题目内容
计算:(下列各题解答时必须给出必要的演算过程或推理步骤)
(1)(-20)+(+3)-(-5)-(+7);
(2)(
+
-
)×24;
(3)(-3)2-(
)3×
-6÷|-
|;
(4)(-1)2013×|-5|-4×(-3)-42;
(5)化简:2(2a2+9b)-(3a2+4b).
(1)(-20)+(+3)-(-5)-(+7);
(2)(
| 3 |
| 8 |
| 1 |
| 6 |
| 3 |
| 4 |
(3)(-3)2-(
| 3 |
| 2 |
| 2 |
| 9 |
| 2 |
| 3 |
(4)(-1)2013×|-5|-4×(-3)-42;
(5)化简:2(2a2+9b)-(3a2+4b).
分析:(1)先将减法运算转化为加法运算,再根据有理数加法法则计算即可;
(2)利用乘法分配律计算即可;
(3)按照有理数混合运算顺序:先算乘方,再算乘除,最后算加减;
(4)按照有理数混合运算顺序:先算乘方,再算乘除,最后算加减;
(5)先去括号,再合并同类项即可.
(2)利用乘法分配律计算即可;
(3)按照有理数混合运算顺序:先算乘方,再算乘除,最后算加减;
(4)按照有理数混合运算顺序:先算乘方,再算乘除,最后算加减;
(5)先去括号,再合并同类项即可.
解答:解:(1)(-20)+(+3)-(-5)-(+7)
=-20+3+5-7
=-19;
(2)(
+
-
)×24
=9+4-18
=-5;
(3)(-3)2-(
)3×
-6÷|-
|
=9-
×
-6×
=9-
-9=-
;
(4)(-1)2013×|-5|-4×(-3)-42
=(-1)×5-(-12)-16
=-5+12-16
=-9;
(5)2(2a2+9b)-(3a2+4b)
=4a2+18b-3a2-4b
=(4a2-3a2)+(18b-4b)
=a2+14b.
=-20+3+5-7
=-19;
(2)(
| 3 |
| 8 |
| 1 |
| 6 |
| 3 |
| 4 |
=9+4-18
=-5;
(3)(-3)2-(
| 3 |
| 2 |
| 2 |
| 9 |
| 2 |
| 3 |
=9-
| 27 |
| 8 |
| 2 |
| 9 |
| 3 |
| 2 |
=9-
| 3 |
| 4 |
| 3 |
| 4 |
(4)(-1)2013×|-5|-4×(-3)-42
=(-1)×5-(-12)-16
=-5+12-16
=-9;
(5)2(2a2+9b)-(3a2+4b)
=4a2+18b-3a2-4b
=(4a2-3a2)+(18b-4b)
=a2+14b.
点评:本题考查了有理数混合运算及整式的加减,进行有理数的混合运算时,注意各个运算律的运用,使运算过程得到简化.几个整式相加减,通常用括号把每一个整式括起来,再用加减号连接;然后去括号、合并同类项,整式的加减实质上就是合并同类项.
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