ÌâÄ¿ÄÚÈÝ

°´ÕÕÌâÄ¿ÒªÇó×÷ͼ

£¨1£©¸ù¾ÝƽÃæ¾µ³ÉÏñÌص㣬»­³öͼ¼×ÖÐÎïÌåABÔÚƽÃæ¾µÖÐËù³ÉµÄÏñ¡£
£¨2£©´«ËÍ´øÉÏÓÐÒ»¸öÎïÌåM£¬ÖÊÁ¿Îª2kg£¬ËüÓë´«ËÍ´øÒ»ÆðÒÔ0.5m/sµÄËÙ¶ÈÔÚˮƽ·½ÏòÏòÓÒÔÈËÙÔ˶¯£¬²»¼Æ¿ÕÆø×èÁ¦¡£ÇëÔÚͼÒÒÖл­³öMÊÜÁ¦Ê¾Òâͼ¡£
£¨3£©³¬ÊÐÀïµÄµçÌÝ£¬ÓÐÈ˳ËʱÔËÐнϿ죬ÎÞÈ˳ËʱΪÁ˽ÚÄÜÔËÐнÏÂý¡£ÀûÓõç´Å¼ÌµçÆ÷¿ÉÒÔÉè¼ÆÕâÑùµÄµç·£¬Çë°´ÕÕÒªÇóÓñʻ­Ïß´úÌæµ¼Ïß½«Í¼±ûÖеĿØÖƵ緺͹¤×÷µç·Á¬½ÓÍêÕû¡£ÆäÖÐR1ÊÇѹÃôµç×裨Êܵ½Ñ¹Á¦Ê±×èÖµ½ÏС£¬²»ÊÜѹÁ¦Ê±×èÖµºÜ´ó£©£¬R2ÊÇÏÞÁ÷µç×裨´®ÁªÔÚµç·ÖпɼõСµç·ÖеĵçÁ÷£©¡£

£¨1£©·Ö±ð×÷³öÎïÌåAB¶ËµãA¡¢B¹ØÓÚƽÃæ¾µµÄ¶Ô³ÆµãA¡ä¡¢B¡ä£¬ÓÃÐéÏßÁ¬½ÓA¡ä¡¢B¡ä¼´ÎªABÔÚƽÃæ¾µÖеÄÏñ£®Èçͼ¼×£º
£¨2£©ÓÉÓÚÎïÌåMºÍ´«ËÍ´øÒ»ÆðÔÈËÙÔ˶¯£¬Ïà¶Ô¾²Ö¹£¬ËùÒÔM²»ÊÜĦ²ÁÁ¦µÄ×÷Óã¬Ö»ÊÜÖØÁ¦ºÍÖ§³ÖÁ¦µÄ×÷Óã»G=mg=2kg¡Á9.8N/kg=19.6N£®
ÈçͼÒÒËùʾ£º
£¨3£©½«µç¶¯»úºÍÏ´¥µã´®Áª×é³É¹¤×÷µç·£¬½«R1ºÍµç´ÅÌú´®Á¬½ÓÈë¿ØÖƵç·£»µç·Èçͼ±ûËùʾ£»
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø