ÌâÄ¿ÄÚÈÝ

Æû³µÒѾ­³ÉΪÖØÒªµÄ½»Í¨¹¤¾ß£¬µ«ÆäÅŷŵÄβÆøÊÇ¿ÕÆøµÄÖ÷ÒªÎÛȾÎïÖ®Ò»¡£ÒÑÖªÆû³µÎ²ÆøÖеÄÖ÷ÒªÎÛȾÎïÓУºCmHn(Ìþ)¡¢SO2¡¢NOX¡¢COºÍCµÈ£¬Çë»Ø´ðÏÂÁÐÓйØÎÊÌâ¡£

    (1)ÈôÓÃCmHn±íʾÆûÓ͵ÄÖ÷Òª×é³É£¬CmHnÔÚ¿ÕÆøÖÐÍêȫȼÉյĻ¯Ñ§·½³ÌʽΪ    £¬ÆûÓÍȼÉÕ²úÉúÄÜÁ¿ÎªÆû³µÌṩÁ˶¯Á¦£¬ÕâÒ»¹ý³ÌÖÐÄÜÁ¿µÄת»¯ÊÇÓÉ     ÄÜת»¯Îª      ÄÜ£¬×îÖÕת»¯Îª»úеÄÜ£»

    (2)ͨ¹ý³µÓÃȼÓ͵ľ«Á¶¼Ó¹¤´¦Àí£¬¿É¼õÉÙÆû³µÎ²ÆøÖеĠ     (Ìѧʽ£¬¶àÌî±¾¿Õ²»µÃ·Ö)ÅÅ·Å£»

    (3)Ä¿Ç°Æû³µÎ²Æø¶à²ÉÓô߻¯×ª»¯µÄ·½·¨¼ÓÒÔÖÎÀí£¬Ð´³öÔÚ´ß»¯¼Á×÷ÓÃÏÂNOXÓëCO·´Ó¦µÄ»¯Ñ§·½³Ìʽ                                    ¡£

£¨1£©4CmHn +(4m+n)O2  2nH2O + 4mCO2 £»»¯Ñ§£»ÈÈÄÜ

£¨2£©SO2  £¨3£©2NOx+ 2xCO N2 + 2x CO2


½âÎö:

£¨1£©ÆûÓÍȼÉյĻ¯Ñ§·½³ÌʽΪ£º

4CmHn +(4m+n)O2  2nH2O + 4mCO2 £¬È¼ÉÕ¹ý³ÌΪ»¯Ñ§ÄÜת»¯ÎªÈÈÄÜ¡£

£¨2£©¾«Á¶ÆûÓÍ¿ÉÒÔ¼õÉÙÆäÖÐÁòµÄº¬Á¿´Ó¶ø¼õÉÙ¶þÑõ»¯ÁòµÄÅÅ·Å´ó¡£

£¨3£©ÕâºÍ£¨1£©Ò»Ñù£¬Ò²ÊÇÊôÓÚ¶Ôδ֪Îï·´Ó¦·½³ÌʽµÄÅäƽ£º2NOx+ 2xCO N2 + 2x CO2

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø