ÌâÄ¿ÄÚÈÝ

ϱíÊÇÔªËØÖÜÆÚµÄÒ»²¿·Ö£¬ÆäÖÐËùÁÐ×Öĸ·Ö±ð´ú±íijһԪËØ¡£

a

b

e

c

d

f

g

h

j

Çë¸ù¾Ý±íÖÐËùÁÐÔªËØ£¬»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©»ù̬ԭ×ӵļ۵ç×Ó²ãÖУ¬Î´³É¶Ôµç×ÓÊý×î¶àµÄÔªËØÊÇ         £¨Ìîд±íÖÐ×Öĸ£©£»Ð´³öÆä¼Ûµç×ӵĹìµÀ±íʾʽ                                 £»µ±´ËÔªËصÄÔ­×ÓÓëaÔªËصÄÔ­×ÓÐγɼòµ¥µÄ·Ö×Óʱ£¬¸ÃÔªËصÄÔ­×ÓÒÔsp3ÐÎʽÔÓ»¯£¬ËùÐγɼòµ¥·Ö×ÓµÄÁ¢Ìå¹¹ÐÍΪ         £¬¸Ã·Ö×ÓΪ         ·Ö×Ó£¨Ìî¡°¼«ÐÔ¡±»ò¡°·Ç¼«ÐÔ¡±£©¡£

£¨2£©Ð´³öjÔªËØ»ù̬ԭ×ӵĵç×ÓÅŲ¼Ê½                           £»d¡¢g¡¢j·Ö±ðÓëaÐγɻ¯ºÏÎÍƶÏËùÐγɵĻ¯ºÏÎï·ÐµãÓɸߵ½µÍµÄÅÅÁÐ˳ÐòΪ         £¨Ìѧʽ£©¡£

£¨3£©¿ÉÓÃÀ´×é³ÉËá¡¢¼î¡¢ÑÎÈýÀàÎïÖÊÖÁÉÙÐèÒªµÄÔªËØÓР        £¨Ìîд±íÖÐ×Öĸ£©£»e¡¢fµ¥Öʼ°efºÏ½ðÖÐÓ²¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòΪ                            £¨ÌîдÃû³Æ£©

£¨1£©       c

    Èý½Ç׶ÐΠ     ¼«ÐÔ

£¨2£©Se  1s22s22p63s23p63d104s24p4     H2O>H2Se>H2S

£¨3£©acd    þÂÁºÏ½ð>ÂÁ>þ

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ϱíΪԪËØÖÜÆÚ±íµÄÒ»²¿£¬Çë²ÎÕÕÔªËØ¢Ù-¢âÔÚ±íÖеÄλÖã¬Óû¯Ñ§ÓÃÓï»Ø´ðÏÂÁÐÎÊÌ⣺
×åÖÜÆÚ IA 0
1 ¢Ù ¢òA ¢óA ¢ôA ¢õA ¢öA ¢÷A
2 ¢Ú ¢Û ¢Ü ¢Ý
3 ¢Þ ¢ß ¢à ¢á  ¢â
£¨1£©Çëд³ö¢ÚµÄÔªËØ·ûºÅ
Be
Be

£¨2£©Çëд³ö¢ÛµÄ×î¸ß¼ÛÑõ»¯ÎïµÄµç×Óʽ
£®
£¨3£©±È½Ï¢Ý¡¢¢Þ¡¢¢àµÄÔ­×Ӱ뾶ÓÉ´óµ½Ð¡µÄ˳ÐòΪ£¨ÓÃÔªËØ·ûºÅ±íʾ£©
Na£¾Al£¾F
Na£¾Al£¾F

£¨4£©±È½Ï¢Û¡¢¢Ü¡¢¢áµÄ×î¸ß¼Ûº¬ÑõËáµÄËáÐÔÓÉÇ¿µ½ÈõµÄ˳ÐòÊÇ£¨ÓÃËáµÄ»¯Ñ§Ê½±íʾ£©
HNO3£¾H2CO3£¾H2SiO3£¨»òH4SiO4£©
HNO3£¾H2CO3£¾H2SiO3£¨»òH4SiO4£©
£®
£¨5£©Ð´³öÔÚÔªËØ¢Ù-¢âÖÐ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïµÄ×îÇ¿¼îÓë×îÇ¿º¬ÑõËáÖ®¼äµÄ»¯Ñ§·´Ó¦·½³Ìʽ
NaOH+HClO4¨TNaClO4+H2O
NaOH+HClO4¨TNaClO4+H2O

£¨6£©¢ß¢àÁ½ÔªËØÏà±È½Ï£¬½ðÊôÐÔ½ÏÇ¿µÄÊÇ
þ
þ
£¨ÌîÃû³Æ£©£¬¿ÉÒÔÑéÖ¤¸Ã½áÂÛµÄʵÑéÊÇ
£¨b£©£¨c£©
£¨b£©£¨c£©
£¨Ìî±àºÅ£©£®
£¨a£©½«ÔÚ¿ÕÆøÖзÅÖÃÒѾõÄÕâÁ½ÖÖÔªËصĿé×´µ¥ÖÊ·Ö±ð·ÅÈëÈÈË®ÖÐ
£¨b£©½«ÐÎ×´¡¢´óСÏàͬµÄÕâÁ½ÖÖÔªËصĵ¥ÖÊ·Ö±ðºÍͬŨ¶ÈµÄÑÎËá·´Ó¦
£¨c£©½«ÐÎ×´¡¢´óСÏàͬÕâÁ½ÖÖÔªËصĵ¥ÖÊ·Ö±ðºÍÈÈË®×÷Ó㬲¢µÎÈë·Ó̪ÈÜÒº
£¨d£©±È½ÏÕâÁ½ÖÖÔªËصÄÆø̬Ç⻯ÎïµÄÎȶ¨ÐÔ£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø