ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿Ð¡Ã÷ÏëÖªµÀ½´Ó͵ÄÃܶȣ¬ÓÚÊÇËûºÍС»ªÓÃÌìƽºÍÁ¿Í²×öÁËÈçÏÂʵÑé:
(1)½«Ììƽ·ÅÔÚˮƽ̨ÉÏ£¬°ÑÓÎÂë·ÅÔÚÁã¿Ì¶È´¦£¬·¢ÏÖÖ¸ÕëÖ¸ÔÚ·Ö¶ÈÅ̵ÄÓҲ࣬ҪʹºáÁºÆ½ºâ£¬Ó¦½«Æ½ºâÂÝĸÏò______(Ìî¡°ÓÒ¡±»ò¡°×ó¡±)µ÷.
(2)ÓÃÌìƽ²â³ö¿ÕÉÕ±µÄÖÊÁ¿Îª17g£¬ÔÚÉÕ±Öе¹ÈëÊÊÁ¿µÄ½´ÓÍ£¬²â³öÉÕ±ºÍ½´Ó͵Ä×ÜÖÊÁ¿Èçͼ¼×Ëùʾ£¬½«ÉÕ±ÖеĽ´ÓÍÈ«²¿µ¹ÈëÁ¿Í²ÖУ¬½´Ó͵ÄÌå»ýÈçͼÒÒËùʾ£¬ÔòÉÕ±Öн´Ó͵ÄÖÊÁ¿Îª_______g,½´Ó͵ÄÃܶÈΪ_________kg/m3.
(3)СÃ÷ÓÃÕâÖÖ·½·¨²â³öµÄ½´ÓÍÃܶȻá________(Ìî¡°Æ«´ó¡±»ò¡°Æ«Ð¡¡±).
(4)С»ª²»Ð¡ÐĽ«Á¿Í²´òËéÁË£¬ÀÏʦ˵ֻÓÃÌìƽҲÄܲâÁ¿³ö½´Ó͵ÄÃܶÈ.ÓÚÊÇС»ªÌí¼ÓÁ½¸öÍêÈ«ÏàͬµÄÉÕ±ºÍÊÊÁ¿µÄË®£¬Éè¼ÆÁËÈçÏÂʵÑé²½Ö裬ÇëÄã²¹³äÍêÕû.
¢Ùµ÷ºÃÌìƽ£¬ÓÃÌìƽ²â³ö¿ÕÉÕ±ÖÊÁ¿Îªm0;
¢Ú½«Ò»¸öÉÕ±________________£¬ÓÃÌìƽ²â³öÉÕ±ºÍË®µÄ×ÜÖÊÁ¿Îªm1;¢ÛÁíÒ»¸öÉÕ±×°Âú½´ÓÍ£¬ÓÃÌìƽ²â³ö¢ÛÉÕ±ºÍ½´Ó͵Ä×ÜÖÊÁ¿Îªm2;
¢ÜÔò½´Ó͵ÄÃܶȱí´ïʽ¦Ñ=__________________. (ÒÑ֪ˮµÄÃܶÈΪ¦ÑË®)
¡¾´ð°¸¡¿ ×ó 45 1.125¡Á103 Æ«´ó ×°ÂúË® £¨m2-m0£©¦Ñ/(m1-mo)
¡¾½âÎö¡¿ÊÔÌâ·ÖÎö£º±¾Ì⿼²éÒºÌåÃܶȵIJâÁ¿£¬¸ù¾ÝÃܶȲâÁ¿ÔÀí£¨£©·ÖÎö×ö´ð¡£
£¨1£©³ÆÁ¿Ç°µ÷½ÚÌìƽƽºâʱ£¬Ö¸Õë×óÆ«ÓÒµ÷£¬ÓÒÆ«×óµ÷£¬ËùÒÔÓ¦¸Ã½«Æ½ºâÂÝĸÏò×óµ÷£»
£¨2£©Í¼¼×ÖÐÉÕ±ºÍ½´ÓÍ×ÜÖÊÁ¿Îª62g£¬
ËùÒÔÉÕ±Öн´ÓÍÖÊÁ¿Îª£¬
ͼÒÒÖÐÉÕ±Öн´ÓÍÌå»ýΪ40mL£¬
ËùÒÔ½´ÓÍÃܶÈΪ£»
£¨3£©ÒòΪÉÕ±ÖлáÓвÐÁô½´ÓÍ£¬Ëù²âÌå»ýƫС£¬ËùÒÔ²âÁ¿µÄ½´ÓÍÃܶȻáÆ«´ó£»
£¨4£©Ã»ÓÐÁ¿Í²£¬Òª²âÁ¿½´ÓÍÌå»ýµÄ»°£¬Ö»Äܼä½Ó²âÁ¿¡£½«ÉÕ±×°ÂúË®£¬Í¨¹ýË®µÄÖÊÁ¿ºÍÃܶȼÆËãÉÕ±ÈÝ»ý£¬Ôٴν«ÉÕ±×°Âú½´ÓÍ£¬ÏÖÔÚ½´Ó͵ÄÌå»ýÒ²¾ÍÊÇÉÕ±µÄÈÝ»ýÁË£¬Ò²¾Í¼ä½Ó²âÁ¿½´ÓÍÌå»ýÁË¡£ËùÒÔ²Ù×÷²½ÖèÈçÏ£º
¢Ùµ÷ºÃÌìƽ£¬ÓÃÌìƽ²â³ö¿ÕÉÕ±ÖÊÁ¿Îªm0£»
¢Ú½«Ò»¸öÉÕ±×°ÂúË®£¬ÓÃÌìƽ²â³öÉÕ±ºÍË®µÄ×ÜÖÊÁ¿Îªm1£»
¢ÛÁíÒ»¸öÉÕ±×°Âú½´ÓÍ£¬ÓÃÌìƽ²â³ö¢ÛÉÕ±ºÍ½´Ó͵Ä×ÜÖÊÁ¿Îªm2£»
¢ÜÔò½´Ó͵ÄÃܶȱí´ïʽ¡£