题目内容
计算:
(1)(-23)+(-12);
(2)6-(+3)-(-7)+(-2);
(3)-16
+29
;
(4)-0.5-(-3
)+2.75-7
;
(5)-(-7)+(-2);
(6)(-4
)-(+5
)-(-4
);
(7)(+9)+(-7)+(+10)+(-3)+(-9);
(8)1-3+5-7+9-11+…+97-99+100.
(1)(-23)+(-12);
(2)6-(+3)-(-7)+(-2);
(3)-16
1 |
3 |
1 |
6 |
(4)-0.5-(-3
1 |
4 |
1 |
2 |
(5)-(-7)+(-2);
(6)(-4
1 |
4 |
1 |
3 |
1 |
4 |
(7)(+9)+(-7)+(+10)+(-3)+(-9);
(8)1-3+5-7+9-11+…+97-99+100.
分析:(1)利用有理数的加法求解即可求得答案;
(2)首先去括号,然后同号相加,再求解即可求得答案;
(3)利用有理数的加法求解即可求得答案;
(4)首先去括号,然后同号相加,再求解即可求得答案;
(5)首先去括号,然后利用有理数的减法运算法则求解即可求得答案;
(6)首先去括号,然后分母相加,再求解即可求得答案;
(7)首先去括号,然后同号相加,再求解即可求得答案;
(8)首先将原式变形为:(1-3)+(5-7)+(9-11)+…+(97-99)+100,继而可求得答案.
(2)首先去括号,然后同号相加,再求解即可求得答案;
(3)利用有理数的加法求解即可求得答案;
(4)首先去括号,然后同号相加,再求解即可求得答案;
(5)首先去括号,然后利用有理数的减法运算法则求解即可求得答案;
(6)首先去括号,然后分母相加,再求解即可求得答案;
(7)首先去括号,然后同号相加,再求解即可求得答案;
(8)首先将原式变形为:(1-3)+(5-7)+(9-11)+…+(97-99)+100,继而可求得答案.
解答:解:(1)(-23)+(-12)=-35;
(2)6-(+3)-(-7)+(-2)=6-3+7-2=13-5=8;
(3)-16
+29
=12
;
(4)-0.5-(-3
)+2.75-7
=-0.5-7.5+3.25+2.75=-8+6=-2;
(5)-(-7)+(-2)=7-2=5;
(6)(-4
)-(+5
)-(-4
)=-4
+4
-5
=-5
;
(7)(+9)+(-7)+(+10)+(-3)+(-9)=9-7+10-3-9=0;
(8)1-3+5-7+9-11+…+97-99+100=(1-3)+(5-7)+(9-11)+…+(97-99)+100=-2-2-2-…-2+100=-2×25+100=50.
(2)6-(+3)-(-7)+(-2)=6-3+7-2=13-5=8;
(3)-16
1 |
3 |
1 |
6 |
5 |
6 |
(4)-0.5-(-3
1 |
4 |
1 |
2 |
(5)-(-7)+(-2)=7-2=5;
(6)(-4
1 |
4 |
1 |
3 |
1 |
4 |
1 |
4 |
1 |
4 |
1 |
3 |
1 |
3 |
(7)(+9)+(-7)+(+10)+(-3)+(-9)=9-7+10-3-9=0;
(8)1-3+5-7+9-11+…+97-99+100=(1-3)+(5-7)+(9-11)+…+(97-99)+100=-2-2-2-…-2+100=-2×25+100=50.
点评:此题考查了有理数的加减混合运算.注意掌握运算法则,掌握简便方法是关键.
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