ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÊµÑéÊÒÒªÅäÖÆ0.5mol/LNaClÈÜÒº480mL,ÏÖÓÃNaCl¹ÌÌåÅäÖÆ£¬°´ÏÂÁвÙ×÷²½ÖèÌî¿Õ£¬ÒÔʹÕû¸ö²Ù×÷ÍêÕû¡£
£¨1£©Ñ¡ÔñÒÇÆ÷¡£Íê³É±¾ÊµÑéËù±ØÐëµÄÒÇÆ÷ÓУºÍÐÅÌÌìƽ£¨¾«È·µ½0.1g£©¡¢Ò©³×¡¢ÉÕ±¡¢Á¿Í²¡¢²£Á§°ô¡¢_________________¡¢__________________ÒÔ¼°µÈÖÊÁ¿µÄÁ½Æ¬ÂËÖ½¡£
£¨2£©¼ÆËã¡£ÅäÖƸÃÈÜÒºÐèÒª³ÆÈ¡NaCl¹ÌÌå______________g¡£
£¨3£©³ÆÁ¿¡£
£¨4£©Èܽ⡣Èܽâºó______________£¨Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±£©Á¢¼´½«ÈÜҺתÒÆÖÁÈÝÁ¿Æ¿¡£
£¨5£©×ªÒÆ¡¢Ï´µÓ¡£×ªÒƺóӦϴµÓÉÕ±ºÍ²£Á§°ô2¡«3´Î£¬Ï´µÓÒºµÄÕýÈ·´¦Àí·½·¨ÊÇ_________¡£
A£®Ö±½Óµ¹ÈëÏÂË®µÀ B. µ¹ÈëÖ¸¶¨·ÏÒº¸× C. תÒƵ½ÈÝÁ¿Æ¿ÖÐ
Ä¿µÄÊÇ__________________________________________________¡£
£¨6£©ÔÚµÚ£¨4£©¡¢£¨5£©²½ÖоùÒªÓõ½²£Á§°ô£¬×÷Ó÷ֱðÊÇ_______________¡¢______________¡£
£¨7£©ÅäÖƹý³ÌÖУ¬Èô³öÏÖÏÂÁÐÇé¿ö£¬¶ÔËùÅäÈÜÒºµÄŨ¶ÈÓ°ÏìÊÇ£¨Ìî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±»ò¡°²»Ó°Ï족
¢Ù¶¨ÈÝʱÑöÊÓ______________¡£
¢Ú³ÆÁ¿Ê±Ò©Æ·ºÍíÀÂë·Å·´ÁË__________________¡£
¡¾´ð°¸¡¿ 500mLÈÝÁ¿Æ¿ ½ºÍ·µÎ¹Ü 14.6 ²»ÄÜ C ʹÈÜÖÊÈ«²¿×ªÈëÈÝÁ¿Æ¿£¬È·±£ËùÅäÈÜҺŨ¶ÈµÄ׼ȷÐÔ ½Á°è£¬¼Ó¿ìÈܽâËÙ¶È ÒýÁ÷£¬·ÀÖ¹ÒºÌ彦³ö Æ«µÍ Æ«µÍ
¡¾½âÎö¡¿£¨1£©Ã»ÓÐ480mLÈÝÁ¿Æ¿£¬Òò´ËÍê³É±¾ÊµÑéËù±ØÐëµÄÒÇÆ÷ÓУºÍÐÅÌÌìƽ£¨¾«È·µ½0.1g£©¡¢Ò©³×¡¢ÉÕ±¡¢Á¿Í²¡¢²£Á§°ô¡¢500mLÈÝÁ¿Æ¿¡¢½ºÍ·µÎ¹ÜÒÔ¼°µÈÖÊÁ¿µÄÁ½Æ¬ÂËÖ½¡££¨2£©ÅäÖƸÃÈÜÒºÐèÒª³ÆÈ¡NaCl¹ÌÌåµÄÖÊÁ¿ÊÇ0.5L¡Á0.5mol/L¡Á58.5g/mol¡Ö14.6g¡££¨4£©ÈܽâºóÐèÒªÀäÈ´µ½ÊÒκó½«ÈÜҺתÒÆÖÁÈÝÁ¿Æ¿¡££¨5£©Îª¼õÉÙÈÜÖÊËðʧ£¬Ï´µÓÒºµÄÕýÈ·´¦Àí·½·¨ÊÇתÒƵ½ÈÝÁ¿Æ¿ÖУ¬Ä¿µÄÊÇʹÈÜÖÊÈ«²¿×ªÈëÈÝÁ¿Æ¿£¬È·±£ËùÅäÈÜҺŨ¶ÈµÄ׼ȷÐÔ¡££¨6£©ÈܽâºÍתÒÆʱ²£Á§°ôµÄ×÷Ó÷ֱðÊǽÁ°è£¬¼Ó¿ìÈܽâËٶȺÍÒýÁ÷£¬·ÀÖ¹ÒºÌ彦³ö¡££¨7£©¢Ù¶¨ÈÝʱÑöÊÓ£¬ÈÜÒºÌå»ýÔö¼Ó£¬Å¨¶ÈÆ«µÍ¡£¢Ú³ÆÁ¿Ê±Ò©Æ·ºÍíÀÂë·Å·´Á˵¼ÖÂÈÜÖʵÄÖÊÁ¿¼õÉÙ£¬Å¨¶ÈÆ«µÍ¡£
¡¾ÌâÄ¿¡¿ÏÂÁÐʵÑé·½°¸ÖУ¬ÄܴﵽʵÑéÄ¿µÄµÄÊÇ
Ñ¡Ïî | ʵÑéÄ¿µÄ | ʵÑé·½°¸ |
A | ±È½ÏHFºÍHClOµÄËáÐÔÇ¿Èõ | ·Ö±ð²â¶¨µÈÌå»ýµÈÎïÖʵÄÁ¿Å¨¶ÈµÄHFºÍHClOÈÜÒºÏûºÄNaOHµÄÎïÖʵÄÁ¿ |
B | ¼ìÑéÈÜÒºÖÐÊÇ·ñº¬NH4+ | µÎ¼ÓÏ¡NaOHÈÜÒº£¬²¢½«ÈóʪµÄºìɫʯÈïÊÔÖ½ÖÃÓÚÊ¢·ÅÈÜÒºµÄÊԹܿڣ¬¹Û²ìÊÔÖ½ÑÕÉ«±ä»¯ |
C | Ö¤Ã÷Na2CO3ÈÜÒºÖдæÔÚË®½âƽºâ | Ïòº¬ÓзÓ̪µÄNa2CO3 ÈÜÒºÖмÓÈëÉÙÁ¿BaCl2¹ÌÌ壬¹Û²ìÈÜÒºÑÕÉ«±ä»¯ |
D | Ö¤Ã÷ŨÏõËá¾ßÓÐÇ¿Ñõ»¯ÐÔ | ³£ÎÂÏ£¬½«Ì¿ÓëŨÏõËá»ìºÏºó¹Û²ìÏÖÏó |
A. A B. B C. C D. D
¡¾ÌâÄ¿¡¿ÎÄÏ×¼ÇÔØ£¬Ìú·ÛÔÚÏ¡ÏõËáÖлá·Å³öÇâÆø¡£Ä³Í¬Ñ§½øÐÐÈçÏÂÑéÖ¤ºÍ¶Ô±ÈʵÑé¡£
ʵÑéI. ÊÒÎÂÏ £¨20¡æ£©£¬ ÔÚºãѹÃܱÕÈÝÆ÷ÄÚ·ÅÈë¹ýÁ¿Ìú·ÛºÍ 2.0 mL 0.5 mol¡¤L¨C1 HNO3£¬Á¢¼´ÓÐÆøÌåÉú³É¡£³ä·Ö·´Ó¦ºó£¬ËùµÃÈÜÒº¼¸ºõÎÞÉ«£¬ÊÕ¼¯µ½ÎÞÉ«ÆøÌå 6.0 mL¡£½«¸ÃÆøÌåͨÈëÓпÕÆøµÄÊԹܣ¬ÎÞÃ÷ÏԱ仯¡£µãȼÆøÌ壬ÓмâÈñ±¬ÃùÉù£¬ÊԹܱڳöÏÖÒºµÎ¡£È¡·´Ó¦ºóÈÜÒº£¬¼ÓÈë×ãÁ¿ NaOH ÈÜÒºµÃµ½»ÒÂÌÉ«³Áµí¡£Öó·Ðʱ£¬ÕôÆøÂÔÓд̼¤ÐÔÆøζ²¢ÄÜʹʪÈóºìɫʯÈïÊÔÖ½±äÀ¶¡£
£¨1£©ÆøÌå²úÎïΪÇâÆøµÄÖ¤¾ÝÊÇ______________________ ¡£
£¨2£©¸ù¾ÝʵÑéÏÖÏó£¬ Ð´³öÌú·ÛÓë 0.5 mol¡¤L¨C1 ÏõËᷴӦʱ»¹Ô·´Ó¦µÄ°ë·´Ó¦·½³Ìʽ¡£¢Ù 2H+ + 2e¨C = H2¡ü£» ¢Ú_____________ ¡£
£¨3£©¸Ãͬѧ¶Ô²úÉúÇâÆøµÄÔÒòÌá³ö¼ÙÉ裺
¼ÙÉè 1£º¸ÃŨ¶ÈµÄÏõËáÖÐ H+µÄÑõ»¯ÐÔ´óÓÚNO3-£»
¼ÙÉè 2£º H+µÄ»¹ÔËÙÂÊ´óÓÚNO3-µÄ»¹ÔËÙÂÊ£»
I. ÑéÖ¤¼ÙÉè 1£ºÓÃ____£¨Cu»òMg£©·ÛÓë_____ ÏõËá·´Ó¦£¬ËµÃ÷¼ÙÉè1²»³ÉÁ¢¡£ÊµÑéÖ¤¾ÝÊÇ______________________ ¡£
II. ÑéÖ¤¼ÙÉè 2£º ¸Ä±äÌõ¼þÖظ´ÊµÑé I£¬½á¹ûÈçÏ£¨ÆøÌå³É·ÖºÍÈÜÒº³É·Ö¼ìÑéµÄÏÖÏóÓëʵÑé I ÏàËÆ£©¡£
ÐòºÅ | ½ðÊô״̬ | ·´Ó¦ÎÂ¶È | ʵÑéÏÖÏó |
a | Ìú·Û | 40¡æ | ÈÜÒºÂÔ´ø»ÆÉ«£¬ÆøÌå 3.4 mL¡£ |
b | Ìú·Û | 60¡æ | »ÆÉ«ÈÜÒº£¬ÆøÌå 2.6 mL¡£ |
¢Ù¸ù¾ÝʵÑéÏÖÏó£¬ÄãÈÏΪ¼ÙÉè2ÊÇ·ñ³ÉÁ¢£¿¼òÊöÀíÓÉ¡£__________________________
¢ÚÊÔ·ÖÎöζȶÔÌú·ÛÓëÏõËá·´Ó¦Éú³ÉÇâÆøÌå»ýµÄÓ°Ïì¡£__________________________
£¨4£©¸ÄÓà 3 mol¡¤L¨C1 HNO3Óë¹ýÁ¿Ìú·Û·´Ó¦£¬ ÓÐÎÞÉ«ÆøÌåÉú³É£¬ ÈÜÒº±äΪÉî×ØÉ«¡£ÆøÌå½Ó´¥¿ÕÆøÏÔºì×ØÉ«£¬²»¿Éȼ¡£ ¸ù¾ÝÒÔÉϽáÂÛ½âÊÍÉú³É»¹Ô²úÎïµÄÔÒò__________________________
£¨5£©×ÛÉÏËùÊö£¬½ðÊôÓëÏõËáÉú³ÉÇâÆø£¬ÐèÒª¿ØÖÆÄÄЩÌõ¼þ£¿__________________________________