题目内容
计算| x2-2x+1 |
| x2-1 |
| x2-x |
| x+1 |
| 1 |
| x |
分析：此题运算顺序：先除后减，注意把除法转化为乘法来做．
解答：解：原式=
•
-
=
-
=0．
故答案为0．
| (x-1)2 |
| (x+1)(x-1) |
| x+1 |
| x(x-1) |
| 1 |
| x |
=
| 1 |
| x |
| 1 |
| x |
=0．
故答案为0．
点评：此题应注意运算顺序，分解因式、约分是关键．
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题目内容
计算| x2-2x+1 |
| x2-1 |
| x2-x |
| x+1 |
| 1 |
| x |
| (x-1)2 |
| (x+1)(x-1) |
| x+1 |
| x(x-1) |
| 1 |
| x |
| 1 |
| x |
| 1 |
| x |