题目内容
计算:
(1)
÷
+
(2)
-
.
(1)
x-4 |
x2-1 |
(x+1)(x-4) |
x2+2x+1 |
1 |
x-1 |
(2)
a-6 |
a2-4 |
2 |
2a-a2 |
①原式=
•
+
=
+
=
;
②原式=
-
=
+
=
+
=
=
=
.
x-4 |
(x-1)(x+1) |
(x+1)2 |
(x+1)(x-4) |
1 |
x-1 |
=
1 |
x-1 |
1 |
x-1 |
=
2 |
x-1 |
②原式=
a-6 |
(a-2)(a+2) |
2 |
a(2-a) |
=
a-6 |
(a-2)(a+2) |
2 |
a(a-2) |
=
a2-6a |
a(a-2)(a+2) |
2a+4 |
a(a-2)(a+2) |
=
a2-4a+4 |
a(a-2)(a+2) |
=
(a-2)2 |
a(a-2)(a+2) |
=
a-2 |
a(a+2) |
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