题目内容
如图,以等边△OAB的高OC为边向逆时针方向作等边△OCD,CD交OB于点E,再以OE为边向逆时针方向作等边△OEF,EF交OD于点G,再以OG为边向逆时针方向作等边△OGH,…,按此方法操作,最后得到△OMN,此时N在AO延长线上.若AB=1,则ON=______.


∵等边△ABC的边长为1,OC⊥AB,
∴OC=OA•sin60°=1×
=
,
同理,OE=OC•sin60°=
×
=(
)2=
,
OG=OE•sin60°=
×
=(
)3=
,
故OM=ON=(
)4=
.
故答案为:
.
∴OC=OA•sin60°=1×
| ||
2 |
| ||
2 |
同理,OE=OC•sin60°=
| ||
2 |
| ||
2 |
| ||
2 |
3 |
4 |
OG=OE•sin60°=
3 |
4 |
| ||
2 |
| ||
2 |
3
| ||
8 |
故OM=ON=(
| ||
2 |
9 |
16 |
故答案为:
9 |
16 |

练习册系列答案
相关题目