题目内容
化简题:
(1)
÷(x+3)×
;
(2)-(-
)2•(-
)3•(
)4•(2a3);
(3)
-
;
(4)
÷(x+2-
);
(5)(x2-1)(
-
-1).
(1)
| 2x-6 |
| 4-4x+x2 |
| x2+x-6 |
| 3-x |
(2)-(-
| a2 |
| b |
| b2 |
| a |
| 1 |
| ab |
(3)
2+
| ||
2-
|
| ||||
|
(4)
| 3-x |
| 2x-4 |
| 5 |
| x-2 |
(5)(x2-1)(
| 1 |
| x-1 |
| 1 |
| x+1 |
(1)
÷(x+3)×
=
×
×
=-
;
(2)-(-
)2•(-
)3•(
)4•(2a3)
=
•
•
•8a3
=8;
(3)
-
=
-
=
=
;
(4)
÷(x+2-
)
=
÷
=
×
=-
;
(5)(x2-1)(
-
-1)
=(x+1)(x-1)(
-
-1)
=x+1-(x-1)-(x+1)(x-1)
=3-x2.
| 2x-6 |
| 4-4x+x2 |
| x2+x-6 |
| 3-x |
=
| 2(x-3) |
| (x-2)2 |
| 1 |
| x+3 |
| (x-2)(x+3) |
| 3-x |
=-
| 2 |
| x-2 |
(2)-(-
| a2 |
| b |
| b2 |
| a |
| 1 |
| ab |
=
| a4 |
| b2 |
| b6 |
| a3 |
| 1 |
| a4b4 |
=8;
(3)
2+
| ||
2-
|
| ||||
|
=
| 2x+3y |
| 2x-3y |
| 3x+2y |
| 3x-2y |
=
| (2x+3y)(3x-2y)-(2x-3y)(3x+2y) |
| (2x-3y)(3x-2y) |
=
| 10xy |
| (2x-3y)(3x-2y) |
(4)
| 3-x |
| 2x-4 |
| 5 |
| x-2 |
=
| 3-x |
| 2(x-2) |
| (x+2)(x-2)-5 |
| x-2 |
=
| 3-x |
| 2(x-2) |
| x-2 |
| (x+3)(x-3) |
=-
| 1 |
| 2(x+3) |
(5)(x2-1)(
| 1 |
| x-1 |
| 1 |
| x+1 |
=(x+1)(x-1)(
| 1 |
| x-1 |
| 1 |
| x+1 |
=x+1-(x-1)-(x+1)(x-1)
=3-x2.
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