题目内容
化简求值:
(1)2x+3x+5(x2-
x),其中x=2.
(2)已知4a+1=0,求a2-(2a+1)+(a-3a2)的值.
(1)2x+3x+5(x2-
3 | 5 |
(2)已知4a+1=0,求a2-(2a+1)+(a-3a2)的值.
分析:(1)去括号合并同类项,代入求值;
(2)先有4a+1=0,求出a,再化简a2-(2a+1)+(a-3a2),代入求值.
(2)先有4a+1=0,求出a,再化简a2-(2a+1)+(a-3a2),代入求值.
解答:解:(1)2x+3x+5(x2-
x)
=5x+5x2-3x
=2x+5x2,
当x=2时,
原式=2×2+5×22
=24;
(2)由4a+1=0,得a=-
,
a2-(2a+1)+(a-3a2)
=a2-2a-1+a-3a2
=-2a2-a-1,
当a=-
时,
原式=-2×(-
)2-(-
)-1
=-
.
3 |
5 |
=5x+5x2-3x
=2x+5x2,
当x=2时,
原式=2×2+5×22
=24;
(2)由4a+1=0,得a=-
1 |
4 |
a2-(2a+1)+(a-3a2)
=a2-2a-1+a-3a2
=-2a2-a-1,
当a=-
1 |
4 |
原式=-2×(-
1 |
4 |
1 |
4 |
=-
7 |
8 |
点评:本题考查了整式的加减-化简求值,正确化简代数式是解题的关键.
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