题目内容
【题目】下列各式中,去括号正确的是
A.x+2(y–1)=x+2y–1 B.x–2(y–1)=x+2y+2
C.x–2(y–1)=x–2y–2 D.x–2(y–1)=x–2y+2
【答案】D
【解析】因为x+2(y–1)=x+2y–2,故A错误;因为x–2(y–1)=x–2y+2,故B错误,C错误,D正确.故选D.
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题目内容
【题目】下列各式中,去括号正确的是
A.x+2(y–1)=x+2y–1 B.x–2(y–1)=x+2y+2
C.x–2(y–1)=x–2y–2 D.x–2(y–1)=x–2y+2
【答案】D
【解析】因为x+2(y–1)=x+2y–2,故A错误;因为x–2(y–1)=x–2y+2,故B错误,C错误,D正确.故选D.