ÌâÄ¿ÄÚÈÝ
ÒÔÏÂ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
·ÖÎö£º·Ö±ð¸ù¾Ý¶àÏîʽµÄ¶¨ÒåÒÔ¼°º¯ÊýµÄ¶¨Òå·Ö±ð·ÖÎöµÃ³ö¼´¿É£®
½â´ð£º½â£ºA¡¢0.5b+0.35a£¬ab+3mn£¬¦Ðr2-a2µÈ¶¼ÊǶàÏîʽ£¬
ÊÇ·Öʽ£¬¹Ê´ËÑ¡Ïî´íÎó£»
B¡¢ÉèÔÚÒ»¸ö±ä»¯¹ý³ÌÖÐÓÐÁ½¸ö±äÁ¿xÓëy£¬¶ÔÓÚxµÄÿһ¸öÈ·¶¨µÄÖµ£¬y¶¼ÓÐΨһµÄÖµÓëÆä¶ÔÓ¦£¬ÄÇô¾Í˵yÊÇxµÄº¯Êý£¬xÊÇ×Ô±äÁ¿£¬¹Ê´ËÑ¡Ïî´íÎó£»
C¡¢Ïñ3n£¬ab+c2µÈ£¬º¬Óмӡ¢¼õ¡¢³Ë¡¢³ý¡¢³Ë·½ÔËËãµÄ´úÊýʽ½Ð×öÕûʽ£¬
ÊÇ·Öʽ£¬¹Ê´ËÑ¡Ïî´íÎó£»
D¡¢Ê½×Ón-m£¬
a£¬
£¬2£¨a+b£©µÈ¶¼ÊÇ´úÊýʽ£¬´ËÑ¡ÏîÕýÈ·£®
¹ÊÑ¡£ºD£®
x+3 |
y |
B¡¢ÉèÔÚÒ»¸ö±ä»¯¹ý³ÌÖÐÓÐÁ½¸ö±äÁ¿xÓëy£¬¶ÔÓÚxµÄÿһ¸öÈ·¶¨µÄÖµ£¬y¶¼ÓÐΨһµÄÖµÓëÆä¶ÔÓ¦£¬ÄÇô¾Í˵yÊÇxµÄº¯Êý£¬xÊÇ×Ô±äÁ¿£¬¹Ê´ËÑ¡Ïî´íÎó£»
C¡¢Ïñ3n£¬ab+c2µÈ£¬º¬Óмӡ¢¼õ¡¢³Ë¡¢³ý¡¢³Ë·½ÔËËãµÄ´úÊýʽ½Ð×öÕûʽ£¬
2 |
v |
D¡¢Ê½×Ón-m£¬
4 |
3 |
1 |
m |
¹ÊÑ¡£ºD£®
µãÆÀ£º´ËÌâÖ÷Òª¿¼²éÁ˶àÏîʽµÄ¶¨ÒåÒÔ¼°´úÊýʽµÄ¶¨ÒåºÍÕýÕûµÄ¸ÅÄÒ壬ÊìÁ·°ÑÎÕÏà¹Ø¶¨ÒåÊǽâÌâ¹Ø¼ü£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ÒÔÏÂ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A¡¢ÔÚͬһÄê³öÉúµÄ400ÈËÖÐÖÁÉÙÓÐÁ½È˵ÄÉúÈÕÏàͬ | ||
B¡¢Ò»¸öÓÎÏ·µÄÖн±ÂÊÊÇ1%£¬Âò100ÕŽ±È¯£¬Ò»¶¨»áÖн± | ||
C¡¢Ò»¸±ÆË¿ËÅÆÖУ¬ËæÒâ³éÈ¡Ò»ÕÅÊǺìÌÒK£¬ÕâÊDZØȻʼþ | ||
D¡¢Ò»¸ö´üÖÐ×°ÓÐ3¸öºìÇò¡¢5¸ö°×Çò£¬ÈÎÒâÃþ³öÒ»¸öÇòÊǺìÇòµÄ¸ÅÂÊÊÇ
|
a¡¢b¡¢c¡¢dΪʵÊý£¬¹æ¶¨ÒÔÏÂÔËË㣺
£¨a£¬b£©+£¨c£¬d£©=£¨a+c£¬b+d£©
£¨a£¬b£©¡Á£¨c£¬d£©=£¨ac-bd£¬ad+bc£©£®ÔòÒÔÏÂ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
£¨a£¬b£©+£¨c£¬d£©=£¨a+c£¬b+d£©
£¨a£¬b£©¡Á£¨c£¬d£©=£¨ac-bd£¬ad+bc£©£®ÔòÒÔÏÂ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A¡¢Èô£¨3£¬4-x£©+£¨x£¬4£©=£¨4£¬5£©£¬Ôòx=1 | B¡¢Èô£¨x£¬1£©¡Á£¨x-2£¬1£©=£¨2£¬4£©£¬Ôòx=3»ò-1 | C¡¢Èô£¨x£¬y£©¡Á£¨y£¬x-2£©=£¨2£¬4£©£¬Ôòx=3£¬y=1 | D¡¢Èô£¨x£¬x-2£©¡Á£¨x+2£¬4£©=£¨16£¬y£©£¬Ôòx=4£¬y=28»òx=-2£¬y=-8 |