题目内容
分析:由电路图可知,电阻是串联的,根据串联电路特点及欧姆定律分析答题.
解答:解:电阻R1、R2和R3的阻值之比为1:2:3,
设R1=R,则R2=2R,R3=3R,
开关闭合时,I=
=
=
,
电阻串联,电流相等,
=
=
,
开关断开时,I′=
=
=
=
,
则I:I′=2:1;
两电阻串联,电流相等,
=
=
;
故选ABC.
设R1=R,则R2=2R,R3=3R,
开关闭合时,I=
| U |
| R1+R2 |
| U |
| R+2R |
| U |
| 3R |
电阻串联,电流相等,
| U1 |
| U2 |
| IR1 |
| IR2 |
| 1 |
| 2 |
开关断开时,I′=
| U |
| R1+R2+R3 |
| U |
| R+2R+3R |
| U |
| 6R |
| I |
| 2 |
则I:I′=2:1;
两电阻串联,电流相等,
| U1′ |
| U3′ |
| I′R1 |
| I′R3 |
| 1 |
| 3 |
故选ABC.
点评:本题考查了电压之比、电流之比,应用串联电路特点、欧姆定律即可正确解题.
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