题目内容
图10是小红设计的钻石形商标,△ABC是边长为2的等边三角形,四边形ACDE是等腰梯形,AC∥ED,∠EAC=60°,AE=1.(1)证明:△ABE≌△CBD;
(2)图中存在多对相似三角形,请你找出一对进行证明,并求出其相似比(不添加辅助线,不找全等的相似三角形);
(3)小红发现AM=MN=NC,请证明此结论;
(4)求线段BD的长.
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⑴证明:
,
,
. ……………………1分
,
,
,
. ……………………2分
在
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. …………3分
⑵答案不唯一.如
.
证明:
,
,
. ………………………………………5分
其相似比为:
. ……………………………………………6分
⑶由(2)得
,
. ………………8分
同理
.
. ………………………………………9分
⑷作
,
,
. ……………………………………1O分
,
,
,
. ………………………………11分
,
,
. …………………………12分解析:
略
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在
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⑵答案不唯一.如
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证明:
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其相似比为:
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⑶由(2)得
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同理
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⑷作
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略
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