ÌâÄ¿ÄÚÈÝ

¡¡¡¡ Æû³µÒѾ­³ÉΪÖØÒªµÄ½»Í¨¹¤¾ß£¬µ«ÆäÅŷŵÄβÆøÊÇ¿ÕÆøµÄÖ÷ÒªÎÛȾÎïÖ®Ò»¡£ÒÑÖªÆû³µÎ²ÆøÖеÄÖ÷ÒªÎÛȾÎïÓУºCmHn(Ìþ)¡¢SO2¡¢NOX¡¢COºÍCµÈ£¬Çë»Ø´ðÏÂÁÐÓйØÎÊÌâ¡£

¡¡ (1)ÈôÓÃCmHn±íʾÆûÓ͵ÄÖ÷Òª×é³É£¬CmHnÔÚ¿ÕÆøÖÐÍêȫȼÉյĻ¯Ñ§·½³ÌʽΪ¡¡ £¬ÆûÓÍȼÉÕ²úÉúÄÜÁ¿ÎªÆû³µÌṩÁ˶¯Á¦£¬ÕâÒ»¹ý³ÌÖÐÄÜÁ¿µÄת»¯ÊÇÓÉ ¡¡¡¡ÄÜת»¯Îª¡¡¡¡ ÄÜ£¬×îÖÕת»¯Îª»úеÄÜ£»

¡¡ (2)ͨ¹ý³µÓÃȼÓ͵ľ«Á¶¼Ó¹¤´¦Àí£¬¿É¼õÉÙÆû³µÎ²ÆøÖеġ¡¡¡ (Ìѧʽ£¬¶àÌî±¾¿Õ²»µÃ·Ö)ÅÅ·Å£»

¡¡ (3)Ä¿Ç°Æû³µÎ²Æø¶à²ÉÓô߻¯×ª»¯µÄ·½·¨¼ÓÒÔÖÎÀí£¬Ð´³öÔÚ´ß»¯¼Á×÷ÓÃÏÂNOXÓëCO·´Ó¦µÄ»¯Ñ§·½³Ìʽ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ ¡£

´ð°¸£¨1£©4CmHn +(4m+n)O2  2nH2O + 4mCO2 £»»¯Ñ§£»ÈÈÄÜ

£¨2£©SO2  £¨3£©2NOx+ 2xCO N2 + 2x CO2

 ¡¾½âÎö¡¿£¨1£©ÆûÓÍȼÉյĻ¯Ñ§·½³ÌʽΪ£º

4CmHn +(4m+n)O2  2nH2O + 4mCO2 £¬È¼ÉÕ¹ý³ÌΪ»¯Ñ§ÄÜת»¯ÎªÈÈÄÜ¡£

£¨2£©¾«Á¶ÆûÓÍ¿ÉÒÔ¼õÉÙÆäÖÐÁòµÄº¬Á¿´Ó¶ø¼õÉÙ¶þÑõ»¯ÁòµÄÅÅ·Å´ó¡£

£¨3£©ÕâºÍ£¨1£©Ò»Ñù£¬Ò²ÊÇÊôÓÚ¶Ôδ֪Îï·´Ó¦·½³ÌʽµÄÅäƽ£º2NOx+ 2xCO N2 + 2x CO2

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

£¨26·Ö£©
¢ÅÃÞ»¨ÏËάµÄ»¯Ñ§³É·ÖÊÇ               ¡£´ó¶¹Ó͵ÄÖ÷Òª³É·ÖÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡£²ÏË¿ºÍÑòëµÄ»¯Ñ§³É·ÖÊÇ             ¡£ÈçºÎÇø·ÖÃÞÏËάºÍÑòë?                  
¢ÆÒ»¸öÌåÖØ50kgµÄ½¡¿µÈË£¬ÌåÄÚÔ¼º¬ÓÐ2gÌú£¬Õâ2gÌúÔÚÈËÌåÄÚ²»ÊÇÒÔµ¥ÖʵÄÐÎʽ´æÔÚ£¬¶øÊÇÒÔFe2+ºÍFe3+µÄÐÎʽ´æÔÚ¡£Õý¶þ¼ÛÌúÀë×ÓÒ×±»ÎüÊÕ£¬¸øƶѪÕß²¹³äÌúʱ£¬Ó¦¸øÓ躬Fe2+µÄÑÇÌúÑΣ¬ÈçÁòËáÑÇÌú¡£·þÓÃάÉúËØC£¬¿ÉʹʳÎïÖеÄFe3+»¹Ô­³ÉFe2+£¬ÓÐÀûÓÚÈËÌåÎüÊÕ¡£
1) ÔÚÈËÌåÖнøÐеÄת»¯Ê±£¬¢ÙÖеÄFe2+×÷           ¼Á£»¢ÚÖеÄFe3+×÷                    ¼Á
2) ¡°·þÓÃάÉúËØC£¬¿ÉʹʳÎïÖеÄFe3+ »¹Ô­³ÉFe2+¡±Õâ¾ä»°Ö¸³ö£¬Î¬ÉúËØCÔÚÕâÒ»·´Ó¦ÖÐ×÷       ¼Á£¬¾ßÓР                  ÐÔ£»
3) Êг¡³öÊÛµÄijÖÖÂóƬÖк¬ÓÐ΢Á¿µÄ¿ÅÁ£Ï¸Ð¡µÄ»¹Ô­Ìú·Û£¬ÕâЩÌú·ÛÔÚÈËÌåθËáµÄ×÷ÓÃÏÂת»¯³ÉÑÇÌúÑΡ£´Ë·´Ó¦µÄÀë×Ó·½³ÌʽΪ                                                           ¡£
¢ÇÆû³µÒѾ­³ÉΪÖØÒªµÄ½»Í¨¹¤¾ß£¬µ«ÆäÅŷŵÄβÆøÊÇ¿ÕÆøµÄÖ÷ÒªÎÛȾÎïÖ®Ò»¡£ÒÑÖªÆû³µÎ²ÆøÖеÄÖ÷ÒªÎÛȾÎïÓУºCmHn(Ìþ)¡¢SO2¡¢NOX¡¢COºÍCµÈ£¬Çë»Ø´ðÏÂÁÐÓйØÎÊÌâ¡£
1)ÈôÓÃCmHn±íʾÆûÓ͵ÄÖ÷Òª×é³É£¬CmHnÔÚ¿ÕÆøÖÐÍêȫȼÉյĻ¯Ñ§·½³ÌʽΪ                £¬ÆûÓÍȼÉÕ²úÉúÄÜÁ¿ÎªÆû³µÌṩÁ˶¯Á¦£¬ÕâÒ»¹ý³ÌÖÐÄÜÁ¿µÄת»¯ÊÇÓÉ    ÄÜת»¯ÎªÈÈÄÜ£¬×îÖÕת»¯Îª»úеÄÜ£»
2)ͨ¹ý³µÓÃȼÓ͵ľ«Á¶¼Ó¹¤´¦Àí£¬¿É¼õÉÙÆû³µÎ²ÆøÖеĠ      (Ìѧʽ£¬¶àÌî±¾¿Õ²»µÃ·Ö)ÅÅ·Å£»
3)Ä¿Ç°Æû³µÎ²Æø¶à²ÉÓô߻¯×ª»¯µÄ·½·¨¼ÓÒÔÖÎÀí£¬Ð´³öÔÚ´ß»¯¼Á×÷ÓÃÏÂNOXÓëCO·´Ó¦µÄ»¯Ñ§·½³Ìʽ                                                ¡£

¢ÅÃÞ»¨ÏËάµÄ»¯Ñ§³É·ÖÊÇ                ¡£´ó¶¹Ó͵ÄÖ÷Òª³É·ÖÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡£²ÏË¿ºÍÑòëµÄ»¯Ñ§³É·ÖÊÇ              ¡£ÈçºÎÇø·ÖÃÞÏËάºÍÑòë?                  

¢ÆÒ»¸öÌåÖØ50kgµÄ½¡¿µÈË£¬ÌåÄÚÔ¼º¬ÓÐ2gÌú£¬Õâ2gÌúÔÚÈËÌåÄÚ²»ÊÇÒÔµ¥ÖʵÄÐÎʽ´æÔÚ£¬¶øÊÇÒÔFe2+ ºÍFe3+µÄÐÎʽ´æÔÚ¡£Õý¶þ¼ÛÌúÀë×ÓÒ×±»ÎüÊÕ£¬¸øƶѪÕß²¹³äÌúʱ£¬Ó¦¸øÓ躬Fe2+µÄÑÇÌúÑΣ¬ÈçÁòËáÑÇÌú¡£·þÓÃάÉúËØC£¬¿ÉʹʳÎïÖеÄFe3+»¹Ô­³ÉFe2+£¬ÓÐÀûÓÚÈËÌåÎüÊÕ¡£

1) ÔÚÈËÌåÖнøÐеÄת»¯Ê±£¬¢ÙÖеÄFe2+×÷          ¼Á£»¢ÚÖеÄFe3+×÷                     ¼Á

2) ¡°·þÓÃάÉúËØC£¬¿ÉʹʳÎïÖеÄFe3+ »¹Ô­³ÉFe2+¡±Õâ¾ä»°Ö¸³ö£¬Î¬ÉúËØCÔÚÕâÒ»·´Ó¦ÖÐ×÷       ¼Á£¬¾ßÓР                    ÐÔ£»

3) Êг¡³öÊÛµÄijÖÖÂóƬÖк¬ÓÐ΢Á¿µÄ¿ÅÁ£Ï¸Ð¡µÄ»¹Ô­Ìú·Û£¬ÕâЩÌú·ÛÔÚÈËÌåθËáµÄ×÷ÓÃÏÂת»¯³ÉÑÇÌúÑΡ£´Ë·´Ó¦µÄÀë×Ó·½³ÌʽΪ                                                            ¡£

¢ÇÆû³µÒѾ­³ÉΪÖØÒªµÄ½»Í¨¹¤¾ß£¬µ«ÆäÅŷŵÄβÆøÊÇ¿ÕÆøµÄÖ÷ÒªÎÛȾÎïÖ®Ò»¡£ÒÑÖªÆû³µÎ²ÆøÖеÄÖ÷ÒªÎÛȾÎïÓУºCmHn(Ìþ)¡¢SO2¡¢NOX¡¢COºÍCµÈ£¬Çë»Ø´ðÏÂÁÐÓйØÎÊÌâ¡£

1)ÈôÓÃCmHn±íʾÆûÓ͵ÄÖ÷Òª×é³É£¬CmHnÔÚ¿ÕÆøÖÐÍêȫȼÉյĻ¯Ñ§·½³ÌʽΪ                 £¬ÆûÓÍȼÉÕ²úÉúÄÜÁ¿ÎªÆû³µÌṩÁ˶¯Á¦£¬ÕâÒ»¹ý³ÌÖÐÄÜÁ¿µÄת»¯ÊÇÓÉ     ÄÜת»¯ÎªÈÈÄÜ£¬×îÖÕת»¯Îª»úеÄÜ£»

2)ͨ¹ý³µÓÃȼÓ͵ľ«Á¶¼Ó¹¤´¦Àí£¬¿É¼õÉÙÆû³µÎ²ÆøÖеĠ       (Ìѧʽ£¬¶àÌî±¾¿Õ²»µÃ·Ö)ÅÅ·Å£»

3)Ä¿Ç°Æû³µÎ²Æø¶à²ÉÓô߻¯×ª»¯µÄ·½·¨¼ÓÒÔÖÎÀí£¬Ð´³öÔÚ´ß»¯¼Á×÷ÓÃÏÂNOXÓëCO·´Ó¦µÄ»¯Ñ§·½³Ìʽ                                                 ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø