题目内容

(1)计算:
2
x2-4
-
1
2x-4

(2)先将分式:1-
a-1
a
÷
a2-1
a2+2a
化简,然后请你选一个自己喜欢的a值,求原式的值.
分析:(1)首先把分式进行通分,化为同分母的分式相减,依据法则即可求解;
(2)首先把分式的中的除法转化为乘法,然后通分,相加减即可化简,然后把a=2代入即可求解.
解答:解:(1)原式=
2
(x+2)(x-2)
-
1
2(x-2)

=
4
2(x+2)(x-2)
-
x+2
2(x+2)(x-2)

=
4-(x+2)
2(x+2)(x-2)

=
2-x
2(x+2)(x-2)

=
-(x-2)
2(x+2)(x-2)

=-
1
x+2

(2)原式=1-
a-1
a
a(a+2)
(a+1)(a-1)

=1-
a+2
a+1

=
a+1
a+1
-
a+2
a+1

=
a+1-(a+2)
a+1

=
-1
a+1

=-
1
a+1

当a=2时,原式=-
1
2+1
=-
1
3
点评:本题考查了分式的化简求值,注意在确定a的值时,一定要注意所取的数值使原式有意义.
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