ÌâÄ¿ÄÚÈÝ
A¡¢B¡¢C¡¢D¡¢EΪ¶ÌÖÜÆÚÔªËØ£¬A¡ªEÔ×ÓÐòÊýÒÀ´ÎÔö´ó£¬ÖÊ×ÓÊýÖ®ºÍΪ40£¬B¡¢CͬÖÜÆÚ£¬A¡¢DͬÖ÷×壬A¡¢CÄÜÐγÉÁ½ÖÖҺ̬»¯ºÏÎïA(1)BÔªËØÔÚÖÜÆÚ±íÖеÄλÖÃΪ________________________________¡£
(2)½«DµÄµ¥ÖÊͶÈëA
(3)A¡¢CÁ½ÔªËØ¿É×é³É10µç×ÓÁ£×ÓX-¡£YÓëX-¾ßÓÐÏàͬµÄÔ×ÓÖÖÀ༰ÊýÄ¿£¬ÇÒ²»´øµç£¬YµÄµç×ÓʽΪ________________________¡£
(4)·ÏÓ¡Ë¢µç·°åÉϺ¬ÓÐÍ£¬ÒÔÍùµÄ»ØÊÕ·½·¨Êǽ«Æä×ÆÉÕʹÍת»¯ÎªÑõ»¯Í£¬ÔÙÓÃÁòËáÈܽ⡣ÏÖ¸ÄÓÃA
(5)ÎÒ¹úÊ×´´µÄº£Ñóµç³ØÒÔEµÄµ¥ÖÊΪ¸º¼«£¬²¬ÍøΪÕý¼«£¬¿ÕÆø×÷Ñõ»¯¼Á£¬º£Ë®×÷µç½âÖÊÈÜÒº¡£
µç³ØµÄÕý¼«·´Ó¦Ê½Îª________________£¬µç³Ø×Ü·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ________________¡£
(1)µÚ¶þÖÜÆÚµÚ¢õA×å
(2)2OH-+2Al+2H2O2
+3H2¡ü
(3)
(4)Cu+H2O2+H2SO4CuSO4+2H2O
(5)O2+4e-+2H2O4OH-
4Al+3O2+6H2O4Al(OH)3
½âÎö£ºÒòA¡¢B¡¢C¡¢D¡¢EÔ×ÓÐòÊýÒÀ´ÎÔö´ó£¬A¡¢CÐγÉA

ÏÖÓÐÆßÖÖÔªËØ£¬ÆäÖÐA¡¢B¡¢C¡¢D¡¢EΪ¶ÌÖÜÆÚÖ÷×åÔªËØ£¬F¡¢GΪµÚËÄÖÜÆÚÔªËØ£¬ËüÃǵÄÔ×ÓÐòÊýÒÀ´ÎÔö´ó£®Çë¸ù¾ÝÏÂÁÐÏà¹ØÐÅÏ¢£¬»Ø´ðÎÊÌ⣮
AÔªËصĺËÍâµç×ÓÊýºÍµç×Ó²ãÊýÏàµÈ£¬Ò²ÊÇÓîÖæÖÐ×î·á¸»µÄÔªËØ |
BÔªËØÔ×ӵĺËÍâpµç×ÓÊý±Èsµç×ÓÊýÉÙ1 |
CÔ×ӵĵÚÒ»ÖÁµÚËĵçÀëÄÜ·Ö±ðÊÇ£º I1=738kJ/mol I2=1451kJ/mol I3=7733kJ/mol I4=10540kJ/mol |
DÔ×ÓºËÍâËùÓÐp¹ìµÀÈ«Âú»ò°ëÂú |
EÔªËصÄÖ÷×åÐòÊýÓëÖÜÆÚÊýµÄ²îΪ4 |
FÊÇÇ°ËÄÖÜÆÚÖе縺ÐÔ×îСµÄÔªËØ |
GÔÚÖÜÆÚ±íµÄµÚÆßÁÐ |
£¨2£©B»ù̬Ô×ÓÖÐÄÜÁ¿×î¸ßµÄµç×Ó£¬Æäµç×ÓÔÆÔÚ¿Õ¼äÓÐ
ÐΣ®
£¨3£©»³öCÔ×ӵĵç×ÓÅŲ¼Í¼
£¨4£©ÒÑÖªBA5ΪÀë×Ó»¯ºÏÎд³öÆäµç×Óʽ
£¨5£©DE3ÖÐÐÄÔ×ÓµÄÔÓ»¯·½Ê½Îª
£¨6£©Óõç×Óʽ±íʾFÔªËØÓëEÔªËØÐγɻ¯ºÏÎïµÄÐγɹý³Ì