题目内容
(2012•绵阳)(1)计算:(π-2)0-|
+
|×(-
);
(2)化简:(1+
)+(2x-
)
3 | -8 |
2 |
2 | ||
|
(2)化简:(1+
1 |
x |
1+x2 |
x |
分析:(1)首先计算0次方,以及开方运算,去掉绝对值符号,化简二次根式,然后合并同类二次根式即可求解;
(2)首先计算括号内的分式,然后进行同分母的分式的加法运算即可.
(2)首先计算括号内的分式,然后进行同分母的分式的加法运算即可.
解答:解:(1)原式=1-|-2+
|×(-
)
=1-(2-
)×(-
)
=1+
-1
=
;
(2)原式=
+
=
+
=
=x+1.
2 |
| ||
2 |
=1-(2-
2 |
| ||
2 |
=1+
2 |
=
2 |
(2)原式=
x+1 |
x |
2x2-1-x2 |
x |
=
x+1 |
x |
x2-1 |
x |
=
x2+x |
x |
=x+1.
点评:本题主要考查分式的混合运算,通分、因式分解和约分是解答的关键.

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