÄÁ¿Îª0.025mol£¬Å¨¶ÈΪ£¨0.025/V£©mol¡¤L-1£¬£¬H2µÄÎïÖʵÄÁ¿Îª0.05mol£¬Å¨¶ÈΪ£¨0.05/V£©mol¡¤L-1£¬K=£¨0.075/V£©/£¨0.025/V£©*£¨0.05/V£©2=3*104*V2/25£¬ÔÙ³äÈëCO¡¢H2 ¼° CH3OH ¸÷ 0.025mol£¬Í¬ÑùµÄ·½·¨¼ÆËãµÃµ½Å¨¶ÈÉÌQ=2*104*V2/7.52£¬Q£¼K£¬ËùÒÔv(CO)Õý£¾v (CO)Ä棬D´íÎó¡£ÕýÈ·´ð°¸ÎªAC
¡¾ÌâÄ¿¡¿Ï±íÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö£¬Çë»Ø´ðÓйØÎÊÌ⣺
Ö÷×å | ¢ñA | ¢òA | ¢óA | ¢ôA | ¢õA | ¢öA | ¢÷A | 0 |
2 | ¢Ù | ¢Ú | ¢Û | |||||
3 | ¢Ü | ¢Ý | ¢Þ | ¢ß | ¢à | |||
4 | ¢á | ¢â |
£¨1£©±íÖл¯Ñ§ÐÔÖÊ×î²»»îÆõÄÔªËØ£¬ÆäÔ×ӽṹʾÒâͼΪ £®
£¨2£©±íÖÐÄÜÐγÉÁ½ÐÔÇâÑõ»¯ÎïµÄÔªËØÊÇ£¨ÌîÔªËØÃû³Æ£©£¬Ð´³ö¸ÃÔªËصĵ¥ÖÊÓë¢á×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯Îï·´Ó¦µÄ»¯Ñ§·½³Ìʽ £®
£¨3£©¢Ù¡¢¢Ü¡¢¢Ý¡¢¢Þ¡¢¢ß¡¢¢áÁùÖÖÔªËصÄ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïÖУ¬°´¼îÐÔ¼õÈõËáÐÔÔöÇ¿µÄ˳ÐòÅÅÁÐΪ£¨Óû¯Ñ§Ê½±íʾ£©£®
£¨4£©¢ÛÔªËØÓë¢âÔªËØÁ½Õߺ˵çºÉÊýÖ®²îÊÇ £®