题目内容

计算:
(1)
x-4
x2-1
÷
(x+1)(x-4)
x2+2x+1
+
1
x-1

(2)
a-6
a2-4
-
2
2a-a2
①原式=
x-4
(x-1)(x+1)
(x+1)2
(x+1)(x-4)
+
1
x-1

=
1
x-1
+
1
x-1

=
2
x-1

②原式=
a-6
(a-2)(a+2)
-
2
a(2-a)

=
a-6
(a-2)(a+2)
+
2
a(a-2)

=
a2-6a
a(a-2)(a+2)
+
2a+4
a(a-2)(a+2)

=
a2-4a+4
a(a-2)(a+2)

=
(a-2)2
a(a-2)(a+2)

=
a-2
a(a+2)
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