题目内容
(1)计算:2+(
-1)0-(-
)-2
(2)化简求值:(
-x-1)÷
,其中x2-1=0.
2 |
1 |
2 |
(2)化简求值:(
3 |
x-1 |
x2-4 |
x2-2x+1 |
(1)原式=2+1-4=-1;
(2)原式=
÷
=-
•
=-x+1,
∵x≠1,x2-1=0,
∴x=-1,
则原式=1+1=2.
(2)原式=
3-(x+1)(x-1) |
x-1 |
(x+2)(x-2) |
(x-1)2 |
(x+2)(x-2) |
x-1 |
(x-1)2 |
(x+2)(x-2) |
∵x≠1,x2-1=0,
∴x=-1,
则原式=1+1=2.
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