题目内容
599×0.2100=1 | 9 |
分析:由于5×0.2=1,(-
)×9=-1,81=92,两题都可以逆用积的乘方的性质:anbn=(ab)n,得出结果.
1 |
9 |
解答:解:599×0.2100,
=599×0.299×0.2,
=(5×0.2)99×0.2,
=0.2;
(-
)7×814,
=(-
)7×(92)4,
=(-
)7×98,
=(-
×9)7×9,
=(-1)7×9,
=-1×9,
=-9.
=599×0.299×0.2,
=(5×0.2)99×0.2,
=0.2;
(-
1 |
9 |
=(-
1 |
9 |
=(-
1 |
9 |
=(-
1 |
9 |
=(-1)7×9,
=-1×9,
=-9.
点评:本题考查积的乘方的性质,熟练掌握并灵活运用性质是解决本题的关键.
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