题目内容
化简(3a2)3-7a3[a3-a(4a2+1)]得
- A.48a6+7a4
- B.9a6+7a3
- C.-7a9+31a6+7a4
- D.27a5-7a3
A
(3a2)3-7a3[a3-a(4a2+1)]
=33(a2)3-7a3·a3-7a3·[-a(4a2+1)]
=27a6-7a6+7a4(4a2+1)
=20a6+28a6+7a4=48a6+7a4故选A.
(3a2)3-7a3[a3-a(4a2+1)]
=33(a2)3-7a3·a3-7a3·[-a(4a2+1)]
=27a6-7a6+7a4(4a2+1)
=20a6+28a6+7a4=48a6+7a4故选A.
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