题目内容
计算:
(1)定义计算“?”:a?b=|a+b|-(a-b).若(x-2)?(1-x)=0,求x的值.
(2)求
x-2(x-
y2)-(
y2-
x)的值,其中x=-
,y=-3.
(1)定义计算“?”:a?b=|a+b|-(a-b).若(x-2)?(1-x)=0,求x的值.
(2)求
1 |
2 |
1 |
3 |
1 |
3 |
3 |
2 |
1 |
2 |
(1)根据题意得
|(x-2)+(1-x)|-(x-2)+(1-x)=0,
1-(x-2)+(1-x)=0,
解得x=2;
(2)
x-2(x-
y2)-(
y2-
x)
=
x-2x+
y2-
y2+
x
=
y2.
将y=-3代入得,原式=3.
|(x-2)+(1-x)|-(x-2)+(1-x)=0,
1-(x-2)+(1-x)=0,
解得x=2;
(2)
1 |
2 |
1 |
3 |
1 |
3 |
3 |
2 |
=
1 |
2 |
2 |
3 |
1 |
3 |
3 |
2 |
=
1 |
3 |
将y=-3代入得,原式=3.
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