题目内容
化简题(1)
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(2)5(a2b-2ab2+c)-4(2c+3a2b-ab2)
分析:(1)首先去括号,然后合并同类项即可;
(2)首先去括号,然后合并同类项即可.
(2)首先去括号,然后合并同类项即可.
解答:解:(1)原式=
x-2x+
y2-
x+
y2,
=-3x+y2;
(2)5(a2b-2ab2+c)-4(2c+3a2b-ab2),
=5a2b-10ab2+5c-8c-12a2b+4ab2,
=-7a2b-6ab2-3c.
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=-3x+y2;
(2)5(a2b-2ab2+c)-4(2c+3a2b-ab2),
=5a2b-10ab2+5c-8c-12a2b+4ab2,
=-7a2b-6ab2-3c.
点评:本题考查了整式的加减运算,关键是正确去括号.
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