ÌâÄ¿ÄÚÈÝ

ÒÑÖªÓлúÎïA¡¢B¡¢C¡¢D¡¢E¡¢F¡¢GÓÐÈçÏÂת»¯¹Øϵ,ÆäÖÐCµÄ²úÁ¿¿ÉÓÃÀ´ºâÁ¿Ò»¸ö¹ú¼ÒµÄʯÓÍ»¯¹¤·¢Õ¹Ë®Æ½,GµÄ·Ö×ÓʽΪC9H10O2,ÊԻشðÏÂÁÐÓйØÎÊÌâ¡£

(1)GµÄ½á¹¹¼òʽΪ¡¡¡¡¡¡¡¡¡¡¡£ 
(2)Ö¸³öÏÂÁз´Ó¦µÄ·´Ó¦ÀàÐÍ:Aת»¯ÎªB:¡¡¡¡¡¡,Cת»¯ÎªD:¡¡¡¡¡¡¡¡¡¡¡£ 
(3)д³öÏÂÁз´Ó¦µÄ»¯Ñ§·½³Ìʽ:
DÉú³ÉEµÄ»¯Ñ§·½³Ìʽ:¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£ 
BÓëFÉú³ÉGµÄ»¯Ñ§·½³Ìʽ:¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£ 
(4)·ûºÏÏÂÁÐÌõ¼þµÄGµÄͬ·ÖÒì¹¹ÌåÓС¡¡¡ÖÖ:¢Ù±½»·ÉÏÓÐ3¸öÈ¡´ú»ù,ÇÒÓÐÁ½¸öÈ¡´ú»ùÏàͬ;¢ÚÄܹ»ÓëÐÂÖƵÄÒø°±ÈÜÒº·´Ó¦²úÉúÒø¾µ¡£ÆäÖÐÇâÔ­×Ó¹²ÓÐËÄÖÖ²»Í¬»·¾³µÄËùÓÐÎïÖʵĽṹ¼òʽΪ¡¡¡¡¡¡¡¡¡¡¡¢¡¡¡¡¡¡¡¡¡¡¡¡¡£ 

(1)
(2)È¡´ú·´Ó¦¡¡¼Ó³É·´Ó¦
(3)2CH3CH2OH+O22CH3CHO+2H2O¡¡CH3COOH++H2O
(4)6¡¡¡¡

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

ijѧϰС×éΪ̽¾¿Î¬ÉúËØCµÄ×é³ÉºÍÓйØÐÔÖÊ£¬½øÐÐÁËÒÔÏÂʵÑ飺
¢ÙȡάÉúËØCÑùÆ·ÑÐË飬£®³ÆÈ¡¸ÃÊÔÑù0.704 g£¬ÖÃÓÚ²¬ÖÛ²¢·ÅÈËȼÉÕ¹ÜÖУ¬²»¶ÏͨÈëÑõÆøÁ÷¡£Óþƾ«ÅçµÆ³ÖÐø¼ÓÈÈÑùÆ·£¬ÑùÆ·Öð½¥Ïûʧ×îºóÎÞÈκβÐÁôÎ½«Éú³ÉÎï(½öÓÐÁ½ÖÖÎïÖÊ)ÏȺóͨ¹ýÎÞË®ÁòËáÍ­ºÍ¼îʯ»Ò£¬Á½Õß·Ö±ðÔöÖØ0.288 gºÍ1.056 g£¬Éú³ÉÎïÍêÈ«±»ÎüÊÕ¡£
¢Ú½«ÉÙÐíÑÐËéµÄάÉúËØCÑùÆ·ºÍÊÊÁ¿µÄ×ÏɫʯÈïÊÔÒº³ä·Ö»ìºÏºó£¬ÈÜÒºÑÕÉ«±äºì¡£
Çë½â´ðÏÂÁÐÎÊÌ⣺
£¨1£©³ÆÈ¡µÄÊÔÑùÖУ¬º¬ÓÐÇâÔ­×ÓµÄÎïÖʵÄÁ¿ÊÇ          mo1£»Ì¼ÔªËصÄÖÊ×îÊÇ          g¡£
£¨2£©Î¬ÉúËØCÖР     (Ìî¡°º¬¡±¡¢¡°²»º¬¡±»ò¡°ÎÞ·¨È·¶¨ÊÇ·ñ¡±)ÓÐÑõÔªËØ£¬ÀíÓÉÊǸù¾ÝʵÑéÊý¾Ý¿ÉÖª                                                      ¡£
ÈçÄã»Ø´ð¡°º¬¡±ÓУ¬Çë¼ÆËã³ÆÈ¡µÄÊÔÑùÖÐÑõÔ­×ÓµÄÎïÖʵÄÁ¿²¢ÌîÈëÏÂÒ»¿Õ¸ñÖУ»ÈçÄã»Ø´ð¡°²»º¬¡±µÈ£¬ÔòÏÂÒ»¿Õ¸ñ²»±ØÌîд¡£³ÆÈ¡ÊÔÑùÖÐÑõÔ­×ÓµÄÎïÖʵÄÁ¿Îª           mol¡£
£¨3£©Èç¹ûҪȷ¶¨Î¬ÉúËØCµÄ·Ö×Óʽ£¬ÄãÈÏΪ»¹ÐèÒªÖªµÀµÄÐÅÏ¢ÊÇ                          ¡£
£¨4£©Î¬ÉúËØCºÍ×ÏɫʯÈïÊÔÒº»ìºÏºó£¬ÈÜÒºÑÕÉ«±äºì£¬ËµÃ÷άÉúËØCÈÜÒº¾ßÓР       (Ìî¡°Ëᡱ¡¢¡°¼î¡±»ò¡°ÖС±)ÐÔ¡£²éÔÄÓйØ×ÊÁÏÏÔʾ£¬Î¬ÉúËØC¾ßÓл¹Ô­ÐÔ¡£ÇëÒÔµí·ÛÈÜÒº¡¢µâˮΪÊÔ¼Á£¬Ð´³öÑé֤άÉúËØC¾ßÓл¹Ô­ÐÔµÄʵÑé·½·¨ºÍÏÖÏ󣺠                                                    ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø