ÌâÄ¿ÄÚÈÝ
(¹²10·Ö)ij»¯Ñ§Ð¡×éÒÔ»·¼º´¼ÖƱ¸»·¼ºÏ©£¨ÈçÏÂͼ£©£¬
£¨1£©ÖƱ¸´ÖÆ·
½«12.5mL»·¼º´¼¼ÓÈëÊÔ¹ÜAÖУ¬ÔÙ¼ÓÈëlmLŨÁòËᣬҡÔȺó·ÅÈëËé´ÉƬ£¬»ºÂý¼ÓÈÈÖÁ·´Ó¦ÍêÈ«£¬ÔÚÊÔ¹ÜCÄڵõ½»·¼ºÏ©´ÖÆ·¡£
¢Ù AÖÐËé´ÉƬµÄ×÷ÓÃÊÇ___________£¬µ¼¹ÜB³ýÁ˵¼ÆøÍ⻹¾ßÓеÄ×÷ÓÃÊÇ_________£»
¢ÚÊÔ¹ÜCÖÃÓÚ±ùˮԡÖеÄÄ¿µÄÊÇ____________________________¡£
£¨2£©ÖƱ¸¾«Æ·
¢Ù »·¼ºÏ©´ÖÆ·Öк¬Óл·¼º´¼ºÍÉÙÁ¿ËáÐÔÔÓÖʵȡ£¼ÓÈë±¥ºÍʳÑÎË®£¬Õñµ´¡¢¾²Öᢷֲ㣬»·¼ºÏ©ÔÚ_________²ã(ÌîÉÏ»òÏÂ)£¬·ÖÒººóÓÃ_________ (Ìî×Öĸ)Ï´µÓ£»
a£®KMnO4ÈÜÒº b£®Ï¡H2SO4 c£®Na2CO3ÈÜÒº
¢Ú ÔÙ½«»·¼ºÏ©°´ÓÒͼװÖÃÕôÁó£¬ÀäÈ´Ë®´Ó_________¿Ú½øÈë(Ìî×Öĸ)¡£ÕôÁóʱҪ¼ÓÈëÉúʯ»Ò£¬Ä¿µÄÊÇ___________________£»
¢Û ÊÕ¼¯²úƷʱ£¬¿ØÖƵÄζÈÓ¦ÔÚ_________×óÓÒ£¬ÊµÑéÖƵõĻ·¼ºÏ©¾«Æ·ÖÊÁ¿µÍÓÚÀíÂÛ²úÁ¿£¬¿ÉÄܵÄÔÒòÊÇ______(Ìî×Öĸ)£»
a£®ÕôÁóʱ´Ó70¡æ¿ªÊ¼ÊÕ¼¯²úÆ·
b£®»·¼º´¼Êµ¼ÊÓÃÁ¿¶àÁË
c£®ÖƱ¸´ÖƷʱ»·¼º´¼Ëæ²úÆ·Ò»ÆðÕô³ö
£¨3£© ÒÔÏÂÇø·Ö»·¼ºÏ©¾«Æ·ºÍ´ÖÆ·µÄ·½·¨£¬ºÏÀíµÄÊÇ_________(Ìî×Öĸ)¡£
a£®ÓÃËáÐÔ¸ßÃÌËá¼ØÈÜÒº b£®ÓýðÊôÄÆ c£®²â¶¨·Ðµã
(ÿ¿Õ1·Ö£¬¹²10·Ö)
£¨1£©¢Ù·À±©·Ð ÀäÄý ¢ÚÉú³ÉµÄ»·¼ºÏ©±ä³ÉÒºÌ壬·ÀÖ¹»Ó·¢
£¨2£©¢ÙÉϲã c
¢Ú g ÎüÊÕÉú³ÉµÄË®£¬·ÀֹˮÕôÆøËæ»·¼ºÏ©Ò»ÆðÕô³ö
¢Û 83oC c (3) b
¡¾½âÎö¡¿ÂÔ