题目内容
计算:
(1)2
×3
(2)
(3)
÷(
)×(4
)
(4)
÷
(a、b>0)
(1)2
3 |
12 |
(2)
a5+2a3b2+ab4 |
(3)
3
|
2 |
5 |
2
|
1
|
(4)
|
ab• |
|
(1)原式=(2×3)×
=6×6
=36;
(2)原式=
=
=(a2+b2)
;
(3)原式=(1×
×4)×
=10
=10×
=2
;
(4)原式=
=
=
.
3×12 |
=6×6
=36;
(2)原式=
a(a4+2a2b2+b4) |
=
a(a2+b2)2 |
=(a2+b2)
a |
(3)原式=(1×
5 |
2 |
|
=10
|
=10×
1 |
5 |
70 |
=2
70 |
(4)原式=
|
=
|
=
| ||
ab2 |
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