ÌâÄ¿ÄÚÈÝ
ij¹¤³§Éú²úµÄAÖÖ²úÆ·£¬ËüµÄ³É±¾ÊÇ2Ôª£¬ÊÛ¼ÛÊÇ3Ôª£¬ÄêÏúÁ¿Îª100Íò¼þ£¬ÎªÁË»ñµÃ¸üºÃµÄÐ§Òæ£¬³§¼Ò×¼±¸ÄóöÒ»¶¨µÄ×ʽð×ö¹ã¸æ£»¸ù¾Ýͳ¼Æ£¬Ã¿ÄêͶÈëµÄ¹ã¸æ·ÑÊÇx£¨Ê®ÍòÔª£©£¬²úÆ·µÄÄêÏúÁ¿½«ÊÇÔÏúÊÛÁ¿µÄy±¶£¬ÇÒyÊÇxµÄ¶þ´Îº¯Êý£¬ËüÃǵĹØÏµÈç±í£º| x£¨Ê®ÍòÔª£© | 1 | 2 | |
| y | 1 | 1.5 | 1.8 |
£¨2£©Èç¹û°ÑÀûÈó¿´³ÉÏúÊÛ×ܶî¼õÈ¥³É±¾·ÑºÍ¹ã¸æ·Ñ£¬ÊÔд³öÄêÀûÈóS£¨Ê®ÍòÔª£©Óë¹ã¸æ·Ñx£¨Ê®ÍòÔªµÄº¯Êý¹ØÏµÊ½£©£»
£¨3£©Èç¹ûͶÈëµÄÄê¹ã¸æ·ÑΪ10ÍòÔª¡«30ÍòÔª£¬ÎÊ¹ã¸æ·ÑÔÚʲô·¶Î§ÄÚ£¬¹¤³§»ñµÃµÄÀûÈó×î´ó£¿×î´óÀûÈóÊǶàÉÙ£¿
¡¾´ð°¸¡¿·ÖÎö£º£¨1£©¸ù¾ÝÌâÒâ¿ÉÇó³öyÓëxµÄ¶þ´Îº¯Êý¹ØÏµÊ½£®
£¨2£©¸ù¾ÝÌâÒâ¿ÉÖªS=£¨3-2£©×100y÷10-x=-x2+5x+10£»
£¨3£©¸ù¾Ý½âÎöʽÇó×îÖµ¼´¿É£®
½â´ð£º½â£º£¨1£©ÉèyÓëxµÄº¯Êý¹ØÏµÊ½Îªy=ax2+bx+c£¬
ÓÉÌâÒâµÃ£º
£¬
½âµÃ£º
£¬
¡àyÓëxµÄº¯Êý¹ØÏµÊ½Îª£ºy=-0.1x2+0.6x+1£»
£¨2£©¡ßÀûÈó=ÏúÊÛ×ܶî¼õÈ¥³É±¾·ÑºÍ¹ã¸æ·Ñ£¬
¡àS=£¨3-2£©×100y÷10-x=-x2+5x+10£»
£¨3£©S=-x2+5x+10=-£¨x-2.5£©2+16.25£¬
µ±x=2.5ʱ£¬º¯ÊýÓÐ×î´óÖµ£®ËùÒÔx£¼2.5ÊǺ¯ÊýµÄµÝÔöÇø¼ä£¬
ÓÉÓÚ1¡Üx¡Ü3£¬ËùÒÔ1¡Üx¡Ü2.5ʱ£¬SËæxµÄÔö´ó¶øÔö´ó£®
¡àx=2.5ʱÀûÈó×î´ó£¬×î´óÀûÈóΪ16.25£¨Ê®ÍòÔª£©£®
µãÆÀ£ºÇó¶þ´Îº¯ÊýµÄ×î´ó£¨Ð¡£©ÖµÓÐÈýÖÖ·½·¨£¬µÚÒ»ÖÖ¿ÉÓÉͼÏóÖ±½ÓµÃ³ö£¬µÚ¶þÖÖÊÇÅä·½·¨£¬µÚÈýÖÖÊǹ«Ê½·¨£®ÒªÑ§»áÓöþ´Îº¯Êý½â¾öʵ¼ÊÎÊÌ⣮
£¨2£©¸ù¾ÝÌâÒâ¿ÉÖªS=£¨3-2£©×100y÷10-x=-x2+5x+10£»
£¨3£©¸ù¾Ý½âÎöʽÇó×îÖµ¼´¿É£®
½â´ð£º½â£º£¨1£©ÉèyÓëxµÄº¯Êý¹ØÏµÊ½Îªy=ax2+bx+c£¬
ÓÉÌâÒâµÃ£º
½âµÃ£º
¡àyÓëxµÄº¯Êý¹ØÏµÊ½Îª£ºy=-0.1x2+0.6x+1£»
£¨2£©¡ßÀûÈó=ÏúÊÛ×ܶî¼õÈ¥³É±¾·ÑºÍ¹ã¸æ·Ñ£¬
¡àS=£¨3-2£©×100y÷10-x=-x2+5x+10£»
£¨3£©S=-x2+5x+10=-£¨x-2.5£©2+16.25£¬
µ±x=2.5ʱ£¬º¯ÊýÓÐ×î´óÖµ£®ËùÒÔx£¼2.5ÊǺ¯ÊýµÄµÝÔöÇø¼ä£¬
ÓÉÓÚ1¡Üx¡Ü3£¬ËùÒÔ1¡Üx¡Ü2.5ʱ£¬SËæxµÄÔö´ó¶øÔö´ó£®
¡àx=2.5ʱÀûÈó×î´ó£¬×î´óÀûÈóΪ16.25£¨Ê®ÍòÔª£©£®
µãÆÀ£ºÇó¶þ´Îº¯ÊýµÄ×î´ó£¨Ð¡£©ÖµÓÐÈýÖÖ·½·¨£¬µÚÒ»ÖÖ¿ÉÓÉͼÏóÖ±½ÓµÃ³ö£¬µÚ¶þÖÖÊÇÅä·½·¨£¬µÚÈýÖÖÊǹ«Ê½·¨£®ÒªÑ§»áÓöþ´Îº¯Êý½â¾öʵ¼ÊÎÊÌ⣮
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ij¹¤³§Éú²úµÄAÖÖ²úÆ·£¬ËüµÄ³É±¾ÊÇ2Ôª£¬ÊÛ¼ÛÊÇ3Ôª£¬ÄêÏúÁ¿Îª100Íò¼þ£¬ÎªÁË»ñµÃ¸üºÃµÄÐ§Òæ£¬³§¼Ò×¼±¸ÄóöÒ»¶¨µÄ×ʽð×ö¹ã¸æ£»¸ù¾Ýͳ¼Æ£¬Ã¿ÄêͶÈëµÄ¹ã¸æ·ÑÊÇx£¨Ê®ÍòÔª£©£¬²úÆ·µÄÄêÏúÁ¿½«ÊÇÔÏúÊÛÁ¿µÄy±¶£¬ÇÒyÊÇxµÄ¶þ´Îº¯Êý£¬ËüÃǵĹØÏµÈç±í£º
£¨1£©ÇóyÓëxµÄº¯Êý¹ØÏµÊ½£»
£¨2£©Èç¹û°ÑÀûÈó¿´³ÉÏúÊÛ×ܶî¼õÈ¥³É±¾·ÑºÍ¹ã¸æ·Ñ£¬ÊÔд³öÄêÀûÈóS£¨Ê®ÍòÔª£©Óë¹ã¸æ·Ñx£¨Ê®ÍòÔªµÄº¯Êý¹ØÏµÊ½£©£»
£¨3£©Èç¹ûͶÈëµÄÄê¹ã¸æ·ÑΪ10ÍòÔª¡«30ÍòÔª£¬ÎÊ¹ã¸æ·ÑÔÚʲô·¶Î§ÄÚ£¬¹¤³§»ñµÃµÄÀûÈó×î´ó£¿×î´óÀûÈóÊǶàÉÙ£¿
| x£¨Ê®ÍòÔª£© | 0 | 1 | 2 |
| y | 1 | 1.5 | 1.8 |
£¨2£©Èç¹û°ÑÀûÈó¿´³ÉÏúÊÛ×ܶî¼õÈ¥³É±¾·ÑºÍ¹ã¸æ·Ñ£¬ÊÔд³öÄêÀûÈóS£¨Ê®ÍòÔª£©Óë¹ã¸æ·Ñx£¨Ê®ÍòÔªµÄº¯Êý¹ØÏµÊ½£©£»
£¨3£©Èç¹ûͶÈëµÄÄê¹ã¸æ·ÑΪ10ÍòÔª¡«30ÍòÔª£¬ÎÊ¹ã¸æ·ÑÔÚʲô·¶Î§ÄÚ£¬¹¤³§»ñµÃµÄÀûÈó×î´ó£¿×î´óÀûÈóÊǶàÉÙ£¿
ij¹¤³§Éú²úµÄAÖÖ²úÆ·£¬ËüµÄ³É±¾ÊÇ2Ôª£¬ÊÛ¼ÛÊÇ3Ôª£¬ÄêÏúÁ¿Îª100Íò¼þ£¬ÎªÁË»ñµÃ¸üºÃµÄÐ§Òæ£¬³§¼Ò×¼±¸ÄóöÒ»¶¨µÄ×ʽð×ö¹ã¸æ£»¸ù¾Ýͳ¼Æ£¬Ã¿ÄêͶÈëµÄ¹ã¸æ·ÑÊÇx£¨Ê®ÍòÔª£©£¬²úÆ·µÄÄêÏúÁ¿½«ÊÇÔÏúÊÛÁ¿µÄy±¶£¬ÇÒyÊÇxµÄ¶þ´Îº¯Êý£¬ËüÃǵĹØÏµÈç±í£º
£¨1£©ÇóyÓëxµÄº¯Êý¹ØÏµÊ½£»
£¨2£©Èç¹û°ÑÀûÈó¿´³ÉÏúÊÛ×ܶî¼õÈ¥³É±¾·ÑºÍ¹ã¸æ·Ñ£¬ÊÔд³öÄêÀûÈóS£¨Ê®ÍòÔª£©Óë¹ã¸æ·Ñx£¨Ê®ÍòÔªµÄº¯Êý¹ØÏµÊ½£©£»
£¨3£©Èç¹ûͶÈëµÄÄê¹ã¸æ·ÑΪ10ÍòÔª¡«30ÍòÔª£¬ÎÊ¹ã¸æ·ÑÔÚʲô·¶Î§ÄÚ£¬¹¤³§»ñµÃµÄÀûÈó×î´ó£¿×î´óÀûÈóÊǶàÉÙ£¿
| x£¨Ê®ÍòÔª£© | 1 | 2 | |
| y | 1 | 1.5 | 1.8 |
£¨2£©Èç¹û°ÑÀûÈó¿´³ÉÏúÊÛ×ܶî¼õÈ¥³É±¾·ÑºÍ¹ã¸æ·Ñ£¬ÊÔд³öÄêÀûÈóS£¨Ê®ÍòÔª£©Óë¹ã¸æ·Ñx£¨Ê®ÍòÔªµÄº¯Êý¹ØÏµÊ½£©£»
£¨3£©Èç¹ûͶÈëµÄÄê¹ã¸æ·ÑΪ10ÍòÔª¡«30ÍòÔª£¬ÎÊ¹ã¸æ·ÑÔÚʲô·¶Î§ÄÚ£¬¹¤³§»ñµÃµÄÀûÈó×î´ó£¿×î´óÀûÈóÊǶàÉÙ£¿
£¨2001•°²»Õ£©Ä³¹¤³§Éú²úµÄAÖÖ²úÆ·£¬ËüµÄ³É±¾ÊÇ2Ôª£¬ÊÛ¼ÛÊÇ3Ôª£¬ÄêÏúÁ¿Îª100Íò¼þ£¬ÎªÁË»ñµÃ¸üºÃµÄÐ§Òæ£¬³§¼Ò×¼±¸ÄóöÒ»¶¨µÄ×ʽð×ö¹ã¸æ£»¸ù¾Ýͳ¼Æ£¬Ã¿ÄêͶÈëµÄ¹ã¸æ·ÑÊÇx£¨Ê®ÍòÔª£©£¬²úÆ·µÄÄêÏúÁ¿½«ÊÇÔÏúÊÛÁ¿µÄy±¶£¬ÇÒyÊÇxµÄ¶þ´Îº¯Êý£¬ËüÃǵĹØÏµÈç±í£º
£¨1£©ÇóyÓëxµÄº¯Êý¹ØÏµÊ½£»
£¨2£©Èç¹û°ÑÀûÈó¿´³ÉÏúÊÛ×ܶî¼õÈ¥³É±¾·ÑºÍ¹ã¸æ·Ñ£¬ÊÔд³öÄêÀûÈóS£¨Ê®ÍòÔª£©Óë¹ã¸æ·Ñx£¨Ê®ÍòÔªµÄº¯Êý¹ØÏµÊ½£©£»
£¨3£©Èç¹ûͶÈëµÄÄê¹ã¸æ·ÑΪ10ÍòÔª¡«30ÍòÔª£¬ÎÊ¹ã¸æ·ÑÔÚʲô·¶Î§ÄÚ£¬¹¤³§»ñµÃµÄÀûÈó×î´ó£¿×î´óÀûÈóÊǶàÉÙ£¿
| x£¨Ê®ÍòÔª£© | 1 | 2 | |
| y | 1 | 1.5 | 1.8 |
£¨2£©Èç¹û°ÑÀûÈó¿´³ÉÏúÊÛ×ܶî¼õÈ¥³É±¾·ÑºÍ¹ã¸æ·Ñ£¬ÊÔд³öÄêÀûÈóS£¨Ê®ÍòÔª£©Óë¹ã¸æ·Ñx£¨Ê®ÍòÔªµÄº¯Êý¹ØÏµÊ½£©£»
£¨3£©Èç¹ûͶÈëµÄÄê¹ã¸æ·ÑΪ10ÍòÔª¡«30ÍòÔª£¬ÎÊ¹ã¸æ·ÑÔÚʲô·¶Î§ÄÚ£¬¹¤³§»ñµÃµÄÀûÈó×î´ó£¿×î´óÀûÈóÊǶàÉÙ£¿