ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÂÈ¡¢µª¡¢ÁòµÄ»¯ºÏÎïÓëÈËÀàÉú»îºÍÉú²úÓÐ×ÅÃÜÇеÄÁªÏµ¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Èðµä»¯Ñ§¼ÒÉáÀÕ½«ÈíÃÌ¿ó£¨Ö÷Òª³É·ÖÊÇMnO2£©ÓëŨÑÎËá»ìºÏ¼ÓÈÈ£¬ÔÚÊÀ½çÉÏÊ×ÏÈÖƵÃÁËÂÈÆø¡£·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º_________________________¡£ÆäÖУ¬Ñõ»¯¼ÁÊÇ_______¡£ÈôʵÑéÊÒÖƵñê×¼×´¿öÏÂ4.48LÂÈÆø£¬ÔòתÒƵç×ÓµÄÊýĿΪ_____¸ö¡£
£¨2£©ÔÚµªµÄ»¯ºÏÎïÖУ¬ºì×ØÉ«¡¢Óд̼¤ÐÔÆøζµÄÓж¾ÆøÌåÊÇ___________£¨Ìîд»¯Ñ§Ê½£©£¬Çëд³ö¸ÃÆøÌåÓëË®·´Ó¦µÄ»¯Ñ§·½³Ìʽ________________________¡£
£¨3£©ÇëÅäƽŨÁòËáÔÚ¼ÓÈÈʱÓë̼·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º____C+____H2SO4(Ũ)=__CO2¡ü+_____SO2¡ü+____H2O¡£
Ôڸ÷´Ó¦ÖУ¬Å¨H2SO4±íÏÖ³ö___________(Ìî¡°ÎüË®¡±¡¢¡°ÍÑË®¡±»ò¡°Ñõ»¯¡±)ÐÔ¡£
¡¾´ð°¸¡¿ MnO2+4HCl(Ũ)MnCl2+Cl2¡ü+2H2O MnO2»ò¶þÑõ»¯ÃÌ 0.4NA »ò2.408¡Á1023 NO2 3NO2 + H2O=2HNO3 + NO _1__C+___2_H2SO4(Ũ) __1__ CO2¡ü+__2___SO2¡ü+__2__H2O Ñõ»¯
¡¾½âÎö¡¿£¨1£©MnO2ÓëŨÑÎËá»ìºÏ¹²ÈÈÉú³ÉMnCl2¡¢Cl2ºÍH2O¡£¶Ô±ÈÑõ»¯»¹Ô·´Ó¦ÖиÅÄîºÍ¼ÆËã×÷´ð¡£
£¨2£©ÔÚµªµÄ»¯ºÏÎïÖУ¬ºì×ØÉ«¡¢Óд̼¤ÐÔÆøζµÄÓж¾ÆøÌåÊÇNO2¡£NO2ÓëH2O·´Ó¦Éú³ÉHNO3ºÍNO¡£
£¨3£©Óû¯ºÏ¼ÛÉý½µ·¨Åäƽ£¬¸ù¾Ý·½³Ìʽ·ÖÎöŨÁòËáµÄÐÔÖÊ¡£
£¨1£©MnO2ÓëŨÑÎËá»ìºÏ¹²ÈÈÉú³ÉMnCl2¡¢Cl2ºÍH2O£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪMnO2+4HClMnCl2+Cl2¡ü+2H2O¡£Ôڸ÷´Ó¦ÖÐMnÔªËصĻ¯ºÏ¼ÛÓÉ+4¼Û½µÎª+2¼Û£¬Ñõ»¯¼ÁÊÇMnO2¡£ClÔªËصĻ¯ºÏ¼ÛÓÉ-1¼ÛÉýÖÁ0¼Û£¬Ã¿Éú³É1molCl2תÒÆ2molµç×Ó£¬n£¨Cl2£©==0.2mol£¬ÊµÑéÊÒÖƵñê×¼×´¿öÏÂ4.48LCl2תÒƵç×ÓÎïÖʵÄÁ¿Îª0.2mol2=0.4mol£¬×ªÒƵç×ÓÊýΪ0.4NA»ò0.46.021023=2.4081023¡£
£¨2£©ÔÚµªµÄ»¯ºÏÎïÖУ¬ºì×ØÉ«¡¢Óд̼¤ÐÔÆøζµÄÓж¾ÆøÌåÊÇNO2¡£NO2ÓëH2O·´Ó¦Éú³ÉHNO3ºÍNO£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ3NO2+H2O=2HNO3+NO¡£
£¨3£©·´Ó¦ÖÐCÔªËصĻ¯ºÏ¼ÛÓÉ0¼ÛÉýÖÁ+4¼Û£¬1molCʧȥ4molµç×ÓÉú³É1molCO2£»SÔªËصĻ¯ºÏ¼ÛÓÉ+6¼Û½µÖÁ+4¼Û£¬1molH2SO4£¨Å¨£©µÃµ½2molµç×ÓÉú³É1molSO2£»¸ù¾ÝµÃʧµç×ÓÊغ㡢Ô×ÓÊغ㣬ÅäƽµÄ·½³ÌʽΪ1C+2H2SO4£¨Å¨£©1CO2¡ü+2SO2¡ü+2H2O¡£Ôڸ÷´Ó¦ÖÐËùÓÐ+6¼ÛµÄSÈ«±»»¹ÔΪ+4¼Û£¬Å¨H2SO4±íÏÖÑõ»¯ÐÔ¡£
¡¾ÌâÄ¿¡¿¶þÂÈ»¯¶þÁò(S2Cl2)ÊÇÒ»ÖÖÖØÒªµÄ»¯¹¤ÔÁÏ,³£ÓÃ×÷Ïð½ºÁò»¯¼Á,¸Ä±äÉúÏð½ºÊÜÈÈ·¢Õ³¡¢ÓöÀä±äÓ²µÄÐÔÖÊ¡£²éÔÄ×ÊÁÏ¿ÉÖªS2Cl2¾ßÓÐÏÂÁÐÐÔÖÊ:
ÎïÀíÐÔÖÊ | ¶¾ÐÔ | ɫ̬ | »Ó·¢ÐÔ | ÈÛµã | ·Ðµã |
¾ç¶¾ | ½ð»ÆÉ«ÒºÌå | Ò×»Ó·¢ | -76¡æ | 138¡æ | |
»¯Ñ§ÐÔÖÊ | ¢Ù300 ¡æÒÔÉÏÍêÈ«·Ö½â ¢ÚS2Cl2£«Cl22SCl2 ¢ÛÓö¸ßÈÈ»òÓëÃ÷»ð½Ó´¥,ÓÐÒýÆðȼÉÕµÄΣÏÕ ¢ÜÊÜÈÈ»òÓöË®·Ö½â·ÅÈÈ,·Å³ö¸¯Ê´ÐÔÑÌÆø |
(1)ÖÆÈ¡ÉÙÁ¿S2Cl2
ʵÑéÊÒ¿ÉÀûÓÃÁòÓëÉÙÁ¿ÂÈÆøÔÚ110~140¡æ·´Ó¦ÖƵÃS2Cl2´ÖÆ·£¬ÂÈÆø¹ýÁ¿Ôò»áÉú³ÉSCl2¡£
¢ÙÒÇÆ÷m µÄÃû³ÆΪ__________,×°ÖÃF ÖÐÊÔ¼ÁµÄ×÷ÓÃÊÇ_________¡£
¢Ú×°ÖÃÁ¬½Ó˳Ðò: A______ ED¡£
¢ÛʵÑéÇ°´ò¿ªK1,ͨÈëÒ»¶Îʱ¼äµÄµªÆøÅž¡×°ÖÃÄÚ¿ÕÆø¡£ÊµÑé½áÊøÍ£Ö¹¼ÓÈȺó£¬ÔÙͨÈëÒ»¶Îʱ¼äµÄµªÆø,ÆäÄ¿µÄÊÇ_____________¡£
¢ÜΪÁËÌá¸ßS2Cl2µÄ´¿¶È,ʵÑéµÄ¹Ø¼üÊÇ¿ØÖƺÃζȺÍ____________¡£
(2)ÉÙÁ¿S2Cl2й©ʱӦÅçË®Îí¼õÂýÆä»Ó·¢(»òÀ©É¢),²¢²úÉúËáÐÔÐü×ÇÒº,µ«²»Òª¶Ôй©Îï»òй©µãÖ±½ÓÅçË®,ÆäÔÒòÊÇ______________¡£
(3)S2Cl2ÓöË®»áÉú³ÉSO2¡¢HClÁ½ÖÖÆøÌå,ijͬѧÉè¼ÆÁËÈçÏÂʵÑé·½°¸À´²â¶¨¸Ã»ìºÏÆøÌåÖÐSO2µÄÌå»ý·ÖÊý¡£
¢ÙWÈÜÒº¿ÉÒÔÊÇ_____(Ìî±êºÅ)¡£
a.H2O2ÈÜÒº b.KMnO4ÈÜÒº(ÁòËáËữ) c.ÂÈË®
¢Ú¸Ã»ìºÏÆøÌåÖжþÑõ»¯ÁòµÄÌå»ý·ÖÊýΪ_________(Óú¬V¡¢m µÄʽ×Ó±íʾ)¡£
¡¾ÌâÄ¿¡¿¢ñ.ÓÉA¡¢B¡¢C¡¢DËÄÖÖ½ðÊô°´Ï±íÖÐ×°ÖýøÐÐʵÑé¡£
×°ÖÃ | |||
ÏÖÏó | ¶þ¼Û½ðÊôA²»¶ÏÈܽâ | CµÄÖÊÁ¿Ôö¼Ó | AÉÏÓÐÆøÌå²úÉú |
¸ù¾ÝʵÑéÏÖÏó»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©×°Öü×Öиº¼«µÄµç¼«·´Ó¦Ê½ÊÇ_______________£¬×°ÖÃÒÒÖÐÕý¼«µÄµç¼«·´Ó¦Ê½ÊÇ___________¡£
£¨2£©ËÄÖÖ½ðÊô»îÆÃÐÔÓÉÇ¿µ½ÈõµÄ˳ÐòÊÇ_____________________________________¡£
¢ò.ÃÀ¹ú°¢²¨ÂÞÓîÖæ·É´¬ÉÏʹÓÃÁËÒ»ÖÖÐÂÐÍ·¢µç×°ÖáªÇâÑõȼÁϵç³Ø£¬Æä¹¹ÔìÈçͼËùʾ£¬ÆäÖÐa¡¢bÁ½¸öµç¼«¾ùÓɶà¿×µÄ̼Ȳ×é³É£¬¸Ãµç³ØµÄ¸º¼«·´Ó¦Ê½Îª_________________£¬Èô¸Ãµç³Ø¹¤×÷ʱÈÜÒºÖÐÔö¼Ó1molH2O£¬ÔòÀíÂÛÉϵç·ÖÐͨ¹ýµç×ÓµÄÎïÖʵÄÁ¿Îª________mol¡£