ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿ÔÚʵÑéÊÒÖÐÓöþÑõ»¯Ã̸úŨÑÎËá·´Ó¦ÖƱ¸¸ÉÔï´¿¾»µÄÂÈÆø¡£½øÐдËʵÑ飬ËùÓÃÒÇÆ÷ÈçÏÂͼ£º

(1)Á¬½ÓÉÏÊöÒÇÆ÷µÄÕýȷ˳Ðò(Ìî¸÷½Ó¿Ú´¦µÄ×Öĸ)£º____½Ó____£»____½Ó____£»____½Ó____£»____½Ó____¡£

(2)×°ÖÃÖУ¬±¥ºÍʳÑÎË®µÄ×÷ÓÃÊÇ__________________________£»

(3)»¯Ñ§ÊµÑéÖг£ÓÃʪÈóµÄµí·Û£­KIÊÔÖ½¼ìÑéÊÇ·ñÓÐCl2²úÉú¡£Èç¹ûÓÐCl2²úÉú£¬¿É¹Û²ìµ½________£¬·´Ó¦·½³Ìʽ__________________¡£

(4)д³öÏÂÁл¯Ñ§·´Ó¦µÄ·½³Ìʽ£º

¢ÙÆøÌå·¢Éú×°ÖýøÐеķ´Ó¦£º______________¡£¢ÚNaOHÈÜÒºÖз¢ÉúµÄ·´Ó¦£º_____________¡£

(5)KMnO4µÄÑõ»¯ÐÔ±ÈMnO2Ç¿µÃ¶à£¬ÊµÑéÊÒÒ²¿ÉÒÔÓÃKMnO4¹ÌÌåºÍŨÑÎËá·´Ó¦ÖÆÈ¡ÂÈÆø£¬·´Ó¦·½³ÌʽÈçÏ£º2KMnO4£«16HCl(Ũ)===2KCl£«2MnCl2£«5Cl2¡ü£«8H2O¡£

¢ÙÇëÓá°µ¥ÏßÇÅ¡±±ê³öµç×ÓתÒƵķ½ÏòºÍÊýÄ¿_________£»

¢Ú¸Ã·´Ó¦Öб»Ñõ»¯ºÍδ±»Ñõ»¯µÄHClµÄÎïÖʵÄÁ¿Ö®±ÈÊÇ________£¬Èç¹û½«20 mL¡¢12 mol¡¤L£­1µÄŨÑÎËáÓë×ãÁ¿KMnO4³ä·Ö·´Ó¦£¬Êµ¼ÊÄÜÊÕ¼¯µ½µÄÂÈÆøÔÚ±ê×¼×´¿öϵÄÌå»ý½«________¡£

A£®¡Ý1.68 L B£®£¾1.68 L C£®¡Ü1.68 L D£®£¼1.68 L

¡¾´ð°¸¡¿ E C D A B H G F ³ýÈ¥ÂÈÆøÖеÄHClÔÓÖÊ ÊÔÖ½±äÀ¶ 2KI£«Cl2===2KCl£«I2 MnO2£«4HCl(Ũ) MnCl2£«Cl2¡ü£«2H2O 2NaOH£«Cl2===NaCl£«NaClO£«H2O 5¡Ã3 D

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿Ìú±»ÓþΪ¡°µÚÒ»½ðÊô¡±£¬Ìú¼°Æ仯ºÏÎï¹ã·ºÓ¦ÓÃÓÚÉú»î¡¢Éú²ú¡¢¹ú·ÀµÈÁìÓò¡£

£¨1£©Fe2+Êǹ¹³ÉÈËÌåѪºìµ°°×£¨Èçͼ1Ëùʾ£©µÄÖØÒªÔªËØ£¬»ù̬Fe2+¼ò»¯µÄµç×ÓÅŲ¼Ê½Îª___________£»ÓÃÎïÖʽṹÓëÐÔÖÊ֪ʶ·ÖÎöFe2+ÔÚ¿ÕÆøÖÐÈÝÒ×±»Ñõ»¯³ÉFe3+µÄÖ÷ÒªÔ­Òò£º_________________________________________¡£

£¨2£©Ñªºìµ°°×ÖÐËùº¬·Ç½ðÊôÔªËصĵ縺ÐÔÓÉСµ½´óµÄ˳ÐòΪ___________£»Ì¼Ô­×ÓµÄÔÓ»¯¹ìµÀÀàÐÍΪ__________________ÔÓ»¯¡£

£¨3£©ôÊ»ùÌú[Fe(CO)5]¿ÉÓÃ×÷´ß»¯¼ÁµÈ¡£1mol[Fe(CO)5]·Ö×ÓÖк¬ÓÐ____molµÄ¦Ò¼ü£¬ÓëCO»¥ÎªµÈµç×ÓÌåµÄÀë×ӵĻ¯Ñ§Ê½Îª___________________________£¨Ð´Ò»ÖÖ£©¡£

£¨4£©¾Ý±¨µÀ£¬¹¤ÒµÉϿɵç½âÈÛÈÚµÄFeO¡¢Fe2O3Ò±Á¶¸ß´¿Ìú¡£Fe2O3µÄÈÛµã____________£¨Ìî¡°¸ßÓÚ¡±»ò¡°µÍÓÚ¡±£© FeOµÄÈ۵㣬ÀíÓÉÊÇ____________________________________________¡£

£¨5£©Ìú¾§ÌåÓÐÃæÐÄÁ¢·½¡¢ÌåÐÄÁ¢·½¡£ÔÚÕâÁ½ÖÖ¾§ÌåÖÐÌúµÄÅäλÊýÖ®±ÈΪ______________¡£

£¨6£©Ä³ÖÖµª»¯Ìú¾§ÌåµÄ¾§°ûÈçͼ2Ëùʾ¡£ÒÑÖª£º¸Ã¾§°û±ß³¤¡¢¸ß·Ö±ðΪanm¡¢bnm£¬NA=6.02¡Á1023mol-l

¢Ù¸Ãµª»¯Ìú¾§ÌåµÄ»¯Ñ§Ê½Îª______________¡£

¢ÚÁÐʽ±íʾ¸Ãµª»¯Ìú¾§ÌåµÄÃܶÈ_________________________________________¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø