题目内容
计算:
(1)
+
(2)(
)3÷
+
(3)
-x-1
(4)
+
-
.
(1)
2a |
a+1 |
2 |
a+1 |
(2)(
pq |
2r |
2p |
r2 |
1 |
2q |
(3)
x2 |
x-1 |
(4)
4 |
x2-4 |
2 |
x+2 |
1 |
x-2 |
分析:先因式分解或约分,然后化简.
解答:解:(1)原式=
=
=2;
(2)原式=
•
+
=
+
(3)原式=
-
=
;
(4)原式=
+
-
=
=
.
2a+2 |
a+1 |
2(a+1) |
a+1 |
=2;
(2)原式=
p3q3 |
8r3 |
r2 |
2p |
r2 |
2q |
=
p2q3 |
16r |
r2 |
2q |
(3)原式=
x2 |
x-1 |
x2-1 |
x-1 |
=
1 |
x-1 |
(4)原式=
4 |
(x-2)(x+2) |
2x-4 |
(x-2)(x+2) |
x+2 |
(x-2)(x+2) |
=
x-2 |
(x-2)(x+2) |
=
1 |
x+2 |
点评:本题主要考查分式的混合运算,把分式化到最简是解答的关键.
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