题目内容
把5.4千克的铝和1分米3的铁制成合金,合金密度为多少?(ρ铝=2.7×103千克/米3,ρ铁=7.8×103千克/米3)?
解:合金的质量:
m=m铝+m铁=m铝+ρ铁V铁=5.4kg+7.8×103kg/m3×10﹣3m3=13.2kg;
合金的体积:
V=V铝+V铁=
+V铁=
+10﹣3m3=3×10﹣3m3;
合金密度:
ρ和=
=
=4.4×103kg/m3.
m=m铝+m铁=m铝+ρ铁V铁=5.4kg+7.8×103kg/m3×10﹣3m3=13.2kg;
合金的体积:
V=V铝+V铁=
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合金密度:
ρ和=
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