题目内容
计算:
(1)
(2cos45°-sin60°)+
;
(2)
sin45°+cos30°•tan60°-
(1)
2 |
| ||
4 |
(2)
2 |
(-3)2 |
(1)
(2cos45°-sin60°)+
,
=
(2×
-
)+
,
=2-
+
,
=2.
(2)
sin45°+cos30°•tan60°-
,
=
×
+
×
-3
=1+
-3,
=-
.
2 |
| ||
4 |
=
2 |
| ||
2 |
| ||
2 |
| ||
4 |
=2-
| ||
2 |
| ||
2 |
=2.
(2)
2 |
(-3)2 |
=
2 |
| ||
2 |
| ||
2 |
3 |
=1+
3 |
2 |
=-
1 |
2 |
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