题目内容
(2012•恩施州)先化简,再求值:
÷
-
,其中x=
-2.
| x2+2x+1 |
| x+2 |
| x2-1 |
| x-1 |
| x |
| x+2 |
| 3 |
分析:先根据分式混合运算的法则把原式进行化简,再把x的值代入进行计算即可.
解答:解:原式=
÷
-
,
=
×
-
,
=
-
=
,
将x=
-2代入上式,原式=
.
| (x+1)2 |
| x+2 |
| (x+1)(x-1) |
| x-1 |
| x |
| x+2 |
=
| (x+1)2 |
| x+2 |
| x-1 |
| (x+1)(x-1) |
| x |
| x+2 |
=
| x+1 |
| x+2 |
| x |
| x+2 |
=
| 1 |
| x+2 |
将x=
| 3 |
| ||
| 3 |
点评:本题考查的是分式的混合运算,熟知分式混合运算的法则是解答此题的关键.
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