题目内容
一元二次方程x(x-2)=2-x的根是
A.﹣1 | B.2 | C.1和2 | D.﹣1和2 |
D
x(x-2)=2-x,
x2-2x=2-x,
x2-2x+x-2=0,
x2-x-2=0,
(x-2)(x+1)=0,
x-2=0或x+1=0,
解得x1=2,x2=-1;
故选D
x2-2x=2-x,
x2-2x+x-2=0,
x2-x-2=0,
(x-2)(x+1)=0,
x-2=0或x+1=0,
解得x1=2,x2=-1;
故选D
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