题目内容
计算:
(1)(2a+3b+1)(1-2a-3b)+(2a-3b)2
(2)
÷
+
.
(1)(2a+3b+1)(1-2a-3b)+(2a-3b)2
(2)
x |
x-1 |
x2-x |
x2-1 |
1 |
1-x |
(1)原式=1-(2a+3b)2+(2a+3b)2=1;
(2)原式=
•
+
=
-
=
.
(2)原式=
x |
x-1 |
(x+1)(x-1) |
x(x-1) |
1 |
1-x |
x+1 |
x-1 |
1 |
x-1 |
x |
x-1 |
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