题目内容
计算题
(1)
÷(a2-4)•
;
(2)
÷(x+1)•
(1)
a2-4 |
a2+2a-8 |
a2-4a+4 |
a-2 |
(2)
x2-1 |
x2-4x+4 |
x2-3x+2 |
x-1 |
(1)原式=
•
•
=
;
(2)原式=
×
×
=
.
(a+2)(a-2) |
(a+4)(a-2) |
1 |
(a+2)(a-2) |
(a-2)2 |
a-2 |
1 |
a+4 |
(2)原式=
(x+1)(x-1) |
(x-2)2 |
1 |
x+1 |
(x-1)(x-2) |
x-1 |
x-1 |
x-2 |
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