ÌâÄ¿ÄÚÈÝ

´Ó2011Äê5ÔÂ11ÈÕÆð£¬Ö´ÐоƼÝÖØ·£Ð¹涨£®²ÎÕÕ¡¶³µÁ¾¼ÝÊ»ÈËÔ±ºôÆø¾Æ¾«º¬Á¿ãÐÖµÓë¼ìÑé±ê×¼£¨GB19522£©¡·£¬ºôÆøÖоƾ«Å¨¶È´óÓÚµÈÓÚ0.09mg/L¾ÍÊôÓھƺó¼ÝÊ»£®¾©¿ÚÖÐѧ×ÛºÏʵ¼ù»î¶¯Ð¡×éµÄͬѧ¾Í¡°ºôÆøÖоƾ«Å¨¶ÈÊÇ·ñ³¬±ê¡±Õ¹¿ªÌ½¾¿»î¶¯£¬Ð¡×éͬѧͨ¹ý×ÊÁϲéѯ£¬ÖªµÀÑõ»¯Îý¾ßÓÐÆøÃôÌØÐÔ£¬µ±ÖÜΧÆøÌåÖоƾ«Å¨¶ÈÔö¼Ó£¬Æäµç×èÖµ¾Í½µµÍ£®ËûÃǵ½µç×ÓÆ÷²ÄÉ̵깺µÃijÐͺÅÑõ»¯Îý¾Æ¾«ÆøÌå´«¸ÐÆ÷£¬Æä×èÖµRxÓëÖÜΧÆøÌåÖоƾ«Å¨¶ÈµÄ¹ØϵÈçϱíËùʾ£®½»¾¯Ê¹ÓõÄijÐͺžƾ«²âÊÔÒǵŤ×÷Ô­ÀíÈçͼ1Ëùʾ£¬µçÔ´µçѹºãΪ6V£¬R0Ϊ¶¨Öµµç×裬ÔÚ²âÊÔʱµ±¾Æ¾«ÆøÌåµÄŨ¶ÈΪ0.01mg/Lʱ£¬µçѹ±íµÄʾÊýΪ1V£¬Çó£º
£¨1£©¶¨Öµµç×èR0µÄ×èÖµ£»
£¨2£©ÔÚ¼ì²âʱµçѹ±í¶ÁÊý´óÓÚµÈÓÚ¶àÉÙʱ±»¼ì²âÕßÊôÓھƺó¼Ý³µ£¿
£¨3£©¸Ã¾Æ¾«¼ì²âÒDZíÅ̵ÄÁã¿Ì¶ÈÓ¦ÔÚµçѹ±íµÄʲôʾÊýλÖã¬Çë¼ÆËã²¢ÔÚͼ2±íÅÌÉϱê³ö£»
£¨4£©Èôµçѹ±íµÄÁ¿³ÌÊÇ0¡«3V£¬´Ë¾Æ¾«²âÊÔÒÇÄܼì²â³ö¾Æ¾«ÆøÌåµÄŨ¶È×î¶àΪ¶àÉÙ£¿
¾Æ¾«ÆøÌåµÄŨ¶È/mg/L 0 0.01 0.03 0.05 0.07 0.09 0.11 0.13
¾Æ¾«ÆøÌå´«¸ÐÆ÷µç×èRx/¦¸ 36 20 15 11 8 6 4.5 4
·ÖÎö£º£¨1£©Óɱí¸ñÊý¾Ý¿ÉÖª£¬µ±¾Æ¾«ÆøÌåµÄŨ¶ÈΪ0.01mg/Lʱ¾Æ¾«ÆøÌå´«¸ÐÆ÷µÄµç×裬¸ù¾Ý´®Áªµç·µÄµçѹÌصãÇó³ö¾Æ¾«ÆøÌå´«¸ÐÆ÷µç×èÁ½¶ËµÄµçѹ£¬ÀûÓÃÅ·Ä·¶¨Âɺʹ®Áªµç·µÄµçÁ÷ÌصãÇó³öµç·ÖеĵçÁ÷£¬×îºó¸ù¾ÝÅ·Ä·¶¨ÂÉÇó³ö¶¨Öµµç×èR0µÄ×èÖµ£»
£¨2£©Óɱí¸ñÊý¾Ý¿ÉÖª£¬µ±¾Æ¾«ÆøÌåµÄŨ¶ÈΪ0.09mg/Lʱ¾Æ¾«ÆøÌå´«¸ÐÆ÷µÄµç×裬¸ù¾Ýµç×èµÄ´®ÁªºÍÅ·Ä·¶¨ÂÉÇó³öµç·ÖеĵçÁ÷£¬ÔÙ¸ù¾ÝÅ·Ä·¶¨ÂÉÇó³öµçѹ±íµÄʾÊý¼´Îª¾Æ¼ÝʱµÄ×îСʾÊý£»
£¨3£©Óɱí¸ñÊý¾Ý¿ÉÖª£¬µ±¾Æ¾«ÆøÌåµÄŨ¶ÈΪ0mg/Lʱ¾Æ¾«ÆøÌå´«¸ÐÆ÷µÄµç×裬¸ù¾Ý×èµÄ´®ÁªºÍÅ·Ä·¶¨ÂÉÇó³öµç·ÖеĵçÁ÷£¬ÔÙ¸ù¾ÝÅ·Ä·¶¨ÂÉÇó³öµçѹ±íµÄʾÊý¼´ÎªÁã¿Ì¶ÈµÄλÖã»
£¨4£©¸ù¾ÝÅ·Ä·¶¨ÂÉÇó³öµçѹ±íµÄʾÊýΪ3Vʱµç·ÖеĵçÁ÷£¬ÔÙ¸ù¾Ý´®Áªµç·µÄµçѹÌصãÇó³ö¾Æ¾«ÆøÌå´«¸ÐÆ÷µç×èÁ½¶ËµÄµçѹ£¬ÀûÓÃÅ·Ä·¶¨ÂÉÇó³ö¾Æ¾«ÆøÌå´«¸ÐÆ÷µç×èµÄ×èÖµ£¬Óɱí¸ñ¶Á³ö´Ë¾Æ¾«²âÊÔÒÇÄܼì²â³ö¾Æ¾«ÆøÌåµÄ×î´óŨ¶È£®
½â´ð£º½â£º£¨1£©Óɱí¸ñÊý¾Ý¿ÉÖª£¬µ±¾Æ¾«ÆøÌåµÄŨ¶ÈΪ0.01mg/Lʱ¾Æ¾«ÆøÌå´«¸ÐÆ÷µÄµç×èRx=20¦¸£¬
¡ß´®Áªµç·ÖÐ×ܵçѹµÈÓÚ¸÷·Öµçѹ֮ºÍ£¬
¡à¾Æ¾«ÆøÌå´«¸ÐÆ÷µç×èÁ½¶ËµÄµçѹ£º
Ux=U-U0=6V-1V=5V£¬
¡ß´®Áªµç·Öи÷´¦µÄµçÁ÷ÏàµÈ£¬
¡à¸ù¾ÝÅ·Ä·¶¨Âɿɵ㬵ç·ÖеĵçÁ÷£º
I=Ix=
Ux
Rx
=
5V
20¦¸
=0.25A£¬
¶¨Öµµç×èR0µÄ×èÖµ£º
R0=
U0
I
=
1V
0.25A
=4¦¸£»
£¨2£©Óɱí¸ñÊý¾Ý¿ÉÖª£¬µ±¾Æ¾«ÆøÌåµÄŨ¶ÈΪ0.09mg/Lʱ¾Æ¾«ÆøÌå´«¸ÐÆ÷µÄµç×èRx¡ä=6¦¸£¬
¡ß´®Áªµç·ÖÐ×ܵç×èµÈÓÚ¸÷·Öµç×èÖ®ºÍ£¬
¡à´Ëʱµç·ÖеĵçÁ÷£º
I¡ä=
U
R0+R¡äx
=
6V
4¦¸+6¦¸
=0.6A£¬
µçѹ±íµÄʾÊý£º
U0¡ä=I¡äR0=0.6A¡Á4¦¸=2.4V£¬
¼´µçѹ±íµÄʾÊý´óÓÚµÈÓÚ2.4VʱÊôÓھƺó¼Ý³µ£»
£¨3£©Óɱí¸ñÊý¾Ý¿ÉÖª£¬µ±¾Æ¾«ÆøÌåµÄŨ¶ÈΪ0mg/Lʱ¾Æ¾«ÆøÌå´«¸ÐÆ÷µÄµç×èRx¡å=36¦¸£¬
µç·ÖеĵçÁ÷£º
I¡å=
U
R0+R¡åx
=
6V
4¦¸+36¦¸
=0.15A£¬
µçѹ±íµÄʾÊý£º
U0¡å=I¡åR0=0.15A¡Á4¦¸=0.6V£¬
¼´¸Ã¾Æ¾«¼ì²âÒDZíÅ̵ÄÁã¿Ì¶ÈÓ¦ÔÚµçѹ±í0.6VµÄʾÊýλÖã¬ÈçÏÂͼËùʾ£º

£¨4£©µ±µçѹ±íµÄʾÊýΪ3Vʱ£¬´Ë¾Æ¾«²âÊÔÒÇÄܼì²â³ö¾Æ¾«ÆøÌåµÄŨ¶È×î´ó£¬
µç·ÖеĵçÁ÷£º
Imax=
U0max
R0
=
3V
4¦¸
=0.75A£¬
´Ëʱ¾Æ¾«ÆøÌå´«¸ÐÆ÷Á½¶ËµÄµçѹ£º
Uxmin=U-U0max=6V-3V=3V£¬
¾Æ¾«ÆøÌå´«¸ÐÆ÷µÄµç×裺
Rxmin=
Uxmin
Imax
=
3V
0.75A
=4¦¸£¬
Óɱí¸ñ¿ÉÖª£¬´Ë¾Æ¾«²âÊÔÒÇÄܼì²â³ö¾Æ¾«ÆøÌåµÄŨ¶È×î¶àΪ0.13mg/L£®
´ð£º£¨1£©¶¨Öµµç×èR0µÄ×èֵΪ4¦¸£»
£¨2£©ÔÚ¼ì²âʱµçѹ±í¶ÁÊý´óÓÚµÈÓÚ2.4Vʱ±»¼ì²âÕßÊôÓھƺó¼Ý³µ£»
£¨3£©¸Ã¾Æ¾«¼ì²âÒDZíÅ̵ÄÁã¿Ì¶ÈÓ¦ÔÚµçѹ±íµÄ0.6VʾÊýλÖã¬ÈçÉϱíËùʾ£»
£¨4£©Èôµçѹ±íµÄÁ¿³ÌÊÇ0¡«3V£¬´Ë¾Æ¾«²âÊÔÒÇÄܼì²â³ö¾Æ¾«ÆøÌåµÄŨ¶È×î¶àΪ0.13mg/L£®
µãÆÀ£º±¾Ì⿼²éÁË´®Áªµç·µÄÌصãºÍÅ·Ä·¶¨ÂɵÄÓ¦Ó㬹ؼüÊÇ´Ó±í¸ñÖеóö¾Æ¾«Å¨¶È¶ÔÓ¦¾Æ¾«ÆøÌå´«¸ÐÆ÷µç×èµÄ×èÖµ£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø