ÌâÄ¿ÄÚÈÝ

£¨12·Ö£©A¡¢B¡¢C¡¢D¡¢E·Ö±ð´ú±íÎåÖÖ¶ÌÖÜÆÚÔªËØ£¬ÇÒÔ­×ÓÐòÊýÒÀ´ÎÔö´ó£¬ÒÑÖª£ºBµÄ×îÍâ²ãµç×ÓÅŲ¼ÊÇnsnnpn£«1£»CµÄpÄܼ¶ÉÏδ³É¶ÔµÄµç×Ó±ÈBÉÙÒ»¸ö£»DµÄ¶þ¼ÛÑôÀë×ÓÓëCµÄÒõÀë×Ó¾ßÓÐÏàͬµÄµç×Ó²ã½á¹¹£»EÓëDͬÖÜÆÚÇÒEÔÚ¸ÃÖÜÆÚÖÐÔ­×Ӱ뾶×îС£»BÓëAµÄµ¥ÖÊÄÜÉú³É¾ßÓд̼¤ÐÔÆøζµÄÆøÌ壬¸ÃÆøÌ弫Ò×ÈÜÓÚË®¡£
(1)BÔ­×ÓºËÍâµç×ÓÅŲ¼Ê½Îª____________________________¡£
(2)AÓëE»¯ºÏʱԭ×Ó¼äÒÔ_____________¼üÏà½áºÏ£¬DÓëC»¯ºÏʱԭ×Ó¼äÒÔ_____________¼üÏà½áºÏ¡£
(3)д³öA¡¢CµÄµ¥ÖÊÖ±½Ó»¯ºÏÐγɵĻ¯ºÏÎïÓëEµ¥ÖÊ·´Ó¦µÄÀë×Ó·½³Ìʽ£º________________________________¡£
(4)AÓëBÐγɻ¯ºÏÎïʱ£¬ÖÐÐÄÔ­×Ó²ÉÈ¡________ÔÓ»¯³É¼ü£¬ÆäÁ¢Ìå½á¹¹Îª________£¬ÊôÓÚ________(Ìî¡°¼«ÐÔ¡±»ò¡°·Ç¼«ÐÔ¡±)·Ö×Ó¡£
(5) ½«°×É«µÄÎÞË®CuSO4ÈܽâÓÚA2CÖУ¬ÈÜÒº³ÊÀ¶É«£¬ÊÇÒòΪÉú³ÉÁËÒ»ÖÖ³ÊÀ¶É«µÄÅäºÏÀë×Ó¡£Çëд³öÉú³É´ËÅäºÏÀë×ÓµÄÀë×Ó·½³Ìʽ£º                           ¡£
£¨6£©ÎåÖÖÔªËØÖе縺ÐÔ×î´óµÄÊÇ           £¨ÌîÔªËØÃû³Æ£©¡£
£¨¹²12·Ö£¬³ý·½³Ìʽ2·Ö£¬ÆäÓàÿ¿Õ1·Ö£©
(1)1s22s22p3¡¡ 2·Ö         (2)¹²¼Û¡¡Àë×Ó    2·Ö
(3)Cl2£«H2O===H£«£«Cl£­£«HClO¡¡2·Ö   (4)sp3¡¡Èý½Ç׶ÐΡ¡¼«ÐÔ   3·Ö
£¨5£©Cu2++4H2O=[Cu(H2O)4]2+   2·Ö     £¨6£©Ñõ     1·Ö
¸ù¾ÝÔªËصĽṹ¼°ÓйØÐÔÖÊ¿ÉÖª£¬A¡¢B¡¢C¡¢D¡¢E·Ö±ðÊÇH¡¢N¡¢O¡¢Mg¡¢Cl¡£
£¨1£©¸ù¾Ý¹¹ÔìÔ­Àí¿ÉÖª£¬µªÔ­×ӵĺËÍâµç×ÓÅŲ¼Ê½Îª1s22s22p3¡£
£¨2£©HºÍClÔ­×Ó¶¼ÊǷǽðÊô£¬ËùÒÔ¶þÕßµÄÐγɵĻ¯Ñ§¼üÊǼ«ÐÔ¼ü£»ÑõÔªËØÊÇ»îÆõķǽðÊô£¬Ã¾ÊÇ»îÆõĽðÊô£¬¶þÕßÐγɵĻ¯Ñ§¼üÊÇÀë×Ó¼ü¡£
£¨3£©A¡¢CµÄµ¥ÖÊÖ±½Ó»¯ºÏÐγɵĻ¯ºÏÎïÊÇË®£¬ËùÒÔºÍÂÈÆø·´Ó¦µÄÀë×Ó·½³ÌʽÊÇCl2£«H2O===H£«£«Cl£­£«HClO¡£
£¨4£©¸ù¾Ý¼Û²ãµç×Ó¶Ô»¥³âÀíÂÛ¿ÉÖª£¬ÔÚ°±Æø·Ö×ÓÖеªÔªËغ¬ÓеŶԵç×Ó¶ÔÊýÊÇ£¨5£­1¡Á3£©¡Â2£½1£¬ËùÒÔ°±ÆøÊÇÈý½Ç׶Ðνṹ£¬µªÔ­×ÓÊÇsp3ÔÓ»¯£¬ÓÉÓÚÕý¸ºµçºÉ²»ÄÜÖغϣ¬ËùÒÔ°±ÆøÊôÓÚ¼«ÐÔ·Ö×Ó¡£
£¨5£©ÁòËáÍ­ÖеçÀë³öµÄÌúÀë×ÓÄܺÍË®·Ö×ÓÐγÉÅäλ¼ü£¬ÆäÖÐË®ÊÇÅäÌ壬ÅäλÊýÊÇ4£¬ËùÒÔ·´Ó¦µÄÀë×Ó·½³ÌʽÊÇCu2++4H2O=[Cu(H2O)4]2+ ¡£
£¨6£©·Ç½ðÊôÐÔԽǿ£¬µç¸ºÐÔÔ½´ó¡£ÓÉÓÚÑõÔªËصķǽðÊôÐÔ×îÇ¿£¬ËùÒÔÑõÔªËصĵ縺ÐÔ×î´ó¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø