题目内容
计算
(1)2(m+1)2-(2m+1)(2m-1) (2)28x4y2÷7x3y
(1)2(m+1)2-(2m+1)(2m-1) (2)28x4y2÷7x3y
(1)2(m+1)2-(2m+1)(2m-1) (2)28x4y2÷7x3y
=2(m2+2m+1)-[(2m)2-1] =(28÷7)( x4÷x3)( y2÷y)
=2m2+4m+2-4m2+1 =4x4-3y2-1
=-2m2+4m+3 =4xy
=2(m2+2m+1)-[(2m)2-1] =(28÷7)( x4÷x3)( y2÷y)
=2m2+4m+2-4m2+1 =4x4-3y2-1
=-2m2+4m+3 =4xy
略
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