题目内容
(6分)某初级中学准备随机选出七、八、九三个年级各1名学生担任领操员.现已知这三个年级分别选送一男、一女共6名学生为备选人.【小题1】(1)请你利用树状图或表格列出所有可能的选法;
【小题2】(2)求选出“两男一女”三名领操员的概率.
【小题1】解法一:(1)用表格列出所有可能结果:
七年级 | 八年级 | 九年级 | 结果 |
男 | 男 | 男 | (男,男,男) |
男 | 男 | 女 | (男,男,女) |
男 | 女 | 男 | (男,女,男) |
男 | 女 | 女 | (男,女,女) |
女 | 女 | 女 | (女,女,女) |
女 | 女 | 男 | (女,女,男) |
女 | 男 | 女 | (女,男,女) |
女 | 男 | 男 | (女,男,男) |
·········································································································· 3分
解法二:(1)用树状图列出所有可能结果:
·········································································································· 3分
【小题2】(2)从上表可知:共有8种结果,且每种结果都是等可能的,其中“两男一女”的结果有3种. 5分
所以,P(两男一女)=.········································································ 6分解析:
略
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