ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿CH4³¬¸ÉÖØÕûCO2¼¼Êõ¿ÉµÃµ½¸»º¬COµÄ»¯¹¤ÔÁÏ¡£»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©CH4³¬¸ÉÖØÕûCO2µÄ´ß»¯×ª»¯ÈçͼËùʾ£º
¢ÙÒÑÖªÏà¹Ø·´Ó¦µÄÄÜÁ¿±ä»¯ÈçͼËùʾ£º
¹ý³Ì¢ñµÄÈÈ»¯Ñ§·½³ÌʽΪ________¡£
¢Ú¹ØÓÚÉÏÊö¹ý³Ì¢òµÄ˵·¨²»ÕýÈ·µÄÊÇ________£¨ÌîÐòºÅ£©¡£
a£®ÊµÏÖÁ˺¬Ì¼ÎïÖÊÓ뺬ÇâÎïÖʵķÖÀë
b£®¿É±íʾΪCO2£«H2£½H2O£¨g£©£«CO
c£®COδ²ÎÓë·´Ó¦
d£®Fe3O4¡¢CaOΪ´ß»¯¼Á£¬½µµÍÁË·´Ó¦µÄ¦¤H
¢ÛÆäËûÌõ¼þ²»±ä£¬ÔÚ²»Í¬´ß»¯¼Á£¨¢ñ¡¢¢ò¡¢¢ó£©×÷ÓÃÏ£¬·´Ó¦CH4£¨g£©£«CO2£¨g£©£½2CO£¨g£©£«2H2£¨g£©½øÐÐÏàͬʱ¼äºó£¬CH4µÄת»¯ÂÊË淴Ӧζȵı仯ÈçͼËùʾ¡£aµãËù´ú±íµÄ״̬________£¨Ìî¡°ÊÇ¡±»ò¡°²»ÊÇ¡±£©Æ½ºâ״̬£»bµãCH4µÄת»¯ÂʸßÓÚcµã£¬ÔÒòÊÇ________¡£
£¨2£©ÔÚÒ»¸ÕÐÔÃܱÕÈÝÆ÷ÖУ¬CH4ºÍCO2µÄ·Öѹ·Ö±ðΪ20kPa¡¢25kPa£¬¼ÓÈëNi£¯¦Á£Al2O3´ß»¯¼Á²¢¼ÓÈÈÖÁ1123KʹÆä·¢Éú·´Ó¦CH4£¨g£©£«CO2£¨g£©£½2CO£¨g£©£«2H2£¨g£©¡£
¢ÙÑо¿±íÃ÷COµÄÉú³ÉËÙÂʦԣ¨CO£©£½1.3¡Á10£2¡¤p£¨CH4£©¡¤p£¨CO2£©mol¡¤g£1¡¤s£1£¬Ä³Ê±¿Ì²âµÃp£¨CO£©£½20kPa£¬Ôòp£¨CO2£©£½________kPa£¬¦Ô£¨CO£©£½________mol¡¤g£1¡¤s£1¡£
¢Ú´ïµ½Æ½ºâºó²âµÃÌåϵѹǿÊÇÆðʼʱµÄ1.8±¶£¬Ôò¸Ã·´Ó¦µÄƽºâ³£ÊýµÄ¼ÆËãʽΪKp£½________£¨kPa£©2¡££¨Óø÷ÎïÖʵķÖѹ´úÌæÎïÖʵÄÁ¿Å¨¶È¼ÆË㣩
£¨3£©CH4³¬¸ÉÖØÕûCO2µÃµ½µÄCO¾Å¼Áª·´Ó¦¿ÉÖƵòÝËᣨH2C2O4£©¡£³£ÎÂÏ£¬ÏòijŨ¶ÈµÄ²ÝËáÈÜÒºÖмÓÈëÒ»¶¨Å¨¶ÈµÄNaOHÈÜÒº£¬ËùµÃÈÜÒºÖУ¬Ôò´ËʱÈÜÒºµÄpH£½________¡££¨ÒÑÖª³£ÎÂÏÂH2C2O4µÄKa1£½6¡Á10£2£¬Ka2£½6¡Á10£5£¬lg6£½0.8£©
¡¾´ð°¸¡¿CH4(g)+CO2(g)=2CO(g)+2H2(g) ¦¤H=247.4kJ¡¤mol-1 cd ²»ÊÇ bºÍc¶¼Î´´ïƽºâ£¬bµãζȸߣ¬·´Ó¦ËÙÂʿ죬Ïàͬʱ¼äÄÚת»¯ÂÊ¸ß 15 1.95 2.7
¡¾½âÎö¡¿
ÓÉÄÜÁ¿£·´Ó¦½ø³ÌÇúÏßµÃÈÈ»¯Ñ§·½³Ìʽ£¬Ó¦ÓøÇ˹¶¨Âɿɵùý³ÌIµÄÈÈ»¯Ñ§·½³Ìʽ¡£¹ý³ÌIIÖнøÈëÑ»·µÄÎïÖÊÊÇ×î³õ·´Ó¦Î³öÑ»·µÄÎïÖÊÊÇ×îÖÕÉú³ÉÎ¿ÉµÃ×Ü·´Ó¦·½³Ìʽ¡£ºãκãÈÝʱ×é·ÖÆøÌåµÄ·ÖѹÓëÆäÎïÖʵÄÁ¿³ÉÕý±È£¬¹ÊÓ÷Öѹ´úÌæÎïÖʵÄÁ¿½øÐмÆËã¡£²ÝËáÈÜÒºÓëNaOHÈÜÒº»ìºÏºó£¬ÆäÁ½²½µçÀëƽºâÈÔÈ»´æÔÚ£¬¾ÝµçÀë³£Êý±í´ïʽ¿ÉÇóÌض¨Ìõ¼þÏÂÈÜÒºµÄpH¡£
(1)¢Ù¾ÝCH4³¬¸ÉÖØÕûCO2µÄ´ß»¯×ª»¯Í¼£¬¹ý³ÌIµÄ»¯Ñ§·´Ó¦ÎªCH4(g)+CO2(g)=2CO(g)+2H2(g)¡£ÓÉÄÜÁ¿£·´Ó¦½ø³ÌÇúÏßµÃÈÈ»¯Ñ§·½³Ìʽ£º
CH4(g)+H2O(g)=CO(g)+3H2(g) ¦¤H£½+206.2kJ¡¤mol-1 £¨i£©
CO2(g)+4H2(g)=CH4(g)+2H2O(g) ¦¤H£½£165kJ¡¤mol-1 £¨ii£©
(i)¡Á2+(ii)µÃ¹ý³ÌIµÄÈÈ»¯Ñ§·½³Ìʽ£ºCH4(g)+CO2(g)=2CO(g)+2H2(g) ¦¤H=247.4kJ¡¤mol-1
¢Ú¹ý³Ì¢òÎïÖʱ仯Ϊ£º×óÉÏ£¨CO¡¢H2¡¢CO2£©+ ÓÒÏ£¨¶èÐÔÆøÌ壩¡ú ×óÏ£¨H2O£©+ ÓÒÉÏ£¨CO¡¢¶èÐÔÆøÌ壩£¬×Ü·´Ó¦ÎªH2+CO2=H2O+CO¡£Fe3O4¡¢CaOΪ×Ü·´Ó¦µÄ´ß»¯¼Á£¬ÄܽµµÍ·´Ó¦µÄ»î»¯ÄÜ£¬µ«²»Äܸı䷴ӦµÄ¦¤H¡£¹ÊabÕýÈ·£¬cd´íÎó¡£
¢Ûͨ³££¬´ß»¯¼ÁÄܼӿ췴ӦËÙÂÊ£¬Ëõ¶Ì·´Ó¦µ½´ïƽºâµÄʱ¼ä¡£µ«´ß»¯¼Á²»ÄÜʹƽºâ·¢ÉúÒƶ¯£¬¼´²»Äܸıäƽºâת»¯ÂÊ¡£ÈôͼÖÐaµãΪ»¯Ñ§Æ½ºâ£¬Ôò±£³ÖζȲ»±ä£¨800¡æ£©£¬½«´ß»¯¼ÁII»»³ÉI»òIII£¬CH4ת»¯ÂÊÓ¦²»±ä£¬¹Êaµã²»ÊÇ»¯Ñ§Æ½ºâ¡£
ͬÀí£¬Í¼ÖÐb¡¢cÁ½µã¶¼Î´´ïµ½»¯Ñ§Æ½ºâ¡£¾ÝÌâÒ⣬b¡¢cÁ½µãÖ»ÓÐζȲ»Í¬£¬bµãζȽϸߣ¬·´Ó¦ËÙÂʿ죬Ïàͬʱ¼äÄÚCH4ת»¯Âʸߡ£
(2)¢Ù¾ÝÆø̬·½³ÌPV£½nRT£¬ºãκãÈÝʱij×é·ÖÆøÌåµÄ·ÖѹÓëÆäÎïÖʵÄÁ¿³ÉÕý±È¡£Ôò·´Ó¦ÖзÖѹΪ
1123KºãÈÝʱ£¬CH4£¨g£©£«CO2£¨g£©£½2CO£¨g£©£«2H2£¨g£©
Æðʼ·Öѹ/kPa£º 20 25 0 0
¸Ä±ä·Öѹ/kPa£º 10 10 20 20
ijʱ·Öѹ/kPa£º 10 15 20 20
¼´Ä³Ê±¿Ìp(CO2)£½15kPa£¬p(CH4)£½10kPa¡£´úÈë¦Ô(CO)£½1.3¡Á10£2¡¤p(CH4)¡¤p(CO2)mol¡¤g£1¡¤s£1£½1.95mol¡¤g£1¡¤s£1¡£
¢ÚÉè´ïµ½Æ½ºâʱCH4µÄ¸Ä±ä·ÖѹΪx kPa£¬
1123KºãÈÝʱ£¬CH4£¨g£©£«CO2£¨g£©£½2CO£¨g£©£«2H2£¨g£©
Æðʼ·Öѹ/kPa£º 20 25 0 0
¸Ä±ä·Öѹ/kPa£º x x 2x 2x
ƽºâ·Öѹ/kPa£º 20£x 25£x 2x 2x
¾ÝÌâÒ⣬ÓУ½1.8£¬½âµÃx£½18¡£CH4(g)¡¢CO2(g)¡¢CO(g)¡¢H2(g)µÄƽºâ·ÖѹÒÀ´ÎÊÇ2 kPa¡¢7 kPa¡¢36 kPa¡¢36 kPa£¬´úÈëKp£½£½(kPa)2¡£
(3)³£ÎÂÏ£¬²ÝËáÈÜÒºÓëNaOHÈÜÒº»ìºÏ£¬ËùµÃ»ìºÏÈÜÒºÖÐÈÔ´æÔÚ·Ö²½µçÀ룺
H2C2O4H++HC2O4£ Ka1£½
HC2O4£H++C2O42£ Ka2£½
µ±Ê±£¬Ka1¡¤Ka2£½¡££½£½6¡Á10£3.5 mol/L£¬pH£½2.7¡£
¡¾ÌâÄ¿¡¿Ï±íÊÇÖÜÆÚ±íÖеÄÒ»²¿·Ö£¬¸ù¾Ý¢Ù--¢âÔÚÖÜÆÚ±íÖеÄλÖã¬ÓÃÔªËØ·ûºÅ»ò»¯Ñ§Ê½»Ø´ðÏÂÁÐÎÊÌ⣺
×åÖÜÆÚ | ¢ñA | ¢òA | ¢óA | ¢ôA | ¢õA | ¢öA | ¢÷A | 0 |
1 | ¢Ù | |||||||
2 | ¢Ü | ¢ß | ¢à | ¢â | ||||
3 | ¢Ú | ¢Û | ¢Ý | ¢Þ | ¢á |
£¨1£©±íÖÐÔªËØ£¬»¯Ñ§ÐÔÖÊ×î²»»îÆõÄÊÇ______£¬»¹ÔÐÔ×îÇ¿µÄµ¥ÖÊÊÇ______£¬¿ÉÓÃÓÚÖÆ°ëµ¼Ìå²ÄÁϵÄÔªËØÊÇ______£»
£¨2£©ÔÚ¢Ú¡¢¢Û¡¢¢Ü¡¢¢Ý¡¢¢Þ¡¢¢ß¡¢¢à¡¢¢áÖУ¬Ô×Ӱ뾶×î´óµÄÊÇ______£»
£¨3£©±È½Ï¢Þ¡¢¢ß¡¢¢áµÄÇ⻯ÎïµÄÎȶ¨ÐÔ×îÈõµÄÊÇ______£»
£¨4£©îëλÓÚÔªËØÖÜÆÚ±íÖеڶþÖÜÆÚµÚ¢òA×å¡£ÏàͬÌõ¼þÏ£¬µ¥ÖÊîëÓëËá·´Ó¦±Èµ¥ÖÊï®ÓëËá·´Ó¦¸ü¼Ó______£¨Ìî¡°¾çÁÒ¡±»ò¡°»ºÂý¡±£©£¬Ð´³öîëÓëÑÎËá·´Ó¦µÄ»¯Ñ§·½³Ìʽ__________¡£