ÌâÄ¿ÄÚÈÝ

СÃ÷²âÁ¿Ö²ÎïÓÍÃܶÈʱ£¬°´ÏÂÁÐ˳Ðò½øÐÐÁ˲Ù×÷£º
¢ÙÓÃÌìƽ²â³ö¿ÕÉÕ±­µÄÖÊÁ¿m1£»
¢ÚÏòÉÕ±­Öе¹ÈëÊÊÁ¿Ö²ÎïÓÍ£¬²â³öÉÕ±­ÓëÖ²ÎïÓ͵Ä×ÜÖÊÁ¿m2£»
¢Û½«ÉÕ±­ÖÐÖ²ÎïÓ͵¹ÈËÁ¿Í²ÖУ¬²â³öÖ²ÎïÓ͵ÄÌå»ýV£»
¢Ü¼ÆËã³öÖ²ÎïÓ͵ÄÃܶȦѣ®

£¨1£©ÈôÔÚ²âÁ¿Ç°£¬µ÷½ÚÌìƽºáÁºÆ½ºâʱ£¬·¢Ï̶ֿÈÅÌÉϵÄÖ¸ÕëÏò×óƫת£¬ÔòÓ¦µ÷½Úµ÷½ÚƽºâÂÝĸ£¬Ê¹ÆäÏò
ÓÒ
ÓÒ
Ðýת£®
£¨2£©Ï±íÊÇСÃ÷¸ù¾ÝÉÏÊöʵÑé²Ù×÷£¬Éè¼ÆµÄ¼Ç¼Êý¾Ý±í¸ñ£®Çë¸ù¾Ýͼ½«±í¸ñÖеÄÊý¾ÝÌîдÍêÕû£®
ÎïÀíÁ¿ ¿ÕÉÕ±­µÄÖÊÁ¿m1/g ÉÕ±­ÓëÖ²ÎïÓ͵Ä×ÜÖÊÁ¿m2/g Ö²ÎïÓ͵ÄÌå»ý
V/cm3
Ö²ÎïÓ͵ÄÃܶȠ ¦Ñ/kg?m-3
²âÁ¿Öµ 15 20
£¨3£©Ð¡Ã÷°´ÉÏÊöʵÑé²Ù×÷µÃµ½µÄÃܶÈÖµ±ÈÕæʵֵ
Æ«´ó
Æ«´ó
£¨Ñ¡¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±»ò¡°²»±ä¡±£©
·ÖÎö£º£¨1£©Ììƽµ÷ƽºâʱ×ñÑ­µÄÔ­ÔòÊÇ£º×óÆ«ÓÒµ÷£¬ÓÒÆ«×óµ÷£¬ÏÈ¿ìºóÂý£®
£¨2£©¸ù¾ÝÌâÖÐͼʾ£¬¶Á³ö×ÜÖÊÁ¿£¬¼õÈ¥¿ÕÉÕ±­µÄÖÊÁ¿¼´ÎªÖ²ÎïÓ͵ÄÖÊÁ¿£¬¸ù¾Ý¹«Ê½¦Ñ=
m
V
Çó³öÃܶȣ»
£¨3£©ÔÚ²âÁ¿Ö²ÎïÓ͵ÄÌå»ýʱ£¬Êǽ«ÉÕ±­ÖеÄʳÓÃÓÍÈ«²¿µ¹ÈëÁ¿Í²ÖУ¬Èôµ¹²»¸É¾»£¬Ê³ÓÃÓ͵ÄÌå»ýƫС£¬¸ù¾ÝÃܶȵļÆË㹫ʽ£¬ÃܶȾÍÆ«´óÁË£®
½â´ð£º½â£º£¨1£©¿Ì¶ÈÅÌÉϵÄÖ¸ÕëÏò×óƫת£¬ºáÁºµÄ×ó¶ËϳÁ£¬Æ½ºâÂÝĸÏòÏà·´µÄ·½ÏòÒƶ¯£¬¼´ÏòÓÒµ÷½ÚƽºâÂÝĸ£¬Ê¹ÌìƽµÄºáÁºÆ½ºâ£»
£¨2£©ÉÕ±­ÓëÖ²ÎïÓ͵Ä×ÜÖÊÁ¿m2=20g+10g+3.4g=33.4g£¬
Ö²ÎïÓ͵ÄÖÊÁ¿£ºm=m2-m1=33.4g-15g=18.4g£¬
Ö²ÎïÓ͵ÄÃܶȣº¦Ñ=
m
V
=
18.4g
20cm3
=0.92g/cm3=0.92¡Á103kg/m3£»
£¨3£©Ð¡Ã÷°´ÉÏÊöʵÑé²Ù×÷ʱ£¬Ê³ÓÃÓ͵ÄÌå»ýƫС£¬¸ù¾ÝÃܶȵļÆË㹫ʽ¦Ñ=
m
V
£¬µÃµ½µÄÃܶÈÖµ±ÈÕæʵֵƫ´ó£®
¹Ê´ð°¸Îª£º£¨1£©ÓÒ£»£¨2£©¼ûÏÂ±í£»£¨3£©Æ«´ó£®
ÎïÀíÁ¿ ¿ÕÉÕ±­µÄÖÊÁ¿m1/g ÉÕ±­ÓëÖ²ÎïÓ͵Ä×ÜÖÊÁ¿m2/g Ö²ÎïÓ͵ÄÌå»ý
V/cm3
Ö²ÎïÓ͵ÄÃܶȠ ¦Ñ/kg?m-3
²âÁ¿Öµ 15 33.4 20 0.92¡Á103kg/m3
µãÆÀ£º±¾ÌâÖ÷ÒªÊÇÌìƽµÄʹÓúͶÁÊýÒÔ¼°ÃܶȼÆË㹫ʽµÄÀí½âºÍÕÆÎÕ£¬Í¬Ê±¿¼²éÁËʵÑéÖÐÎó²îµÄ·ÖÎöÎÊÌ⣬ÎÒÃÇÔÚ×öʵÑéʱҪ¾¡¿ÉÄܵļõСÎó²î£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø