ÌâÄ¿ÄÚÈÝ

£¨15·Ö£©ÏÂͼÊÇÖÐѧ»¯Ñ§³£¼ûÎïÖʵÄת»¯¹Øϵ£¨Ä³Ð©·´Ó¦Ìõ¼þ¼°²¿·Ö²úÎïÒÑÂÔÈ¥£©£¬A¡¢GΪÈÕ³£Éú»îÖеij£¼û½ðÊô¡£B¡¢C¡¢E¡¢I¡¢JΪÆøÌ壬ÆäÖÐCΪ»ÆÂÌÉ«ÆøÌ壬MΪºìºÖÉ«½ºÌå¡£

£¨1£©ÒÑÖªAΪµÚ26ºÅÔªËØ£¬Çëд³öAÔªËØÔÚÖÜÆÚ±íÖеÄλÖÃ__________¡£

£¨2£©DÓëG·´Ó¦µÄ»¯Ñ§·½³Ìʽ_________________________¡£

£¨3£©·´Ó¦¢ÚÀë×Ó·½³Ìʽ__________________________¡£

£¨4£©F¡úMµÄ²Ù×÷·½·¨_______________¡£

£¨5£©ÏÖ½«Ò»ÊÔ¹ÜJÆøÌåµ¹Á¢ÓÚË®²ÛÖÐÒ»¶Îʱ¼äºó£¬Ë®ÃæÉÏÉýµ«²»³äÂú£»Èôʹˮ³äÂúÕû¸öÊԹܣ¬Ó¦ÏòÊÔ¹ÜÖÐͨÈëÒ»¶¨Á¿__________£¨ÌîÆøÌåµÄ»¯Ñ§Ê½£©£¬´ËʱÊÔ¹ÜÖÐÈÜÒºµÄŨ¶ÈΪ________mol/L£¨ÆøÌåÌå»ý°´±ê×¼×´¿ö¼ÆË㣩£¨±£ÁôÁ½Î»ÓÐЧÊý×Ö£©¡£

£¨6£©¢ÙX¡¢Y¾ùΪ¶ÌÖÜÆÚÔªËØ£¬X×îÍâ²ãµç×ÓÊý±ÈCÆøÌåËùº¬ÔªËØ×îÍâ²ãµç×ÓÉÙ1¸öÇÒ²»Í¬ÖÜÆÚ£¬YÓëXͬÖ÷×壬ÏÂÁйØÓÚX¡¢Y¡¢CÈýÔªËØ˵·¨ÕýÈ·µÄÊÇ__________¡£

A£®Ô­×Ӱ뾶  X£¼Y£¼C         B£®Àë×Ӱ뾶  X£¼C£¼Y

C£®·Ç½ðÊôÐÔ  X£¼Y£¼C         D£®×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïËáÐÔ C£¾X£¾Y

E£®Ç⻯Îï·Ðµã X£¼Y£¼C

¢Ú Çëд³öXµÄÇ⻯ÎïÖÐÔ­×Ó¸öÊý±ÈΪ1£º1µÄ»¯ºÏÎïµÄµç×Óʽ_________¡£

£¨7£©DÓëG·´Ó¦Éú³ÉAµÄͬʱ£¬»¹ÓÐÁíÒ»ÖÖ²úÎ¹¤ÒµÉÏÓÃÂÁÍÁ¿ó£¨Ö÷Òª³É·ÖΪAl2O3¡¢¡¢SiO2¡¢Fe2O3£©ÌáÈ¡ÆäµÄ¹¤ÒÕÁ÷³ÌÈçÏ£º

½áºÏ·´Ó¦II£¬ÅжÏÏÂÁÐ΢Á£½áºÏÖÊ×Ó£¨H+£©µÄÄÜÁ¦ÓÉÇ¿µ½ÈõµÄ˳ÐòÊÇ_________£¨Ìî×ÖĸÐòºÅ£©¡£

A£®AlO2¡ª       B£®OH¡ª        C£®SiO32¡ª

 

 

£¨1£©µÚËÄÖÜÆÚ  µÚVIII×å  1·Ö

£¨2£©8Ai + 3Fe3O4 =¸ßÎÂ=4Al2O3 + 9Fe     2·Ö

£¨3£© 3Fe + 8H+ + 2NO3¡ª=== 3Fe2+ + 2NO¡ü+ 4H2O  2·Ö

£¨4£©ÔÚÂÁÈȼÁ±íÃæ·ÅÒ»²ãÂÈËá¼Ø£¬²åÒ»¸ùþÌõ£¬µãȼþÌõ  2·Ö

£¨5£©O2  1·Ö   0.045   2·Ö

£¨6£©B    1·Ö                       2·Ö

£¨7£©BAC    2·Ö

½âÎö:

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨2012?Ìì½òÄ£Ä⣩A¡¢B¡¢C¡¢D¡¢EÊÇÖÐѧ»¯Ñ§³£¼ûµÄ5ÖÖ»¯ºÏÎÆäÖÐA¡¢BÊÇÑõ»¯Îµ¥ÖÊX¡¢YÊÇÉú»îÖг£¼ûµÄ½ðÊô£¬ÊÔ¼Á1ºÍÊÔ¼Á2·Ö±ðΪ³£¼ûµÄËá»ò¼î£®Ïà¹ØÎïÖʼäµÄת»¯¹ØϵÈçÏÂͼËùʾ£¨²¿·Ö·´Ó¦ÎïÓë²úÎïÒÑÂÔÈ¥£©£º

Çë»Ø´ð£º
£¨1£©¢Ù×é³Éµ¥ÖÊXµÄÔªËØÔ­×ӽṹʾÒâͼÊÇ
£»
¢Ú×é³Éµ¥ÖÊYµÄÔªËØÔÚÖÜÆÚ±íÖеÄλÖÃ
µÚËÄÖÜÆÚµÚ VIII×å
µÚËÄÖÜÆÚµÚ VIII×å
£®
£¨2£©ÈôÊÔ¼Á1Ϊǿ¼îÈÜÒº£¬ÔòXÓëÊÔ¼Á1·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ
2Al+2H2O+2OH-=2AlO2-+3H2¡ü
2Al+2H2O+2OH-=2AlO2-+3H2¡ü
£®
£¨3£©¢ÙÈôÊÔ¼Á1ºÍÊÔ¼Á2Ïàͬ£¬ÇÒEÈÜÒº¼ÓÈÈÕô¸É²¢×ÆÉÕºó¿ÉµÃµ½A£¬ÔòAµÄ»¯Ñ§Ê½ÊÇ
Fe2O3
Fe2O3
£®
¢Ú½«ÎïÖÊCÈÜÓÚË®£¬ÆäÈÜÒº³Ê
ËáÐÔ
ËáÐÔ
£¨Ìî¡°ËáÐÔ¡±¡¢¡°ÖÐÐÔ¡±»ò¡°¼îÐÔ¡±£©£¬Ô­ÒòÓÃÀë×Ó·½³Ìʽ¿É±íʾΪ
Al3++3H2O?Al£¨OH£©3+3H+
Al3++3H2O?Al£¨OH£©3+3H+
£®
£¨4£©ÈôÊÔ¼Á2ΪϡÁòËᣬ¹¤ÒµÉÏÒÔE¡¢Ï¡ÁòËáºÍNaNO2ΪԭÁÏÖƱ¸¸ßЧ¾»Ë®¼ÁY£¨OH£©SO4£¬ÇÒ·´Ó¦ÖÐÓÐNOÉú³É£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ
2FeSO4+2NaNO2+H2SO4=2Fe£¨OH£©SO4+Na2SO4+2NO¡ü
2FeSO4+2NaNO2+H2SO4=2Fe£¨OH£©SO4+Na2SO4+2NO¡ü
£®
£¨5£©Ç뽫D+Y¡úEµÄ¹ý³ÌÉè¼Æ³ÉÒ»¸öÄܲúÉú³ÖÐø¶øÎȶ¨µçÁ÷µÄÔ­µç³Ø×°Öã¨Ê¹ÓÃÑÎÇÅ£©£¬ÔÚ¿ò¸ñÄÚ»­³öʵÑé×°ÖÃͼ£¬²¢ÔÚͼÖбê³öµç¼«ºÍÊÔ¼ÁµÄÃû³Æ£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø